Friends,
This already stale since first casino open shop, and researched to death, but nevertheless...
this technique,
already stale...since roulette invented, but, nevertheless...
on the table, carpet,
we see that...
123
456
789,
10,11,12,
13,14,15,
16,17,18,
19,20,21,
22,23,24,
25,26,27,
28,29,30,
31,32,33,
34,35,36,
thus many people, pair up the numbers, as a pair bet on the table
1-2,
3-6
4-5
7-8,
9-12
10,-11,
13,-14,
15,-18
16,-17,
19,-20,
21,-24
22,-23,
25,-26,
27,-30
28,-29,
31,-32,
33,-36
34,-35,
or...
1-4,
2-3
5-6
7-10
8-9
11,-12 and so on.
Thus, instead of 36chips,
they bet 18, albeit zero...
25,-26,x
27,-30x
28,-29,
31,-32,xy
33,-36yy
34,-35,x
below with third nine following numbers
1-2,yz
3-6xyz
4-5
7-8,xz
9-12yy
10,-11,xz
13,-14,xy
15,-18
16,-17,
19,-20,
21,-24x
22,-23,yzz
25,-26,x
27,-30xz
28,-29,
31,-32,xy
33,-36yyz
34,-35,x
zero=z
below with fourth group following numbers.=v
35
----
32
30
4
12
----
8
10
16
12(fourth nine numbers=v)
1-2,yz
3-6xyz
4-5v
7-8,xzv
9-12yyvv
10,-11,xzv
13,-14,xy
15,-18
16,-17,v
19,-20,
21,-24x
22,-23,yzz
25,-26,x
27,-30xzv
28,-29,
31,-32,xyv
33,-36yyz
34,-35,xv
zero=z
Let's see their behavior,
(small micro sample tho...)
1-2,yz
3-6xyz
4-5v
7-8,xzv
9-12yyvv
10,-11,xzv
13,-14,xy
15,-18=(single gap)
16,-17,v
19,-20,(single gap)
21,-24x
22,-23,yzz
25,-26,x
27,-30xzv
28,-29,(single gap)
31,-32,xyv
33,-36yyz
34,-35,xv
zero=z
SEE the REPEATER???
After the X,Y?
We need more samples, to see more behavioral tendencies...
Single gap, double, triple or quad...
And how to bet only TWO TO FOUR chips...
Let's see their behavior,
(small micro sample tho...)
Next 37spin,
let's mark them as "A",B,C,D,
for easy eyes.
----
29A
25A
32A
34A
11A
30A
19A
27A
20A
----
21B
15B
8B
27B
7B
27B
1B
19B
31B
----
33C
4C
17C
6C
16C
8C
25C
10C
1C
-------
10D
2D
22D
1D
34D
0D
6D
33D
8D
----
Xxxx
And mark them on the table, "ayk style"
1-2,yzBCDD
3-6xyzCD
4-5vC
7-8,xzvBBCD
9-12yyvv
10,-11,xzvACD
13,-14,xy
15,-18=(single gap)B
16,-17,vCC
19,-20,(single gap)AAB
21,-24xB
22,-23,yzzD
25,-26,xAC
27,-30xzvAABB
28,-29,(single gap)A
31,-32,xyvAB
33,-36yyzCD
34,-35,xvAD
zero=zD
..
See what happened?
Now,
in next 37 spins...
37...ayk. Averages....
24hit...line
12 repeat....line.
When the "12repeat line" has hit six repeat, then bet the remaining "24line"numbers that had appeared, and when it appear, in next spins...
since averages theory,
six numbers will repeat in next remaining spin up to the 37th spin...""""
This not hg, but just a thought...
Below, three sets of 37spins of Dublin,
Where you see,
1sthas 13unhit,
2nd set has 18unhit...
If you do a ayk with 01234...36,
And contrast with pairing of 12,36,45,....34,35...
You will see differences.
Just do it, and you will understand something...
27
34
31
22
2
34
10
20
34
35
25
9
9
31
26
4
18
17
1
31
13
22
16
30
0
3
27
28
17
16
32
20
34
34
22
29
21
2
24
13
29
24
24
35
7
16
24
16
28
30
6
34
21
32
16
18
16
4
36
6
6
27
7
36
1
6
24
32
20
29
6
13
32
24
0
11
4
14
18
26
14
17
19
11
23
19
12
11
20
36
15
17
33
4
16
8
32
29
27
28
6
13
12
36
14
26
25
2
34
33
2
leoncino74.jpg
Thanks to LEONCINO74, for this image...
As you see, thou just small data, you can see the. REPEAT, vs ,a row of 12345...37.
You see the linear of unhit...
Can you see them?
If we do a 37spins,
with the pairing ayk method ,
and then, another new ayk,
with following 37spins,
then, another new AYK with
following 37spins,
till hundreds of millions sets, of AYK 19blocks...
We can be assured that,
pairing numbers, AYK,
(that has 36/2+1zero=19block),
will not have a REPEAT,
of previous 37spins...
AYK 19blocks pattern..
Though math wise it has probabilities, but you never see one in your lifetime...
What's more, if the numbers arrangement,
is ,
different...
The ayk still has 19blocks,
But the numbers ARRANGEMENT is different. with every following 37spins...
THUS, every 19block, will not repeat the previous...
If 12 numbers sleep for next 37spins,
(which always happen, as the average , always 12 numbers not hit in 37spins),
which is random..
But in dozen1,2, and 3,
each dozen will not sleeping for next 37spins,
though it's math wise probability possible.
If dz1 sleep for next 37spins,
(which you'll never see in your lifetime),
Then ,
123456789,10,11,12...
12n/2=6blocks,
a linear of six empty blocks,
thus you'll never see,
a linear of six empty blocks,
in pairing ayk method.
We do not bet the math, as we can't beat the math,
WE BET THE BLOCK....as it do not succumb to the math...
this thinking outside the box, IMHO...
One simple betting strategy,
to bet this 19blocks AYK...
Say,
1)One chip on leftmost block.(not hit)
2)one on previous leftmost, and one on the rightmost...(not hit...)
3)One on leftmost and 1 on rightmost, add 1 on second leftmost ...not hit
4) repeat previous bet, add one on second rightmost....
Just add one on left, then right, then left and so on...
HOPE, You get the idea...now
You need to figure out the progression....
It just bet 1, 2,3,4,5,6,7,.....so on till hit...
Or is it just that simple???
Anyone following this? Not clear to me, at all.
Blueprint,
Reread page 1 to 5 and post #1583 of "37back to basic"
We could also do NINE blocks of AYK, insurance on zero, using root or foundation numbers of roulette.,
No
Below,
Example,
small data,
of
36 spins.
With only the root numbers shown...
Since there's only 9root, thus we mark 1st,2nd,3rd&4th, set of 9 spins, roots with xyzv
3x
5x
3x
4x
2x
9x
4x
4x
4x
2y
1y
3y
8y
7y
4y
5y
8y
7y
3z
1z
3z
2z
3z
4z
2z
4z
9z
7v
3v
3v
8v
7v
7v
7v
8v
7v
Below, an example of AYK with the root numbers that hit in the 36spins.
1YZ
2XYZZ
3XXYZZZVV
4XXXXYZZ
5XY
6
7YYVVVVV,,
8YYVV
9XZ
Hi Sweet
how would you play the root numbers? Ok we have x-y-v-z, there are repetitions in cycles of 9, but how would you play "through the cycles"? thanks for the help
Leoncino,
Thanks for your post,
You do as many possible, AYK with 37spins only, root numbers, and post them, so we could see their behavior, and figure out how to bet the repeat in linear.
Thanks again.
1YZ
2XYZZ
3XXYZZZVV
4XXXXYZZ
5XY
6
7YYVVVVV,,
8YYVV
9XZ
The above AYK is too small a data sample, but we can see only one block empty...
Quote from HERBY...
Simulation: 100.000 times 111 Numbers 0-36:
{{28, 1}, {29, 3}, {30, 36}, {31, 278}, {32, 1629}, {33, 6062},
{37, 14184}, {34, 16971}, {35, 29991}, {36, 30845}}
Minimum: 28 different numbers
Unquote
28:1mean only 28 number hit=only hit once...
How to apply these fact to ask linear method, with pairing or root.
Since 28mean only 9unhit.
Thus 9/2=only 8pairs,
No FOUR BLOCKS IN ROW
or
only 2sets of root...
NO TWO BLOCKS IN ROW
Quote by notnab
After 37 spins only 28 numbers will hit (01%) 9 won't hit
After 37 spins only 27 numbers will hit (04%) 10 won't hit
After 37 spins only 26 numbers will hit (09%) 11 won't hit
After 37 spins only 25 numbers will hit (16%) 12 won't hit
After 37 spins only 24 numbers will hit (20%) 13 won't hit
After 37 spins only 23 numbers will hit (20%) 14 won't hit
After 37 spins only 22 numbers will hit (15%) 15 won't hit
After 37 spins only 21 numbers will hit (08%) 16 won't hit
After 37 spins only 20 numbers will hit (04%) 17 won't hit
After 37 spins only 19 numbers will hit(1.2%) 18 won't hit