Winning Roulette Strategy, "The Buddy System".

[Norman Bates]

Exercise everyday, so that everyday isn't an exercise.

One of the things that I've always wanted to do is find a winning strategy for the game of Roulette.  It's more fun to play if you know that you are getting the best possible odds for a win.  So, keep in mind that it's to be played for entertainment purposes only.   That being said, I'd still like to have a little fun utilizing a strategy that I feel comfortable with.  One where I know that I'm getting the best possible odds for a win.

So my strategy is to start by betting seventy two chips.  They can be of any denomination, but the denomination must remain the same for all seventy two chips. 

So let's get started on the outside bets by betting five chips on the first twelve, seven chips on the second twelve, and three chips on the third twelve.  Continuing on betting seven chips on the first column of twelve, five chips on the second column of twelve, and finally with three chips bet on the third column of twelve.  For a total of thirty chips bet on the outside.

Now that you've done that, let's move on to the inside bets betting forty two chips across the inside of the layout.  Starting with placing bets of two chips each on the one, four, seven, and ten spots.   Four chips on the fourteen, seventeen, twenty, and twenty three spots, and finally, three chips on the twenty seven, thirty, thirty three, and thirty six spots.   Then you want to bet three chips on both the zero, and double zero spots.   For a grand total of seventy two chips bet.

Now, if the ball lands on either the zero, or the double zero spots, with three chips bet on the number, you will win one hundred, and five chips.   Add the three chips spared, and it comes to one hundred, and eight chips all together.  Subtract the original seventy two chips bet, and it comes to thirty six chips.   For a loss of thirty six chips.

If the ball lands on even the smallest winning bet, (like the two chips bet on the number one spot) with two chips bet, you will win ninety four chips, plus the fourteen chips that were spared it comes to one hundred and eight chips.   Subtract the original seventy two chips bet, and you get thirty six chips.    A loss of thirty six chips.

If the ball lands on the largest bet on the layout, (like number fourteen spot) with an original bet of four chips on the  number, it will be a win of one hundred and sixty four chips.   Plus the sixteen chips that were spared, it comes to a total of one hundred, and eighty chips.   Subtract the original seventy two chips from that, and it comes to one hundred and eight chips.  A win of thirty six chips.

Then, if the ball lands on the second to largest bets, (like the one on number twenty seven spot) with the original bet of three chips on the number, it will be a win of one hundred seventeen chips, plus the nine chips that were spared, for a grand total of one hundred and twenty six chips.  Then by subtracting the original bet of seventy two chips, we come to a grand total of fifty four chips.   A loss of eighteen chips.

So, when you add up the thirty six chip win, and the ninety chips lost, it comes to a loss of fifty four chips on average with every spin of the wheel.   So, you imagine the seventy two chips originally bet on each spin of the wheel as, " the break even point".   Then you imagine that these fifty four chips that were lost go below the break even point leaving twenty five percent, (eighteen chips) above the break even point.   For an average of eighteen chips being won on each spin of the wheel.   Another easy way to figure this out is to take the fifty four chip loss, and divide it by the seventy two chips bet.   Which comes out to be somewhere around the seventy five percent mark.    That means that by using this strategy, the house only holds seventy five percent.

So when you brake it down is sounds a little something like this: Seventy two chips bet, with six chips bet on the zero's, and sixty six chips bet strategically across the layout for maximum winning odds.

The only problem with this strategy, is that by yourself, you would probably never be able to set this betting strategy up at a live roulette table, because you only have a certain amount of time before the ball drops.  Also, you really can't reach across other people at the table to place all of these bets.  There are also betting limits as to how much you can bet on outside, or inside bets.  Because of that, you would need to have a team of three, or more people setting up these bets on all the different betting locations on the lay out.   So, that's why I call this strategy, "The Buddy System". 

Have fun, and good luck.

[VLS]

Welcome to the forum Norman,

Thanks for making your first contribution 

[Hermes]

It is only theory but it could work as a smart software. Let the complications to the programmer.
Hermes

[weddings]

do we bet the same bets every spin? for single zero table do we put 6 chips or 3 chips?

[sekuritati]

D1 - 5
D2 - 7
D3 - 3

C1 - 7
C2 - 5
C3 - 3

2 chips - 1, 4, 7, 10
4 chips - 14, 17, 20, 23
3 chips - 27, 30, 33, 36
3 chips - 0


0 - 108
1 - 72 + 15 + 21 = 108
2 - 15 + 15 = 30
3 - 15 + 9 = 24
4 - 72 + 15 + 21 = 108
5 - 15 + 15 = 30
6 - 15 + 9 = 24
7 - 72 + 15 + 21 = 108
8 - 15 + 15 = 30
9 - 15 + 9 = 24
10 - 72 + 15 + 21 = 108
11 - 15 + 15 = 30
12 - 15 + 9 = 24
13 - 21 + 21 = 42
14 - 144 + 21 + 15 = 180
15 - 21 + 9 = 30
16 - 21 + 21 = 42
17 - 144 + 21 + 15 = 180
18 - 21 + 9 = 30
19 - 21 + 21 = 42
20 - 144 + 21 + 15 = 180
21 - 21 + 9 = 30
22 - 21 + 21 = 42
23 - 144 + 21 + 15 = 180
24 - 21 + 9 = 30
25 - 9 + 21 = 30
26 - 9 + 15 = 24
27 - 108 + 9 + 9 = 126
28 - 9 + 21 = 30
29 - 9 + 15 = 24
30 - 108 + 9 + 9 = 126
31 - 9 + 21 = 30
32 - 9 + 15 = 24
33 - 108 + 9 + 9 = 126
34 - 9 + 21 = 30
35 - 9 + 15 = 24
36 - 108 + 9 + 9 = 126

Here's an RX testing of nearly 7000 live spins, second half of which are from Dublinbet tables 1&2.

I played 3 units on single zero so instead of 72 units for the whole bet, it was 69.

[Fripper]

Sekuritati, I got the same results as you did. Tested it for 10000 spins I think. Maybe we do something wrong?

[Red Nickels]

I want to delete my message, but there doesn't seem to be a delete function, so just nevermind...