Hello,
Can any math minds confirm my findings for 99% on double zero roulette?
This is to bet 11 straight up numbers for 15 spins.
The probability is 1 - (numbers not up)^spins. or 1 - (27/38)^15 = 99.406%
A 15 spin progression on 11 numbers costs $3,839
Using a progression of
Bet 1 for 3 spins.
Bet 2 for 1 spins.
Bet 3 for 1 spins.
Bet 4 for 1 spins.
Bet 6 for 1 spins.
Bet 8 for 1 spins.
Bet 12 for 1 spins.
Bet 17 for 1 spins.
Bet 25 for 1 spins.
Bet 36 for 1 spins.
Bet 52 for 1 spins.
Bet 74 for 1 spins.
Bet 107 for 1 spins.
In the attached spreadsheet, you can change the number of spins to see the chance of winning.
I would use the information on the excel with a progression calculator link:://loothog.com/Systems/prog.html
Any idea of the optimal combination of
1. Number of spins
2. Win Percentage
3. Bankroll
Quote from: FreeRoulette on May 25, 11:02 PM 2020
Hello,
Can any math minds confirm my findings for 99% on double zero roulette?
This is to bet 11 straight up numbers for 15 spins.
The probability is 1 - (numbers not up)^spins. or 1 - (27/38)^15 = 99.406%
A 15 spin progression on 11 numbers costs $3,839
Using a progression of
Bet 1 for 3 spins.
Bet 2 for 1 spins.
Bet 3 for 1 spins.
Bet 4 for 1 spins.
Bet 6 for 1 spins.
Bet 8 for 1 spins.
Bet 12 for 1 spins.
Bet 17 for 1 spins.
Bet 25 for 1 spins.
Bet 36 for 1 spins.
Bet 52 for 1 spins.
Bet 74 for 1 spins.
Bet 107 for 1 spins.
In the attached spreadsheet, you can change the number of spins to see the chance of winning.
I would use the information on the excel with a progression calculator link:://loothog.com/Systems/prog.html
Any idea of the optimal combination of
1. Number of spins
2. Win Percentage
3. Bankroll
IMO, I don't think there is an optimal anything on that! You're right, in order for any hit to provide a profit, for 15 spins you need 3839units (in case you don't get a hit up until then). But... I don't think it's a really friendly way to play!