Math question over 2 spins

[FreeRoulette]

Take two spins.

Assume a normal roulette wheel with no zeros.

If one color is black, then the probability that the other color is red is 1/3.

Now, add both zeros back on the wheel. What are the odds of the second color being red?

[FreeRoulette]

Take two spins.

Assume a normal roulette wheel with no zeros.

If one color is black, then the probability that the other color is red is 1/3.

Now, add both zeros back on the wheel. What are the odds of the second color being red?

I meant to say the probability of the other color being red is 2/3.

[ego]

The odds is 1 in 2 and there is as many singles as there is series.
So it does not matter if your first bet is a single or a serie.

[FreeRoulette]

So in two spins if one color is black, then the probability of the other color to be red is 2/3.

But if we add one 0 in. Then the probability is 2/5.

However, the 0 doesn't have the same chance to come up as red, so I'm not sure how to factor that in.

[Tacwell]

So in two spins if one color is black, then the probability of the other color to be red is 2/3.
No, odds are 18/37 on a single zero table, regardless of the first spin result.

But if we add one 0 in. Then the probability is 2/5.
No, the probability is 18/37 incl. the 0

[FreeRoulette]

But that is for 1 spin. I want to do something with the combined results.

So if one spin came up blue the probability that the other color will be red is 2/3 on a no zero roulette wheel.

For example, the combinations  for two spins are.
BB
RR
RB
BR

The end result can not be RR since we already know one is black.

So the options for the end result are now
RB
BR
BB

So out of the 3 options, we want a red. There are only 2 choices out of 3 possibilities. So the probability of red being the other color is 2/3.