Many years ago I lost money by buying a German system.
I read that the inventor of the system on the thirds (dozens) after decades was able to reveal this truth:
Within two spins you´ll hit the dozen that you chose.
Within seconds we are able to confirm this truth with a little help from a calculator.
Ignoring zero I realize this: 1-(2/3)^2 = 0.555555555.
We might be able to use this knowledge in smaller parts of the game
An example: There are THREE "thirds" (single numbers) in any street.
If we bet the EARLIEST number in each street appearing, and stop as soon as TWO streets have appeared more than once,
we should leave with at least one hit in 55.55 % or all sessions.
Allrighty.........
I'll be the first to admit I don't understand this.
With my limited knowledge of math, I can't understand the equation. I do know for a fact you will not hit a dozen in two tries with any consistency. Hey, we all know that.
Could someone comment on the idea you will hit your chosen dozen in two spins? Would someone care to explain the equation? In English, please. This is the way I read it. Am I right? "Divide two by three and get 66.66. Multiply 66.66 by 66.66% and subtract the 44.43 from one."
Something like that?
TwoCat
You have it about right Sam. The house wins 2/3 of the time when we bet on a dozen. For it to win twice, the odds are 2/3*2/3, or 4/9 (0.44444). Our odds of winning are the remainder (0.5555555). For the real picky, it is 25/37*25/37 or 625/1369 or 45.654% for the house, 54.347% in our favor counting the zero.
Thank you, Colbster!
This will give me something to study on.
And, of course, thanks to Dane for his always-intriguing ideas.
Sam
Dane, please elaborate on what you mean
Quote from: RouletteGhost on Dec 03, 09:47 PM 2014
Dane, please elaborate on what you mean
I think that Colbster has explained the basic procedure.
For the real picky he included zero.
I preferred to ignore zero. You see, each street can be perceived as three thirds, three single numbers
Right after two streets each hitting more than once,
we should be able to count on the probability 0.555555555555555.
Right in our JAWS! :)
Just so i understand. What you are saying is that statistics shows if a street has a repeat (back to back) start betting on it To hit again because theres a 55% chance
The basic idea.is to start betting the numbers in a street that repeats?
RG
In this example...the formula is this
When a number comes..we bet it and we are on that street. Continue until 2 streets have hit more than 3 times. Only betting 1 in each street. Other hits in the same streets are wins or counts to 3.
You are slightly better than evens playing this formula.
Perhaps I misunderstood
So we have better chances of winning on single dozens for the second spin after a virtual loss on the first?
I thought the odds stayed the same for every trial...
The odds stay the same for every spin.
But if you calculate
what happens within more spins, you´ll have other probabilities.
Colbster explained the calculating procedure very well.
The way I could have used the 0.555555555555555
1st of December at table 3 in Spielbank Wiesbaden:
34...I start betting 34
6.... - - - 6
29...- - - 29
1....- - - 1
2... NOW I LEAVE 1.
27...I start betting 27
0
34..HIT. In area 1-36 two streets have hit more than once.
Thanks. I don't understand the streets part. Need coffee. How would you do with DS and splits?
OK, I'll try a summation. (I have to put things in my own words before I understand them.)
We bet each number that comes UNLESS AND UNTIL a second number in that street comes (When the 2 came, he abandoned the 1.) That street is then dead. We continue betting single numbers until, a) we win or b) two streets have two numbers hit. Then we start over.
Can't wait to sneak off to Riverwind and walk this puppy 'round the block.
Sam
Dane...its a great example of building a formula based on maths.
Quote from: psimoes on Dec 04, 10:44 AM 2014
Thanks. I don't understand the streets part. Need coffee. How would you do with DS and splits?
Yes, take a coffee break! Read back my posts!
And look at this:
We have just worked on single numbers.
It´s time for splits or cheveaux.
34...In DS 31-36 I start betting split (cheval) 31-34.
6.... In DS 1-6 - - - - 3-6
29...In DS 25-30 - - - - 26-29
1....As you might have guessed, I divided DS 1-6 into THREE splits: 1-4, 2-5 and 3-6.
This double street or six line has appeared more than once. So I leave it and stop betting the earliest chosen split there!
2
27...Two of the six well known DS have each appeared more than once. So this session ends here.
Now let´s try the procedure on DS.
We divide 1-18 into THREE THIRDS: 1-6, 7-12 and 13-18.
- - 19-36 - - - : 19-24, 25-30 and 31-36.
34...Start betting DS 31-36.
6..... - - DS 1-6.
29....Area 19-36 has appeared more than once. We leave it and its earliest DS.
1..... - 1-18 - - - - - . - - - - - - DS.
This time we won.
Time for a cup of coffee :)
Quote from: TwoCatSam on Dec 04, 11:19 AM 2014
OK, I'll try a summation. (I have to put things in my own words before I understand them.)
We bet each number that comes UNLESS AND UNTIL a second number in that street comes (When the 2 came, he abandoned the 1.) That street is then dead. We continue betting single numbers until, a) we win or b) two streets have two numbers hit. Then we start over.
Can't wait to sneak off to Riverwind and walk this puppy 'round the block.
Sam
Thanks, Sam. Are you going to a B&M? Would you mind posting the table limits in the thread, please? And happy winnings!
Quote from: Dane on Dec 04, 11:27 AM 2014
Yes, take a coffee break! Read back my posts!
And look at this:
We have just worked on single numbers.
It´s time for splits or cheveaux.
34...In DS 31-36 I start betting split (cheval) 31-34.
6.... In DS 1-6 - - - - 3-6
29...In DS 25-30 - - - - 26-29
1....As you might have guessed, I divided DS 1-6 into THREE splits: 1-4, 2-5 and 3-6.
This double street or six line has appeared more than once. So I leave it and stop betting the earliest chosen split there!
2
27...Two of the six well known DS have each appeared more than once. So this session ends here.
Now let´s try the procedure on DS.
We divide 1-18 into THREE THIRDS: 1-6, 7-12 and 13-18.
- - 19-36 - - - : 19-24, 25-30 and 31-36.
34...Start betting DS 31-36.
6..... - - DS 1-6.
29....Area 19-36 has appeared more than once. We leave it and its earliest DS.
1..... - 1-18 - - - - - . - - - - - - DS.
This time we won.
Time for a cup of coffee :)
Cheers! Posting can be consuming.
Iḿ trying to get the reasoning right: Weŕe dealing with multiples or dividers of three, depending on the aspect of the game? With streets, because there are 12, we start over every four outcomes unless we win early? A yes or no answer is enough as Iḿ going for the second cup...
psimoes
My wife and I go to Riverwind Casino in Norman, Oklahoma, to play the Roulette Evolution RNG "wheel". It spins every 30 seconds, ready or not!
The minimum is .25 or a quarter, American. I do not know the upper limits as it would be very difficult to place a large bet. The layout takes .25, 1.00 and 2.00. If you bet $20.00, you'd have to hit the $200 chip ten times. And it always tries to put a chip on a split or corner--never where you want it. Very aggravating, but a fair RNG.
I am not going to speak for Dane, but I think you have it a tad on the wrong side. Read his first post very carefully. He does not give "clues". ::)
P.S. I think you're wrong on this part: we start over every four outcomes unless we win early? I now feel an overwhelming urge to shut up!! ;D
Samster
I understand the part about diving streets or DS by 3, Iḿ failing big time to see the reasoning behind all the "when two streets hit more than once" thing. My fault, it seems arbitrary. Need a rest after typing all that crap last night.
My wife was always against my gambling habits. She wouldn't hear anything about it, but then when I lost all the money that I had "stolen" from the casino she got really angry, despite the bank account had returned to where it was before I started. Female logic anyone?
Sam, careful with RNG. After you win some it switches to PMG mode. Premeditated Number Generating.
What I used to beat it was playing for very little time on one machine, cash the winnings and choose another machine.
You never know what info is in that barcode, so when you leave one machine, change the card for real money and start over.
I have roulette at my local casino with a real wheel and ball in a glass bubble and bets are placed on a screen
That is not rng
Cant wait to hear the results for this
I will try my next trip
I got the rules now (sorry)! How's everyone doing with this system? If it works, 5% is an incredible edge regardless I agree with it or not!
Looks like you bet the numbers as they come and if another number in the same street appears stop betting that number
[delete]
No, you stop betting the entire street! Consider every street as a little game of dozens, since every street has three numbers. Everytime a street hits, it means the house had won the first bet. Probability tells us for the house to win a second time in that little game it loses an edge of near 5%. So we start betting on any number in that street hoping the next time that same street hits we win the game, since the edge is on our side.
I got that part. But dane said he bet the same number not another number in the street. No?
One interesting thing: everytime we bet on a single dozen the casino bets a double dozen against us. OTOH if we bet on a double dozen the casino bets the single dozen against us (interestingly they always flat-bet). We have 2/3 chance of winning the first battle, but we'll lose more than 4% edge to the house, on the second.
Quote from: RouletteGhost on Dec 04, 09:33 PM 2014
I got that part. But dane said he bet the same number not another number in the street. No?
Yes, he said that.
Confusing strategy lol. So many ways it can be interpreted. Dane elaborate please lol
Quote from: RouletteGhost on Dec 04, 09:42 PM 2014
Confusing strategy lol. So many ways it can be interpreted. Dane elaborate please lol
Yes, I have you all between my CLAWS, haven´t I? >:D
Confusing? Not to me!
It is the early worm that catches the bird :girl_to: or something like that.
The session is usually short because I bet the EARLIEST number in any street only (if I have chosen to bet on single numbers).
Within the street I beg for a repeat of the earliest number. And I leave that region of three (that street) as soon as it comes again.
The reason for ending the session when TWO streets have reappeared should be obvious if you look at this once more:
1-(2/3)^2 = 0.5555555555555555.
I have taken the liberty to split the two outcomes into TWO streets (if I have chosen to bet on single numbers).
And I have tried to show you how to bet cheval and DS. Please read back my posts, if you are still insecure.
In my examples so far I have not bet street - only treated street as a region with THREE numbers.
If I wanted to bet street, I accordingly would divide area 1-36 into four like this:
1-3, 4-6, 7-9/ 10-12, 13-15, 16-18/ 19-21, 22-24, 25-27/ 28-30, 31-33, 34-36.
There are exactly THREE streets in each area. Surprised? Then you haven´t really got a clue!
Thanks for the overwhelming interest and good luck to Sam and others who might already have rushed in
to the Casino :)
DANE
Quote from: Dane on Dec 05, 03:16 AM 2014
The reason for ending the session when TWO streets have reappeared should be obvious if you look at this once more:
1-(2/3)^2 = 0.5555555555555555.
I have taken the liberty to split the two outcomes into TWO streets (if I have chosen to bet on single numbers).
It's not obvious yet. 2/3 is the same as 8/12, not 2/12, or even 4/12 counting on two streets repeating. If you take that liberty you won't gain any edge. If you win it's due to luck only. Is it just me?
Quote from: psimoes on Dec 05, 04:28 AM 2014
It's not obvious yet. 2/3 is the same as 8/12, not 2/12, or even 4/12 counting on two streets repeating. If you take that liberty you won't gain any edge. If you win it's due to luck only. Is it just me?
When some street repeats, the probability of hitting the chosen number there is exactly 1/3.
When another street repeats, the probability of hitting the chosen number there is exactly 1/3.
1-(2/3)^2 = 0.555555555555555555555555555555555555555555555555555555555555555555555555555555555555
Hi Dane,
Thanks for sharing, and I understand the odds, just the one question when betting the numbers on the street, why do you end the session when the second street repeats with no win?
Regards
Jim
Quote from: Dane on Dec 05, 04:51 AM 2014
When some street repeats, the probability of hitting the chosen number there is exactly 1/3.
When another street repeats, the probability of hitting the chosen number there is exactly 1/3.
1-(2/3)^2 = 0.555555555555555555555555555555555555555555555555555555555555555555555555555555555555
Yes, but there are 12 streets on the carpet, and each one has the same probability of hitting as any other, 1/12. You can go bust before your winning street hits, not mentioning you're only betting one number within that street. But, if you still apply that formula to streets you might have a better chance, that's what I thought the purpose of your choice on streets was: 1-(8/12)^2. You'd have to think in terms of every 4 streets or 8 per 2 spins... in other words, use the formula to win on a group of streets and at the same time to win on a straight within each street... Same results as when betting dozens, but much better resolution if you can say that, although much more expensive. I really thought we could use this formula to arrange our bet selection in some form of fractal mechanics. Sorry I can't explain myself better.
Quote from: JimmieB on Dec 05, 05:00 AM 2014
Hi Dane,
Thanks for sharing, and I understand the odds, just the one question when betting the numbers on the street, why do you end the session when the second street repeats with no win?
Regards
Jim
Of course this is not a course on basic probabilities.
But I hope that some of you might getting used to think within probabilities. 1-(2/3)^2 =
0.555555555555 fascinated me. If I were to continue the procedure,
I had to grab my calculator again and look at
1-(2/3)^3
1-(2/3)^4
1-(2/3)^5
and so forth and so on
Thanks for further explaining. So let me show an example
1 bet--------1
25 bet-------25
3----------remove chip from number 1
12-------place chip on 12
Also, why not place a chip on another number in the street. If 1 shows bet 2 if if 17 shows bet 16 etc or does the idea only work betting the same number?
Quote from: RouletteGhost on Dec 05, 06:37 AM 2014
Thanks for further explaining. So let me show an example
1 bet--------1
25 bet-------25
3----------remove chip from number 1
12-------place chip on 12
Also, why not place a chip on another number in the street. If 1 shows bet 2 if if 17 shows bet 16 etc or does the idea only work betting the same number?
You seem to master the procedure.
Choosing 2 INSTEAD of 1
- 16 INSTEAD of 17 does not change the chances!
We are not supersticious, I hope.
We could place a chip on the entire street as the numbers come then remove the chip on 2nd hit as well? This way all numbers in street are covered
Quote from: RouletteGhost on Dec 05, 08:35 AM 2014
We could place a chip on the entire street as the numbers come then remove the chip on 2nd hit as well? This way all numbers in street are covered
You could but how would you know that particular street is going to be the one that hits over any other? Furthermore you no longer have the advantage of 55% in your favor. I'm not sure what's so hard to understand here. Dane has given perfect examples and I truly thank him for opening up our eyes to a higher probability. This is all flatbetting guys so it should take quite awhile to "lose" your BR. You are certainly not going to win every game. There will still be variance, highs and lows, etc. But....and a big but is that you actually do have an edge over the casino in playing this way. Casino's lose to players too in the short term but if you played this way in the long term you will indeed be a winner. Look at Dane's perfect example before and understand it. I'm not sure what more you want him to tell you. It is really not that difficult lol.
DRIFTING SLIGHTLY OFF TOPIC..............
(Any deleting fingers, feel free........)
OK, assume the math is correct. In two spins, you have a 55.55% chance (baring zero) of hitting your dozen. In a fair game, you would have a 5.5% edge over the house. Mathematically, we know this is true but empirical evidence tells us it is not. Otherwise, I could create a mechanical, stay-at-home robot to punch the keys and make me wealthy on 5.5%. I know I can't. The question is why?? Why can't I??
I am going to go out on a limb here and say it's because of trends. The wheel simply trends in the wrong direction, just as it does when you are betting red and black eats your lunch.
I see all this as either a conundrum or a paradox. Perhaps a paradox wrapped in a conundrum! I am pretty much burnt out on most roulette ideas/systems, but this one has me by the ying-yang!
I shall not rush to the casino, but shall creep every so cautiously next week and wager my quarters.
TwoCat
Im a little slow
If a street hits and you bet any number in that street until it hits again and do the continuously as numbers come how does that create the 55%
I understand the part where when a number hits you choose any number in that street and place a chip
Quote from: RouletteGhost on Dec 05, 12:39 PM 2014
Im a little slow
If a street hits and you bet any number in that street until it hits again and do the continuously as numbers come how does that create the 55%
I understand the part where when a number hits you choose any number in that street and place a chip
I'm not sure you do as Dane already said your betting the EARLIEST NUMBER that came up in the street so I'm not sure what number your betting on??? Your really making this far more confusing for yourself than it needs to be. Please read Dane's very first post for this topic and his first example with his spins to understand the percentages and how to play this. If you can't understand it from there I think it may be best to try something else.
As dane previously stated, i understand it. It is you making it confusing.
I just wanted to mention the possibility of betting the entire street
Quote from: RouletteGhost on Dec 05, 12:39 PM 2014
I understand the part where when a number hits you choose any number in that street and place a chip
I'm just going off what you just said. You do NOT choose any number in the street, you are playing the Earliest or FIRST number in the street. Otherwise you would not have any advantage. I'm sorry, I'm just going off what your saying and I feek like you really don't understand this at all.
Ok
Quote from: Dane on Dec 03, 03:53 AM 2014
Within two spins you´ll hit the dozen that you chose.
Dane, Can you explain this
I'm assuming you could also play this with the wheel sections as well i.e. 32, 15, 19 is section 1, and so on?
Regards
Jim
You know, the probabilities are there. Any betting selection really is down to personal preference.
Quote from: Turner on Dec 05, 02:29 PM 2014
Dane, Can you explain this
Sorry. What I meant to write in my initial post was of course
that within two spins you´ll PROBABLY hit the chosen dozen.
And if we ignore zero the probability is 0.55555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555 :)
Quote from: Dane on Dec 06, 02:18 AM 2014
Sorry. What I meant to write in my initial post was of course
that within two spins you´ll PROBABLY hit the chosen dozen.
And if we ignore zero the probability is 0.55555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555 :)
Yesterday "plolp" quoted this. NOT HERE on rouletteforum.cc
but on betselection.cc. His posts there can be seen together with these French words:
"Rien de plus normal, tout est étrange". Meaning nothing is normal, everything is strange.
I must admit that I found it rather STRANGE to see the quotation and his comment there.
And I felt I had to tell other bewildered readers there, that the initial post and much more can be seen HERE.
The message from plolp (in essence): "YOU HIRE 2 BETS TO WIN ONE".
Thanks for the enlightening words! They might not be completely true, however.
If you WIN WITHIN TWO SPINS, you may win IN THE FIRST SPIN.
In half of all your winning sessions you need only to hire one bet. Then you´ll win 2 units.
Not exactly rocket science. Of course it gets more complicated if you work inside SEVERAL
cheveaux (splits), streets or double streets as described earlier in this topic.
For any person interested in statistics it might be rewarding to study the number of views.
The usual suspects :) of course read most topics.
The interest in this topic really is overwhelming: Until now there have been approx. 941 views.
Quote from: Dane on Dec 07, 03:02 AM 2014
[...]
The message from plolp (in essence): "YOU HIRE 2 BETS TO WIN ONE".
Thanks for the enlightening words! They might not be completely true, however.
[...]
If you WIN WITHIN TWO SPINS, you may win IN THE FIRST SPIN.
In half of all your winning sessions you need only to hire one bet. Then you´ll win 2 units.
[...]
Dane, isn't all this just basic money management? Could you post a link to that thread?
Quote from: Dane on Dec 06, 02:18 AM 2014
Sorry. What I meant to write in my initial post was of course
that within two spins you´ll PROBABLY hit the chosen dozen.
And if we ignore zero the probability is 0.55555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555 :)
Thats better :thumbsup:
PROBABLY in capitals is the disclaimer in the T's & C's
To psimoes:
link:://betselection.cc/general-discussion/dane (link:://betselection.cc/general-discussion/dane)´s-jaw-of-the-thirds/mgs3456/
OK thanks.
Hi!
I play Danes Ds system like this.
Nr 4 hits Ds 1, put a unit on Ds 1
Nr 19 hits Ds 4, put a unit on Ds 1 and 4
Nr 21 hits ,win on Ds 4 ,remove the unit from Ds 4 ,1 unit on Ds 1
Nr 7 hits loss. Session over There has been 2 hits on Ds 1-3 and 2 hits on Ds 4-6.
My last 102 spins playing like this gained 38 units.
Agesta
Hi Agesta,
Is this flat betting?
Regards
Jim
Quote from: JimmieB on Dec 08, 05:29 AM 2014
Hi Agesta,
Is this flat betting?
Regards
Jim
Hi Jim!
Just flat betting!
I have played 3 more session of around 100 spins,
they ended up
1. +-0
2.+3
3.-19
= +22 units in 400 spins
agesta
Thanks :thumbsup:
Could you add a negative progression to make it more profitable?
Hi Agesta
Thanks for posting the way u play it.
Is it possible to post a sample of about 20 spins
showing how u play it to enable everyone who is following
the thread to have a good understading and to test it
properly. Thanks
Cheers
Chris
Hi!
This is how i play it!
nr2 1 unit on DS 1
nr8 No more play for this session on DS 1,2,3 There is 2 hits on them.
nr 14 no play
nr 4 no play
nr 16 no play
nr 22 play 1 unit on DS 4
nr 9 play 1 unit on DS 4
nr 19 win end of session +3 unit
new session
nr.25 1 unit on DS 5
nr.13 1unit on DS 3 and 5
nr.35 No more play on DS 3.4.5 this session, 1unit on DS3
nr. 31 play 1 unit on DS 3
nr. 30 Play 1 unit on DS 3
nr.4 2 hits on DS 1,2,3 ends session
new session
nr.19 1 unit on Ds 4
nr. 13 1 unit on Ds 3 and 4
nr.23 Win on DS 4, 1 unit on DS 3
nr. 33 1 unit on DS 3
nr.7 2 hits on Ds 1,2,3 end of session.
Total -2 units flat betting
Agesta
Quote from: RouletteGhost on Dec 08, 06:40 AM 2014
Could you add a negative progression to make it more profitable?
As you might have noticed, I am
NO NEGATIVE PROGRESSION ADDICT.
So I am certainly not going to do such a thing.
We should not follow any Ghost
or any Troll for that matter >:D
We might as well ask:
Could you add a POSITIVE progression to make it more profitable?
If you are up or even flat betting then a negative progression poses no significant risk?
Quote from: Dane on Dec 08, 08:26 AM 2014
As you might have noticed, I am
NO NEGATIVE PROGRESSION ADDICT.
So I am certainly not going to do such a thing.
We should not follow any Ghost
or any Troll for that matter >:D
We might as well ask:
Could you add a POSITIVE progression to make it more profitable?
what do you think of using +1/-1 in cycles? got a sweet +45 units in 200 spins on a test run just now
I fully understand a successful system requires no progression. However, that being said if this is a solid system that yields profit or breaks even then a +1 -1 progression should yield more profit
Hello Mr. soggett
On the progression....do you mean up one after a loss of a game or single spin? Loss of a game is when two streets have each had two hits and you weren't a winner.
Sam
i like the idea of playing this with double streets the best
why?
the chances of 6 unique double streets hitting in a row is very very low and very very rare
using a negative progression until a repeat you are just about guaranteed to profit
if 1 hits place chip on 1st double street then if 22 hits chip on double street 1 and double street 4 etc etc
add another chip each time
@Agesta - Thanks for the example.
Cheers
Chris
More than 1300 views now :)
In the examples of reply #59
DS was chosen.
In my examples of reply #9 and reply #13 (page 1)
I also showed you something else.
When choosing a chance we also should consider this:
AFTER LEAVING ONE GROUP WITH THREE PARTS WITHOUT A HIT
THAT PARTICULAR GROUP MAY COME AND COME AGAIN
BEFORE THE END OF THE SESSION.
After leaving area 1-18 (and DS there) these EIGHTEEN numbers may come more times
before 19-36 has appeared twice.
Street 1, 2, 3/ 4, 5, 6/ 7, 8, 9/ 10, 11 12.
Accordingly we might have left area 1-9 without a hit after two appearances there.
Before any of the other three GROUPS has appeared twice,
the left area with NINE NUMBERS can come Again and Again.
Split (cheval):
1-4, 2-5, 3-6/ 7-10, 8-11, 9-12/ 13-16, 14-17, 15-18/ 19-22, 20-23, 21-24/ 25-28, 26-29, 27-30/ 31-34, 32-35, 33-36.
We might have left DS 6 (and its three mentioned splits or cheveaux) without a hit there.
Before ending the session the abandoned area with SIX NUMBERS may come again and Again to our disadvantage!
Plein, Straight Up or single numbers:
Without a hit on No. 3 right after 3, 1 we are leaving area 1-3.
Even these THREE NUMBERS can come Again and Again before any other street has showed twice.
There is nothing like stating the obvious.
This ought to be obvious now! :thumbsup:
Quote from: TwoCatSam on Dec 08, 12:55 PM 2014
Hello Mr. soggett
On the progression....do you mean up one after a loss of a game or single spin? Loss of a game is when two streets have each had two hits and you weren't a winner.
Sam
Hello TCS
i ment after a loss of a game :thumbsup:
There has to be a progression that works with double streets
If you place a chip on a double street as it shows you will have a repeat before 6 unique doublestreets occur. It is a rare event for 6 unique to occur in a row
Soggett are you playing numbers in streets as they show or are you playing double streets?
Quote from: RouletteGhost on Dec 09, 06:26 AM 2014
There has to be a progression that works with double streets
If you place a chip on a double street as it shows you will have a repeat before 6 unique doublestreets occur. It is a rare event for 6 unique to occur in a row
There have to be other threads for this old ideas!
I repeat:
We should not follow any Ghost
or any Troll for that matter >:D
No repeat?
This is off-topic. But let´s just have a look at 5/6x4/6x3/6x2/6x1/6 = 0.054320987654.
Really amazing to see those digits in that order, I must say.
Im referring to agesta's double street version of your idea Dane. His idea would work well with a slight progression of plus 1 minus 1
I would only flatbet your method, no progression
Quote from: RouletteGhost on Dec 09, 07:36 AM 2014
Im referring to agesta's double street version of your idea Dane. His idea would work well with a slight progression of plus 1 minus 1
I would only flatbet your method, no progression
If that´s the case, RouletteGhost,
we should stay focused! Please explain
how exactly agesta´s version differs from my method. Please take your time!
In the meantime I´ll be thinking about
a famous mathematician throwing a die four times in the French Age of Enlightenment
Such a probability reminds me of something with DS :)
Quote from: RouletteGhost on Dec 09, 06:30 AM 2014
Soggett are you playing numbers in streets as they show or are you playing double streets?
agestas way, playing the double streets
Thanks soggett. I love this idea. Could be quite profitable since it is very rare for 6 unique doublestreets to occur in a row
I repeat (from reply #71): " 5/6x4/6x3/6x2/6x1/6 = 0.054320987654".
I don´t know if you realised THAT THESE AMAZING NUMBERS INDICATE EXACTLY HOW RARE IT IS (ignoring Zero).
Rare events do occur if you continue long enough. And with a negative progression they shall hit you harder.
But many gamblers simply won´t take NO :ooh:(to negative progressions) for an answer in various threads.
In the mid-seventeenth Century, a simple question directed to Blaise Pascal by a nobleman sparked the birth of probability theory, as we know it today. Chevalier de Méré
gambled frequently to increase his wealth. He bet that at least one 6 would appear during a total of four rolls.
We have progressed since then, havent´t we?
The prodecure on single numbers can be seen in reply #3.
In fun mode :) I have just tried something POSITIVE on single numbers.
I did not change chip value in any session. The changes took place from session to session.
And with the probability of 0.55555555555555555555555555555 on my side I did not take too long to roll high!
I started with 1 unit. Increasing from 1 unit to 2 units is a giant step.
So I decided to take this step only after winning two sessions in a row.
By winning I mean hitting a number regardless of how much Money might be left.
Right after any session with 2 units per chosen number:
Down to square one if I didn´t win.
If I did get a hit with 2 units, the following session must be with 3 units.
And so forth and so on.
The goal of my free test series: A hit with 8 units.
When a session ended, I decided to use the final spin again like this:
The last number was registered as the earliest number of the following session.
AFTER JUST 17 SESSIONS (97 spins) I had reached my goal!
Result: 575 units! :)
I have been following this thread with interest but I have been quiet so far.
After reading through it several times I do understand how it works.
And now reading the last post of Dane has increased my interest even more.
I think I'll give this a try in Fun Mode at Dublinbet after work.
Quote from: SamNL on Dec 10, 08:12 AM 2014
I have been following this thread with interest but I have been quiet so far.
After reading through it several times I do understand how it works.
And now reading the last post of Dane has increased my interest even more.
I think I'll give this a try in Fun Mode at Dublinbet after work.
My 2ND test series on single numbers
with a positive progression took too much time.
I stopped after approx. 350 spins without reaching my goal.
Quote from: agesta on Dec 08, 08:04 AM 2014
Hi!
This is how i play it!
nr2 1 unit on DS 1
nr8 No more play for this session on DS 1,2,3 There is 2 hits on them.
nr 14 no play
nr 4 no play
nr 16 no play
nr 22 play 1 unit on DS 4
nr 9 play 1 unit on DS 4
nr 19 win end of session +3 unit
new session
nr.25 1 unit on DS 5
nr.13 1unit on DS 3 and 5
nr.35 No more play on DS 3.4.5 this session, 1unit on DS3
nr. 31 play 1 unit on DS 3
nr. 30 Play 1 unit on DS 3
nr.4 2 hits on DS 1,2,3 ends session
new session
nr.19 1 unit on Ds 4
nr. 13 1 unit on Ds 3 and 4
nr.23 Win on DS 4, 1 unit on DS 3
nr. 33 1 unit on DS 3
nr.7 2 hits on Ds 1,2,3 end of session.
Total -2 units flat betting
Agesta
Hi!
This is the way i play this and it still works pretty good but i have tested it with a small progression
1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,10 stop on both sides indipendent.
If i reach a new high i reset both progressions.
If i lose one side say low side i only try 3 times for the high side to hit but i stop direct if i hit a wrong ds.
Last test i was + 13 units in 137 spins and i reach 4 one time on the low side and the third 2 one time on the high side.
This is safe so far but you never now.
agesta