A kind of contre d´Alembert on groups of six.

[Dane]

In roulette circles Jean le Rond d´Alembert (1717-1783) is associated with "Progression d´Alembert": One step up after losing and one step down after winning. A few examples: -1-2-3+4+3+2 = 3. And 1+1+1-1-2-3 = -3. The player from the French Age of Enlightenment might be balanced. And Red and Black might be in balance in the last example. But this balance does not mean, that we are at level 1.
"CONTRE d´Alembert" is contrary to "Progression d´Alembert": One step up after winning and one step down after losing. I do not think it is worth tryiong on the simple chances. I rather try it in a flexible way on the known groups of six (transversal simple, six lines or double streets): 1. =  1-6
                                                                                                                                                                                       2 =  7-12
                                                                                                                                                                                       3 = 13-18
                                                                                                                                                                                       4 = 19-24
                                                                                                                                                                                       5 = 25-30
                                                                                                                                                                                       6 = 31-36.
I bet the groups that came IN THE LATEST FOUR SPINS. The average is just a little bit more than three groups. Within four sessions I one bet only one group.
63 X two DS (Double Streets), 159 X three DS, and 68 X four DS.
Each session ends when I have won on level 10. My first four sessions (from the first four days of 2011, table 3, Spielbank Wiesbaden) resulted in 181+87+27+80 = 375. 375 chips or units.
KEEP AN EYE OF THE LATEST FOUR SPINS!
3
13
29
20..One chip on DS 1, 3, 5, 4.
20..Hit! So we go one step up: TWO chips on each relevant DS, say DS 3, DS 5, DS 4.
0..Loss. One step down. One chip on DS 5 and one chip on DS 4.
13..Loss. There is no step down from here! So we place on chip on DS 4 and one chip on DS 3.
3.. Loss. One chip on DS 4, one chip on DS 3, and one chip on DS 1.
28.. Loss . One chip on DS 3, one chip on DS 1, and one chip on DS 5.
5..Hit! One step up. TWO chips on each relevant DS (three groups).
                                         And so forth and so on.
                                                  Good luck!
                                                      Dane