Hi Bayes and fellow maths heads,
Bearing in mind that according to Bayes statistics on 1m repeats, the sixth last drawn number is the most likely to repeat, how much can you reduce the house edge by playing an even chance bet to match the sixth previously drawn number? According to those statistics, roughly 1/10 repeats will be a repeat of the sixth number drawn. If we bet the same RB/HL/OE of that number, by what percentage do we reduce the house edge?
Thanks
Woods
How many repeats in 1m spins?
Divide that amount by 10 then you have the total number of sixth number repeats. = X
In 1m spins you will bet every 6th spin on an EC totalling 166,666 bets.
Divide 166,666 by X for your number of wins.
You can figure your % from there.