• Welcome to #1 Roulette Forum & Message Board | www.RouletteForum.cc.

News:

Almost every system has been tested many times before. Start by learning what we already know doesn't work, and why.

Main Menu
Popular pages:

Roulette System

The Roulette Systems That Really Work

Roulette Computers

Hidden Electronics That Predict Spins

Roulette Strategy

Why Roulette Betting Strategies Lose

Roulette System

The Honest Live Online Roulette Casinos

How Many Consecutive 8 Spin Sessions With No Number Repeating????

Started by amk, Nov 17, 02:16 PM 2013

Previous topic - Next topic

0 Members and 2 Guests are viewing this topic.

amk

How many consecutive 8 spin sessions do you think there can be max before we have a 8 spin session in which one number repeats?

What are your estimations????

My guess is no more then 6 or 7 sessions???

Example:

1,2,3,4,5,6,7,8    8 spins and not one number repeated   (1 session)

again

1,2,3,4,5,6,7,8    8 spins and not one number repeated   (2 sessions)

again ....  etc.....


Useful Stat:

Several million spin tests have shown that the average number of spins before the first repeat appears is after 8 spins.

Turner

but how does average help?....

in 10 sample.....2,6,11,12,9,5,5,13,6,9 ....the average is 8

None of the numbers are actually 8 and half are below 8 !!!

Several million spin tests have shown that the average number of spins before the first repeat appears is after 8 spins.

To get an average of more than 8, there has to be lots below 8 to make that average.....

amk

Hello Turner,

Perhaps I did not explain clearly.

On average the first repeating number will be within the first 8 spins.

If 8 unique numbers are spun there is no repeat.

I call this one session.

How many consecutive sessions do you think there can be max within which no number repeats in 8 spins?


Turner

Sorry...i get your question

Well...its simple as I see it.

Only looking at the most common amount of hits in 37, we have 24/13....as I am sure you know.

24 hit, 13 don't.

There is nothing to say how that will materialize,  so there could be 24 unique numbers then the last 13 are all repeats.

I've seen 20 uniques....and many times I go up to a table and there are no repeats on the marquee (17)

But....

that's 24/13. You can see 27/10 and all 27 could be unique, but these are much rarer events.

You would have to factor in 3 sessions.

of course, this is WCS

amk

Thanks Turner,

Very interesting estimation.

Only 3 sessions.

Hope there will be some more estimations.

Sounds 2 good 2 be true.

amk

Here is the actual test data:

"A 30 million single zero RNG test, 361 086 games (whenever a number repeats, a new session is started)"

2    9799
3    19199
4    26712
5    33099
6    36817
7    38117
8    37424
9    34613
10    30241
11    25616
12    20579
13    15855
14    11481
15    8103
16    5429
17    3428
18    2057
19    1187
20    665
21    372
22    165
23    79
24    35
25    10
26    3
27    0
28    1

MEAN        8.308740854
MEDIAN        8

Max number of spins before a repeat is 28
.


Looking at the data now I think the max number of session could be closer to 15 or so.

Turner


Loek2000

Hello amk,

I have tested and played this for a year or so. I thought I've found a real good system with it. Made a lot of money even on rng. I've tried several ways. I ended with playing 1,2,3,4,5,6,7,8 at random, following the rabbit (last fallen number). Even played 3 random plays all at once. Progression was easy. Never up in the string. So from 1 to 8 always the same amount. Win? stay put at one unit. Loss? win or lose +1 until last balance bankroll was +1.

But eventually I lost big time. As an answer to your question, I've had lost my strings 12 times in a row. And with 1 or 2 wins in 17 to 21 strings! So with going up +1 per string you lose a lot real quick. But I still like the system must be able to improve it. Would be nice to explore with others.

Suggestion:

1. Play the fallen numbers. We hope for a repeat.
2. Each loss will result in a extra number to play next round. So 1 number,loss play 2 numbers, loss play 3 numbers etc up to 8 numbers.
3. There is a win on any level except with the last one. Then you play even.
4. Lose the string? Wait for one new number start next string of 8 numbers starting with one number.
5. Progression is +1 per string. So string 1 has 1 unit. String 9 has 9 units. etc.
6. Win somewhere in the string start a new one.
7. Play this way until old bankroll balance is back +1 unit.
9. Start back with 1 unit with string 1.
10. Bankroll? Loss limit? Win limit? (Suggestions?)

He, amk, thanks heaps for posting and the results of the 30 mil spins. Could you do me the favor and tell us how many times there was a repeat on the first number? I have had a lot of them too. What feels amazing everytime it happens.  :D

Thanks

Loek2000


amk

Hello Loek!

Thanks for posting your ideas. I am just reading them now and will have to think them through.

There were 9799 hits on the first number spun. "2  9799" means a repeat on the second spin. First a number must be spun, this is spin #1 on spin #2 the number can repeat. So there were 9799 times that the first number spun repeated directly

Example:

35, 35

Loek2000

Ok. That's a different approve all together. My second test ended just now in a loss. -84 units.

-