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How Long Until A Repeat?

Started by Bayes, Aug 19, 08:14 AM 2010

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0 Members and 1 Guest are viewing this topic.

Bayes

Based on a 1M trials. The left column is how long you had to wait for a repeat, and the right column tells you how many times that wait occurred. The average wait is a little over 8 spins, and the most common is 6.

WAIT   FREQUENCY

1         3241
2         6452
3         8923
4         10974
5         12358
6         12671
7         12440
8         11614
9         10095
10       8454
11       6914
12       5349
13       3771
14       2659
15       1818
16       1161
17       695
18       413
19       203
20       109
21       44
22       21
23       12
24       7
25       3
26       1
27       1
28       0
29       0
30       0
31       0
32       0
33       0
34       0
35       0
"The trouble isn't what we don't know, it's what we think we know that just ain't so!" - Mark Twain

VLS

Excellent contribution.

It is amazing how results from different numerical samples can match together in tests made by independent researchers.

Similar figures has been managed by the several studious of roulette as the common average wait. If I recall right, Pierre Basieaux places the average at around ~7. And now we have yours also.

Thank you dear Bayes! :thumbsup:
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sekuritati

Dear Bayes,

since we have started checking samples, would you please check for me in your samples how long does it take for a dosen to repeat itself consecutively on average

It is my impression that, for example, in a 10 spin sample we are almost certain to observe a dosen which has repeated consecutively at least once.

I hope you understood my request

Bayes

Thanks Vic.  :)

@ sekuritati,

You are correct!, the average is actually once every 10 spins (precisely, 9.5 spins). But I will do some tests to see what the dispersion is.
"The trouble isn't what we don't know, it's what we think we know that just ain't so!" - Mark Twain

Bayes

Actually, it's only 1 in 10 if you're talking about a particular dozen, if you mean ANY of the dozens repeating then this happens once every 3 spins, on average.

This means the distribution for repeating dozens is the same as that for any particular dozen, so for example, the longest you have to wait for any dozen to repeat is the same length as a particular dozen might sleep, which is anything up to 35 spins.
"The trouble isn't what we don't know, it's what we think we know that just ain't so!" - Mark Twain

Kattila

Hi  Bayes,  talking about repeaters , i ask this because i never play
this way , just curious:

Let s  say i wait 10 spins without any repeat,
than start to bet that last 10 numbers, than comes new number
bet last 11 numbers, than  new number and bet  the last 12 nmbrs.,
than add new number  and so on until  i bet  18 numbers, so the
last 18 numbers . Progresion first on 10 numbers, second on 12 nmbrs,
third steep on 13 numbers...so on until 18 numbers.
Stop lose at  around -280 ( 9 progression steeps).

What chances ,or  avarage have this ? Probably none, just curious.

Or better wait 7 spins without repeat, than bet  like above,
on the last 7 numbers, than 8 numbers etc... around the last 15 numbers.

Thanks.

RMore

Bayes, I don't know if you are still active re this post but I need a little help understanding your results.   Is this saying, for example, that in a 1M spin trial there are no occasions where a number repeated at 29 spins? or 30? etc.   The numbers seem very low.   I tried to replicate these results and get a very different picture.

wait   number of occasions for this wait
1       27284
2       26380
3       26188
4       24636
5       23672
6       23584
7       22580
8       22300
9       21700
10      21423
11      20496
12      20136
13      19516
14      18739
15      18308
16      17739
17      17339
18      17024
19      16058
20      16256
21      15227
22      15004
23      14596
24      14680
25      14000
26      13468
27      13336
28      13292
29      12419
30      12276
31      11848
32      11603
33      11284
34      11136
35      10508
36      10288
37      9960
38+    363680

Roger

woods101

@Roger

It shows the longest period you had to wait before a drawn number repeated.

Woods

vladir

Can any of you calculate something else I would like to know?

I wanted to know.... how long between occurences of straigth repeats (the same number appearing twice repeatedly).

e.g: 0-0- 1-5-7-10-20 -20 -2- 10 -34-34

The numbers marked o Bolt are the repeaters.
In this example we have an interval of 4 numbers, then of 2 numbers.


Chees and thanks.



"In God we trust; all others must bring data", W. Edwards Deming

Bayes

"The trouble isn't what we don't know, it's what we think we know that just ain't so!" - Mark Twain

vladir

Quote from: Bayes on Oct 25, 03:24 PM 2011
37 spins.  :thumbsup:

Thats on average? It's not the maximum, I think maximum it goes way more then 100 spins...
"In God we trust; all others must bring data", W. Edwards Deming

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