Crazy Ivan

[amk]

-We divide the wheel in half form the zero.

-We wait until one half of the wheel has 5 numbers landed without a repeat. ("our side")

-We bet on those 5 numbers.

-If the ball lands on the other half we continue to bet on those 5 numbers.

-If the ball lands on our side we include that number to bet on, we now have 6 numbers.

-Each time the ball lands on our side we bet on all those numbers.

-If the ball lands on the other side we continue betting on the amount of numbers we have. We do not bet on the numbers on the other side. Only on our side.


Each session will have a different betting progression. MadMaxs progression calculator HAS to be used for live play.

I put this in the notepad because it has so many angles it is difficult to contemplate.

Hope there will be some insights.

[warrior]

I just came across this thread,i think there is a way to make it work ,instead of just using one side use both the sides ,the first to qualify  we start to bet this concept, and once there is a hit we stop and base it on 37 spins,so if you get a hit say 5 spins later after qualifing then let the 37 spins finish,or move to another table, we include the zero for both sides.what do you guys think,it should be tested.

[amk]

Hello Warrior,

Yes we should use both sides, the first to qualify and the zero can be used as well but for one half I think. It might be possible to play continuously or say 5 wins (5 different sessions) and then stop playing the wheel.

I think there could be something here. It is very unlikely that one half of the wheel has no repeats. I will try and test a little. Hope some others are interested as well.

[superman]

We divide the wheel in half form the zero

As there's 37 numbers in a european wheel does the above mean 18 or 19 numbers?

We wait until one half of the wheel has 5 numbers landed without a repeat. ("our side")

Please define repeat, would 32,15,32,6,13,19 qualify? as 32 has come twice but didn't repeat OR must all 5 hit one after another in a unique sequence, if so, why? a number is a number

[amk]

Hey Superman!

Yes one side will be 18 numbers the other 19. Left of zero 18 numbers and the other side 19 numbers.

With repeat I mean that one of our landed numbers on our side is hit again. We wait until one side has 5 numbers landed without a repeat (appearing twice) Then we bet on those numbers. If a number lands again on our side (no repeat) we now include that number as well, we have 6 numbers now. If the ball then lands on the other side we do not include that number we continue betting on just our 6 numbers. Ball lands again on the other side we just play or 6 numbers. Ball lands on our side, no repeat, we now include that number and we have 7 numbers. Then the ball lands on one of our 7 numbers on our side, we have a repeat (appeared twice) and we end the session in the plus.

My theory behind the method is that it will be rare that a number does not appear twice (repeat) on one side of the wheel. We know that there will always be a repeat in 37 spins. The very least we will have 3 repeats. On average I believe there will be around 12 repeats. Chance is small that they are all on one side.........  but ofcourse can and will happen   love that roulette.

We do not know the boundaries of this method. At this point the progression is huge but could be limited or tweaked, maybe a flat bet with a mild progression. I am sure GLC can find something for this. I think in the worst case scenario we can stretch to covering 12 to 15 numbers on one side. In total this could have gone 24/29 spins. If this is the case than we hung around a longtime for a 37 spin cycle

[warrior]

AMK I know your wanting this on a contnious bet,but i did a test on random.org ,5 games which is around 185 spins x5 almost a 1000 ,but i interupt after i won i waited for 37 spins to pass i won them all , i think it would be good to test both ways ,and see which is more profit.  

[amk]

Yes, hopefully this method can catch a little momentum and have some tests done. I like it but just an idea really. You are the first to really venture down this method. Your approach of waiting 37 spins should be followed, it feels like right thing to do.

In a sense we are targeting repeaters in a very precise way. We just don't know the limitations. What is the worst case scenario?

I started typing all of the angles to consider but could not contemplate them all. The method feels right at this point. There is something there.........

[warrior]

The MM is the real trick to this ,betting 5 6 then 7# and so on i will be trying to work more on this part and see what happens.