Simple question about odds for Red/Black?

[falkor]

Hi guys can you please confirm if the following outcomes each have the same chance of occurring - yes or no?

Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red (x22)

=

Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black (x22)

TRUE OR FALSE?

As I know the record for most reds in a row is supposedly 22, but the point of the problem here is: does alternating red/blacks have the same rare chance of occurring?

The alternative to true/yes - as I see it without testing (and taking into account my crappy maths!) - is that you would need 12-22 pairs of Red/Back (total: 22-44 spins) to equal 22 Reds?

Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red, Red (x22)

=

Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black, Red, Black (x44 or somewhere between x23 and x44, say, x33)

TRUE OR FALSE?

Who can confirm? Thanks in advance as always! And again: apologies for my crappy maths!

[Colbster]

The odds of the next result are 50/50 regardless of what has already happened (obviously excluding the 0).  If you are asking about odds, we state the odds of the future.  The odds of getting exactly the 22 reds is the same as getting the 22 alternating results IF WE ARE PREDICTING THEM BEFORE THEY HAPPEN.  As each spin would require a specific result to conform to your patterns, there is a 50/50 chance at each of the 22 steps along the way.  Looking back, I would anticipate the alternating to be a more plausible result, but the odds of it happening are the same.