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Pigeonhole Principle - list of theorems/generalizations

Started by falkor2k15, Aug 23, 05:36 AM 2017

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falkor2k15

Can anyone come up with a full list of theorems and generalizations? How complete is the below list? I can only understand the first 2. Can anyone understand the rest of them containing "k" in the formulas?

Pigeonhole Principle (PP)
If n+1 objects are placed in n boxes, then one of the boxes must contain more than 1 object.

(PPb)
If n-1 objects are placed in n boxes, then one of the boxes must be empty.

Extended Pigeonhole Principle (EPP)
If nk+1 objects are placed in n boxes, then one of the boxes must contain at least k+1 objects.

(EPPb)
If nk-1 objects are placed in n boxes, then one of the boxes must contain at most k-1 objects.

Generalized Pigeonhole Principle (GPP)
If nk+s or more objects are placed in n boxes, then for each 0 ≤ m ≤ n there exist m boxes with a total of at least mk + min(s,m) objects

(GPPb)
If nk+s or fewer objects are placed in n boxes, then for each 0 ≤ m ≤ n there exist m boxes with a total of at most mk + max(0,s+m-n) objects
"Trotity trot, trotity trot, the noughts became overtly hot! Merily, merily, merily, merily, the 2s went gently down the stream..."¸¸.•*¨*•♫♪:

falkor2k15

Pigeonhole Principle (PP)
If n+1 objects are placed in n boxes, then one of the boxes must contain more than 1 object.


In 4 spins 1 dozen has to repeat (excluding zero). Dozen have 3 boxes/pigeonholes. And in 4 spins we have 4 objects/pigeons.

(PPb)
If n-1 objects are placed in n boxes, then one of the boxes must be empty.


This could be the basis for the HG! If you can come up with a rule that puts less pigeons into more pigeonholes then we are guaranteed to never encounter a deadlock - a repeat will always happen before all uniques have shown.

Extended Pigeonhole Principle (EPP)
If nk+1 objects are placed in n boxes, then one of the boxes must contain at least k+1 objects.


I think this is related to multiple repeats? There will be 4 repeats (5 hits) of a dozen in 13 spins. Dozens have 3 boxes/pigeonholes (n). K = 4 = number of repeats. K +1 = 5, so 5 dozens/pigeons are placed in 1 pigeonhole:
D1
D1 D2 D3
D1 D2 D3
D1 D2 D3
D1 D2 D3

(EPPb)
If nk-1 objects are placed in n boxes, then one of the boxes must contain at most k-1 objects.


Related to the above, but need to think about this.

Generalized Pigeonhole Principle (GPP)
If nk+s or more objects are placed in n boxes, then for each 0 ≤ m ≤ n there exist m boxes with a total of at least mk + min(s,m) objects

(GPPb)
If nk+s or fewer objects are placed in n boxes, then for each 0 ≤ m ≤ n there exist m boxes with a total of at most mk + max(0,s+m-n) objects


I guess these last ones are based on the maximum pigeons being more than the average "For a non-empty, finite bag of numbers, the maximum value is at least the average value"?

Let's say we got 3 dozens and 3 pigeonholes to put them in. The maximum number of dozens/pigeons is 3, so the average is 2. The maximum is always greater than the average + 1?
"Trotity trot, trotity trot, the noughts became overtly hot! Merily, merily, merily, merily, the 2s went gently down the stream..."¸¸.•*¨*•♫♪:

Steve

Pigeons crap where they want, when they want. They don't care about your rules.
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

Turner

Quote from: Steve on Aug 23, 06:48 AM 2017
Pigeons crap where they want, when they want. They don't care about your rules.

Correct, Dick Dastardly never managed it


Steve

"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

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