Guaranteed hits. . .

[Person S]

Slightly changed the game, now the bet on the cycle.
I wonder who can analyze how many times in a row can get CL4?

[Firefox]

Take the Ec's for what they are mate...
But what are your thoughts on the dozens??

The dozens also lose in a similar manner.

But they lose twice as quick, as the house edge on dozens is -2.7% whereas on the even chances it is  only -1.35%  assuming partage or en prison rule.

It's not possible to get an advantage on an Even Chance cycle without zero and the same with dozens. Just play a cycle out through all outcomes and you'll see they are break even.

Add in zero and it's a losing game, the dozens losing twice as much for the same value bets.

[mickavelli]

It's not possible to get an advantage on an Even Chance cycle without zero and the same with dozens.

What was suggested is that we bet against the third in the column that initially hits twice because it has only a 1 in 3 chance of being the winning column. So for the third we are betting two dozens on that single spin. If one of them wins the problem then becomes "Which dozen do we bet on the next (4th ) spin?  We have three options here , haven't we -
dozen 1  - dozen 2 - dozen 3
Which one you choose is up to you.
It was suggested betting the one below the first two winners but that is a personal choice. No matter which one you choose you get odds of 7/2 when you bet the 3 chips from the previous win and thus collect 9 chips.
It can be seen that these are correct odds when discounting the zero.
You mentioned non random but this relies on random to be in our favour to beat the HE
Basically, if the first bet looses, play is over, there is no bet on spin 4 - The 9 options are reduced to 8 !
Having now only 8 "Pairs" to contend with after putting ONE chip on each of the TWO dozens on the first bet and if one of them wins bet THREE chips on ONE dozen on the next spin and collect 9 chips - if won -  we win with fair odds of 7/2.
We had 2 chances to win "1 pair" of NOW - 8 "pairs" - a 1 in 4 chance.
Fair odds for which is 3/1 ( 3+1 =4 )
2/8 is one in four chance so - payout should be 3/1 if successful.....
Here, we are getting 7/2, even after allowing for zero!
Nobody is claiming that advantage must win - people like yourself do !

[mickavelli]

Nothing is guaranteed except for the fact that when you put 3 numbers against each other using the grid 1 column is guaranteed more hits
How we use it is up to us!
Dozens aren't the only thing with 3 numbers on the table for example if you played columns at the same time there are straights that overlap.. Or 4 numbers that intersect...
See what you come up with!

[mickavelli]

Slightly changed the game, now the bet on the cycle.
I wonder who can analyze how many times in a row can get CL4?

What game are you playing here mate?

[hanshuckebein]

the topic has reminded me of this one. so fyi.

cheers
hans

[mickavelli]

This is exactly it !! Thanks a million mate I have been looking everywhere for this

[Person S]

What game are you playing here mate?

We have 4 possible outcomes of RR-RB-BB-BR.
I'm looking for an opportunity to repeat, if you take the grid, it will look like this:
RB - if 9 spin comes out R, then on spin 13 we can play for the combination of RB. The rest is identical ...
RR
RR
RB