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Law of the thirds on dozens

Started by GLC, Nov 28, 12:11 AM 2011

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GLC

Check the last 2 spins and bet any dozens that didn't show.

If only 1 dozen didn't show, bet 1.

If lose above bet and the last 2 dozens are the same dozen, bet 2 each on the 2 dozens that didn't show.  If lose, stop and wait for 2 different dozens to show.

If you bet 1 on a single dozen and it loses, and there are 2 dozens in the last 2 spins, bet 2 on the missing dozen.  If lose and you don't have the same dozen twice in the last 2 spins, bet 3 on the missing dozen.  If lose, end of progression so start over.

Summary:

Check last 2 dozens.  If same dozen, bet 1 on each of 2 dozens.  If lose and last 2 spins are the same dozen, bet 2 on each of 2 missing dozens.  If lose stop.
If last 2 dozens are different, bet 1 on missing dozen.  If lose and last 2 dozens are the same dozen, bet 2-2 on the missing dozens.  If lose, stop.

Our progressions are 1-2-3 on single dozens and 1-1 or 2-2 on double dozens.  That's 6 units for either way.

Seems to hold it's own.  Try it!

GLC
In my case it doesn't matter.  I'm both!

marivo


marivo

What about if last 2 dozs are different and you bet 1 on missing, lose, but last 2 dozs are now the same? What do you do in this case? Thanks.

GLC

Quote from: marivo on Nov 28, 02:44 PM 2011
What about if last 2 dozs are different and you bet 1 on missing, lose, but last 2 dozs are now the same? What do you do in this case? Thanks.

In this case, either bet 1-1 on the other 2 dozens to break even or 2-2 on the other 2 dozens to reach +1.  You decide.

Just don't bet more than 3 on a single dozen or 2-2 on a double dozen bet.

I know a steeper progression will win more in the short run, but this progression will keep us up to date as to how we're really doing.  It's a little more aggressive than a flat bet, but not so steep as to get us into real trouble.

I suppose to be exact, we should look at the last 3 spins and bet the missing dozen.  This would mimic the law of the thirds formula more exact.  The law of the thirds reveals to us that in 37 spins only 2/3 of the numbers will show, give or take a couple.  So, if we apply it to the dozens, in 3 spins 2 should show and 1 sleep.  We can either bet on the 2 that showed or we can bet on the 1 that didn't.  I don't know if the law of the thirds is valid for dozens, lines, streets etc...  I don't see why not. 

I find this as good a dozens selection method as any.
In my case it doesn't matter.  I'm both!

GLC

Thinking about the last post and whether the law of the thirds applies to dozens, some observations.

When tracking single numbers, in 37 spins the law of the thirds says that we will get approximately 24 numbers show.  We will never get all 37 numbers to hit in 37 spins.  Neither will we only get 12 numbers to hit and the other 25 to sleep.  (I know the using the word "never" is to absolute, but for practical purposes it applies).

With dozens, we can get all 3 to hit in 3 spins and we can only have 1 hit and the other 2 sleep.  So in fact dozens do not follow the law of the thirds except in a general way.  Probably most of the time we will have 2 of the 3 show and 1 sleep in 3 spins.

No matter that we are precise in our title.  It's just a bet selection method.  I'm still having luck with it.  I kind of like not using a steep progression even though I know that if I used the following:

1-1-2-3-4-6-9-14-21-31-47-70-105 etc... on the single dozen bets and

2-2; 6-6; 18-18; 54-54; 109-109 on double dozen bets we would be winning a lot of units between a total losses but the total loss would be a doozey.  We just have to pick our poison.
In my case it doesn't matter.  I'm both!

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