Doublestreet Method "Juggernaut"

[buffalowizard]

Firstly, list the corresponding DS numbers in a three wide row, like this,

3, 1, 5
2, 3, 1
6, 6, 5 etc

All you have to do is wait for 2 consecutive rows of either odd or even dominant DS numbers

In the example above, odds are dominant for the first 2 lines, by either having 2 or all 3 numbers as being 1,3,5

You then bet for the opposite in the next row - 3 times. In the above example, you would bet the even DS's, 2,4,6
It wins first time out.

I may have posted something similar to this many moons ago, but this one is safer, waiting for the two dominant lines.

2, 5, 6 even dom
1, 1, 4 odd dom
3, 5, 2 odd dom, bet evens
4, 3, 1 win

you get the picture! Let me know how you get on - it's easy to play and you get enough of a break in between bets to get smashed on some ale so it;'s all good.

Cheers

BW

[RouletteGhost]

so if 2 out of the 3 or even thats considered even dominance and the next 3 will be betting odd DS

easy, like it

[buffalowizard]

2 consecutive rows must be 2/3 or 3/3 dominance, not just one row

[RouletteGhost]

got it

already testing

will decide on progression and whether or not to stop after 3 losses in a row and then go back to one unit

[GLC]

Buff, I've got to ask this.  What is the difference between evens vs odds and lows vs highs?  Or any other 3 lines vs the opposing 3 lines?  As a matter of fact, anytime you get 6 spins with 3 of the lines dominating, you can bet on the other 3 lines.  This will give you more betting opportunities.

GLC

[RouletteGhost]

GLC always has an innovative idea to make something better

you can record all the EC bets including double streets and bet against the dominating ones every 6 spins