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Roulette-focused => Main Roulette Board => Topic started by: FreeRoulette on Feb 01, 12:26 AM 2025

Title: Let it ride once on dozens.
Post by: FreeRoulette on Feb 01, 12:26 AM 2025
Bet one dozen, if you win, keep the winnings on the table for a second win. If that wins, reset the progression. If it loses, then move to the next bet in the progression.

Dozens bet progression.
1,1,1,1,1,1,2,2,2,2,3,3,3,4,4,5,5,6,7,8,9,10

It costs $75 and gives 22 spins to get 2 wins in a row.

The reason this works is that the payout is 8 times your bet. Let say you are betting the first 2 in the progression, you lost 6 (1,1,1,1,1,1). 2 pays 4 and you now have 6 on the table and it wins again and pays 12, now you have 18 minus the 2 that you originally bet = 16 (or 8x your original bet) this more than covers the $6 loss.


Title: Re: Let it ride once on dozens.
Post by: Blueprint on Feb 01, 07:08 AM 2025
Let er ride!  Thanks
Title: Re: Let it ride once on dozens.
Post by: nottophammer on Feb 01, 08:33 AM 2025
What happens when that 1 dozen goes 34 spins
Title: Re: Let it ride once on dozens.
Post by: TRD on Feb 01, 04:43 PM 2025
Why won't you optimize to +1 at game won with 2 consequent hits, using ½ unit increment (or even less), that way you are going to
• generate exposition at lower increase rate
• prolong the nunber of steps = sustain further
• maximize the certainty of a game won

If your base-unit=1 is (¥€$₤)10, then using 1.5u makes that 15 .. simple with gandling the chips, even if eg. 13 or 17 too.

Title: Re: Let it ride once on dozens.
Post by: TRD on Feb 01, 09:12 PM 2025
12-14x spins extra -- either averaged at +1 or +0.74 u/game
First spin EC, theafter 2x consective DZ-hits.

copy-paste link in the address bar ending with xlsx included
mediafire.com/file/8qusckgkr8dbfyb/Freeroulette+•+2xDZ.xlsx/file"]xlsx
Title: Re: Let it ride once on dozens.
Post by: TRD on Feb 02, 06:51 AM 2025
Although I posted that, I do not endorse playing this of any other negative progression based systems; though this one incorporates press too.

These are literally the first two sessions simulated & both busted. First session in the very first game to positive played & that at not 22- but 32-steps. Second resolved a few games, one of which had DZ-hits on spins 23+24 & shortly after that another 32-step bust, including the first spin being EC.

Base unit set at 50, for ease of chips placement + the lowest stake exceeding the table-minimum=10.
Bet-selection -- last-outcome.

session1 -- i.ibb.co/zWmYz1rp/i-Markup-20250202-122832.jpg
session2 -- i.ibb.co/23pxvyhd/i-Markup-20250202-122644.jpg
progression -- i.ibb.co/Wv5XYf6W/i-Markup-20250202-122743.jpg

I'd suggest to get rid of that negative progression altogether & base it only on the press + requiring an increasing number of 2-3 hits combos, if needed.

I'd also switch that to EC→DZ combo at first, then after winning that one, if necessary cascade to deeper-payout combos eg. DZ→DZ, DZ→DS, DS→DS, DS→Q ... but if that does not work out relative to the gains, always get back on & revert to higher-payout combos -- in order to increase the probability of the first-hit & combo-realization, keep the max exposition much lower = recoverable drawdowns + take advantage of clusterred-appearances with successive combos.

Eg. amongst other things, every so while a ds-area hits 3-4-5 times in a row, or relatively close-by .. where you may capitalize on that firstly with EC→DZ (3:1 combined), giving you 3-spins at 1u to further amplify that with DZ→DZ (4:1, 3:1 .. if hit on the 2nd-spin after securing the first & in total the 3rd-hit) or DZ→DS (7:1, 6:1). That's on top of the initial 3:1, so in total somewhere between (10:1 or 6:1) with all 4-hits combined.

These & various other combinations.

Title: Re: Let it ride once on dozens.
Post by: FreeRoulette on Feb 02, 03:29 PM 2025
You can also play this same method betting on two dozens.

loss = sum of losses
next bet = loss/2.5 + what ever profit you want

loss = 25
next bet = 25 / 2.5 = 10 + add any profit you want at the end. 

spin 1 
dozen 1 = 10, dozen 2 = 10 win (split the win across bets)

spin 2 
dozen 1 = 15, dozen 2 = 15 win = 25 total



Title: Re: Let it ride once on dozens.
Post by: FreeRoulette on Feb 02, 03:55 PM 2025
@nottophammer
QuoteWhat happens when that 1 dozen goes 34 spins

I would be strategic about when and where to play to bet.

To answer your question though, you would be out $75.







 
Title: Re: Let it ride once on dozens.
Post by: FreeRoulette on Feb 02, 07:20 PM 2025
Play two dozens

Main:   1, 6,  8,  11,  16,  22,  31,  43,  61, 85
Second: 1, 9,  12, 16,  25,  35,  45,  65,  90, 125

Looking at Main, you would place 1 on each of the two dozens. If that loses, then place 6 on each dozen and so on.

Main is the normal progression, but if it wins, then look at Second to place the next bet on each dozen.

For example, if 8 wins, the next bet would be 12. 

Win twice in a row to reset.
If it loses, then move to the next bet on Main, which is 11.