The Ugly Duckling

[albertojonas]

I like to play flat and to observe how correlation of events behave...
One day of play is more or less 300 spins (live)
I use individual events to make my betting dynamic even with mechanical selections.
Here is one more of those, one can add to his arsenal...
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I observe 3 Reds in a row each from each Dozen:
I bet all the blacks in the last two Dozens


I observe 3 Reds in a row from the same Dozen:
I bet all the blacks in the two missing Dozens


It is always a 12 number bet.

[justanothergambler]

I think its a good idea, you are playing the kernel of an homomorphism of a Group with order 12! |Ker(phi)| =12

did you check if its a cyclic !? if so you might get a better bet selection.
just a thought

[albertojonas]

For those who like more betting opportunities


Same bet can be tracked on Double Streets (Lines / Sectors) using Odd & Even.


Same observation for trigger:


3 Odds in a row from 3 different sectors = bet all evens on the furthest sectors (like Vile latest system).
....
Notice that is hard to get 3 Odds or 3 Evens from the same sector.

[attachimg=1]

[albertojonas]

I think its a good idea, you are playing the kernel of an homomorphism of a Group with order 12! |Ker(phi)| =12

did you check if its a cyclic !? if so you might get a better bet selection.
just a thought

Interesting thought, Can you explain it better?
Cheers

[justanothergambler]

Interesting thought, Can you explain it better?
Cheers

a Group G is a certain set of elements and a certain operations like (Z,+) set on integers with plus operations. now if it exist a function phi which map certains elements of G to 0 then the set of those elements is called Kernel of phi. in you case the zero represents the black color/ (idem  phi' maps to reds so its kernels are the reds).
from here you can form another group which might be more interesting G/ker(phi) (G modulo N=ker(phi) which might be Normal Group then abelian)
you can then constract an isomorphism to (Z/2Z = group modulo 2 which contains only the elements {0,1}) black/reds in the other group.
when a Group is cyclic you need to know only one elementm because this element generate lets call it 'g' the whole Group with proprities : g^n = e ( e is the identity element of the Group, exp: 0 for (Z/2Z,+) , the n is a natural number) for example in Z/2Z the number 0 is the identity because 1+0 = 1 , and the group can be generated by only the element 1 : notation <1>
because 1¹ = 1 and 1² = 1+1 = 0 (note that 1² = 1+1 and not 1*1 because the Groups operation is the sign + !)we say 1 is order 2. as you see 1 generated the whole set {0,1} = <1> !
Now lets blacks represents zero, then if we could find a generator it will be g^n = blacks . 

[albertojonas]

I  am sorry but i do not understand that maths... Can you make an explanation for a 5 year old kid?
I do not even get how to apply it in practics...
sorry

[justanothergambler]

I  am sorry but i do not understand that maths... Can you make an explanation for a 5 year old kid?
I do not even get how to apply it in practics...
sorry

I am afraid there is no other simple way, that the simplest way to explain that..
but, what I mean in practice for your system, that operations + etc.. was just examples you might find some other kind of operations for your sets .. some kind an arrangements where black would hit after it, you should find that cycle and bet on it when it appears..
Im sorry if you dnt understand .. Im bad in explaining things! and english is my 4th language..