Say that one is predicting winning numbers using visual ballistics or another method during the spin and there is a good dominant diamond.
If one predicts randomly, maths suggest the mean error would be +\- 9.25 pockets (on a European) wheel.
Is there a way to correlate mean prediction error with % advantage on the wheel in order to establish how well the prediction system has adapted to prevailing conditions.
For example
9.25 pockets mean = -2.7%
9 pockets mean= ??%
8 pockets mean= ??%
7 pockets mean= ??%
Etc etc
Is this a good way of indicating worthwhile conditions? Or is there a better way?
Sorry if this has been answered elsewhere. I took a look and couldn't see it.
Quote from: Firefox on Jan 14, 10:49 AM 2019
Say that one is predicting winning numbers using visual ballistics or another method during the spin and there is a good dominant diamond.
If one predicts randomly, maths suggest the mean error would be +\- 9.25 pockets (on a European) wheel.
Is there a way to correlate mean prediction error with % advantage on the wheel in order to establish how well the prediction system has adapted to prevailing conditions.
For example
9.25 pockets mean = -2.7%
9 pockets mean= ??%
8 pockets mean= ??%
7 pockets mean= ??%
Etc etc
Is this a good way of indicating worthwhile conditions? Or is there a better way?
Sorry if this has been answered elsewhere. I took a look and couldn't see it.
Are you looking for a mathematical formula?
9,25 comes from the average of the half, so 37/4, right? You get to -2.7% by finding the percentage of payouts/odds*100. Since your payout is 36, and your odds are 37/4 (9.25), it goes: (36/4-9.5)/9.25*100=2.7%
This is what you mean?
Brilliant. Thanks for the information.
See what forum is all about.
Quote from: nottophammer on Jan 14, 01:49 PM 2019
See what forum is all about.
Ben and Shaun = Excel black belts. O0
Quote from: Mako on Jan 14, 02:57 PM 2019
Ben and Shaun = Excel black belts. O0
Who is Shaun?