If U Really R that unlucky don’t do this idea

[nottophammer]

We’ll take 24 non-hit will hit in 37 spins.
So where do the repeats hit, or better still how many numbers that have hit, will you have to bet for the repeat.
with 24 numbers possibly to be bet, what spin number would give you the repeat, would it be at spin 9, where you will bet the 8 that have not repeated, will spin 9 be the repeat?


So as the tittle says R U that unlucky,
If we get 13 repeats as 24 non-hit come in 37 spins, and you bet every 3rd spin, spin 3, you'd bet 2 #'s, if its another non-hit, the next point is spin 6, where you bet the last 5 non-hits to come, again if another non-hit number hits, the next point is spin 9 and so on untill one of the bet points gives the repeat.
If you/I have been unlucky and are a spin point 12, we will bet the last 11 numbers that are unique, the cost will be 26 units in total accounting for the other bets.

Now this is where the shite hits the fan, spin point 15 would have us bet last 14 unique numbers, as we have bet 26 units already do we double the 14 to 28 units making a total bet spend of 54 units for return of 72 units.
God for bid if we are at spin point 18, meaning 17 unique have come, here we would have to lay 51 units just to win 3 units.

So would you really  be that unlucky

[nottophammer]

Okay here are 6 games posted on the forum, from steves multi-player, they are in spins from multi-player thread.
Reply 1 win spin 12
reply 2 win spin 24, but this is where non-hits have come fast. spin 24 only had 5 repeats.
reply 3 win spin 15
reply 4 win spin 12
reply 5 win spin 15
reply 6 win spin   9

[sugtips]

and you bet every 3rd spin,

Trying to understand it, consider me a noob.

Let's suppose repeat hits on 10th spin where we have not did bet, means we have lost, so do we restart the process? With what progression?

Anything can we do to bet every spin after 7 or 10 uniq hits?

Sorry for bad English.

Thanks.

[INTERCEPTOR]

I want trust me 

[nottophammer]

Trying to understand it, consider me a noob.

Let's suppose repeat hits on 10th spin where we have not did bet, means we have lost, so do we restart the process? With what progression?

Anything can we do to bet every spin after 7 or 10 uniq hits?

Sorry for bad English.

Thanks.

Theres not much to explain, as this is a set idea based on law of the third (LOTT).
LOTT, how.
Well LOTT says that on average you should/could have 24 of the starting 37 numbers hit once in 37 spins.
Now this idea is not random, is it, because you expect to see 13 numbers repeat, so every 3rd spin upto the 36th spin gives the chance for a number that has already hit to repeat at a set spin, so you are not betting randomly.

But it is still a 50/50 bet as its win/lose.

Why every 3rd spin, it gives 12 points to find the repeat.
Everyones bankroll could handle betting up to point 18, where a small profit of 3 would be made.

From collected data up to the 19th non-hit number to come in, these 19 numbers average to hit in 2 spins, but what is the max for them, well that ranges from 4 spins for the 9th number to hit, up to the 18th to have a max of 7 spins.

The 2nd reply showing the win came on point 24, if my math is right then you would be betting 23#'s @20 units, total 705 wins you 15 units.
So its like the tittle  If U Really R that unlucky-------- don’t do this idea

[sugtips]

Theres not much to explain, as this is a set idea based on law of the third (LOTT).
LOTT, how.
Well LOTT says that on average you should/could have 24 of the starting 37 numbers hit once in 37 spins.
Now this idea is not random, is it, because you expect to see 13 numbers repeat, so every 3rd spin upto the 36th spin gives the chance for a number that has already hit to repeat at a set spin, so you are not betting randomly.

Thank you Sir.

Sir can you please post a filled trot sheet with what you have suggested above.

thanks a lot.

[nottophammer]

I've got to go over Mortagons numbers so if my math is right it should look like this


Bet points in yellow
2
4    this is not a win sugs its betting last 4 unique numbers
7
10  this bet has cost 23 units so far. Next point is betting the 12 unique numbers, now is decision time, bet this for 12 units, if win you'll break even
24  i'd double the units lose
45  this is actual bet point 18, are you with me, theres 15 unique numbers to bet, so 45 units and it lost.
102  so your outlay at point 18 was 92 units, so do you have the bankroll ? if so then its 102 unit bet on 17 unique numbers, 17*6, lost.
228  19*12=228 Off track here, this game is fast from the point of view of non-hit numbers, its one of the times that the wheel is finding those that have not hit.

But you win +10

[nottophammer]

It be better to go for the repeat to happen in a group of 10 spins, each group has got at least 1 repeat in orange, 9/10, in 10 spins the most common outcome is 9/10.
Does the wheel know to keep making each group 10/10, no, but i know what would keep giving 10/10 if you was to play for this type of repeat. The FOBT, there just cheating cu nts

[sugtips]

Ok Thanks Sir, got it. I am with you.

[nottophammer]

If members from uk, wanna check that the FOBT cheats you. Just play like this,
1st spin bet last number with 1 unit, cheapest unit is usually .20p, there is .05p game if you want to search the screen.

But these machines want £1 minimum to spin. so bet 6 ds for .20p= £1.20 + the 1 unit of .20p
As each spin goes by you bet the unique numbers. the 1st 4 bets will need the ds part as 4th bet 4 unique numbers would not let you spin the wheel .80p

Now if the 4 unique lost, you can just bet the 5 unique with out the ds as you've placed a £1, 5*.20
So now you just add the unique numbers up to 10, if not won, it would mean you have had 10/10, so  restart.

If you get a few games giving 8/10-- 7/10 or the common 9/10, it wont be long before the FOBT just chucks out 10/10, eating your bank roll
As said would a live wheel keep banging out 10/10, dont think so, but these machines will

Now off to check ef-bet

[nottophammer]

Morts numbers, today
Remember the bet points, 3,6,9,12,15,18,21,24,27,30,33,36

[nottophammer]

Got to lay this to rest, you've won with spin 9,#20, restart from spin 10, win with #22 from morts #'s 20.5.17, as this is what would happen if you start at spin 13, you'd be really unlucky as this is not that rare.
So 31 is now spin1. we'd not win untill spin 33, #4


You are better off betting for a repeat in each block of 10 spins, as you see, 9/10--9/10--9/10--8/10, even the last 2 blocks get a repeat

[nottophammer]

But if you are prepared to go to say spin 18, betting every 3rd spin for a repeat, then what a great start.
Think i'll just go for repeat in blocks of 10 spins