I'm toying with the idea of a double progression. It takes an average of 15 spins to get 3 reds in a row, and most of the time it happens in 30 spins.

Progression 1:

[2, 2, 2, 2, 3, 3, 3, 4, 4, 5, 5, 6, 7, 8, 9, 10, 11, 12, 14, 16, 18, 20, 22, 25, 28, 32, 36, 40, 45, 51]

This works like a normal progression, if you lose, then you go to the next bet.

Progression 2:
Every time you win, you parlay the bet for 3 spins.

For example, if you bet the first 5 and it win, then bet 10, it wins, then bet 20 for the last win of a total of 40.

The sum of losses to that first 5 bet is [2, 2, 2, 2, 3, 3, 3, 4, 4] = 25 loss  for a profit of 15

Review your payout.
For example, if you bet the first 5 and win three times in a row, your profit are 5+10+20=35.
If you deduct the previous loss of 25, the profit become 10.

You are right. What do you think of this system?

The double progression will burst more often than you think because of the number of times it exceeds 30 spins.

If I remember correctly, it can take up to 60 spins to be sure to see 3 reds in a row. It's getting too expensive and risky.

Make a calculator. Might be worth trying if the bankroll is low enough.

tracker.potads.uk/sim_wes/sim_martingale_parlay/martingaleProgression.html