Some ideas on table layout betting. (Subject modified)

[nottophammer]

yes Chris i see that quote

[Chris555p]

@Ddarko - Yes I see what u mean

[Chris555p]

@Nottophammer - Glad u saw it.

[falkor]

This is using Random.org data... this page has 43 wins vs. 3 losses. However, I still believe it may be possible to recover those 3 losses - perhaps by switching to the closed DSs - or by just remaining in watch mode and looking for a desirable event to occur.

Besides that the system mechanics are looking very clean - nothing in both sets of data are breaking the bank of 500 even once!

[RouletteGhost]

Looking forward to the rules/strategy.......

[atlantis]

This is using Random.org data... this page has 43 wins vs. 3 losses. However, I still believe it may be possible to recover those 3 losses - perhaps by switching to the closed DSs - or by just remaining in watch mode and looking for a desirable event to occur.

Besides that the system mechanics are looking very clean - nothing in both sets of data are breaking the bank of 500 even once!

I don't understand the table you showed.
Falkor - Just to be clear: r u saying that those 3 losses would have wiped out the bankroll? or that the bankroll can handle the three losses encountered?

A.

[falkor]

They just lose 9 units each

0 1 2 3 0 lose means that the first spin is the observation spin (which DS opens first), 1 means there is 1 open DS, 2 means 2 open DSs, 3 means open DSs. It then goes back to zero because when we lost 3 DSs it meant that 4 had opened. We don't bet at all on 4+ open, and then 1 of the DSs closed at spin 5 with 3 open, so we end set there (or go into watch mode).

The progression is 1,1,2
1 DS x 1 = 1
2 DS x 1 = 2
3 DS x 2 = 6
Total units lost = 9

[atlantis]

I see. Thanks.

A.

[SamNL]

Any updates on this?

[falkor]

I'm sure it wins more than it loses, but I'm finding it too difficult to code the progressions. Does anyone know a formula that can dictate how many units to wager based on 1,2 or 3 simultaneous DSs and the BR?

So if:
BR = -65
Open = 3
Then how many units to bet on each DS? It would be an equation of inequality, but we should be able to round up the result to give an integer for betting.

The other method I have for coding it is too tedious to complete by New Years Day.

[klw]

I thought you were going to make us all millionaires Falkor lol Oh well !

I've done my own limited testing on this and it may be slightly different to what falkor is doing but hopefully the data will be explained in a more helpful way as I find it very difficult to decipher some of falkor's tests and I simply don't have the time or energy to wade through it all ( no disrespect to you Falkor as I can see the effort you have put into this )

I've only managed a few thousand spins so far by my pen and paper method , I know it's not enough for the million + spins guys but it gives me an idea of what to look for. ( live spins )

I'm looking for a second hit on a double street to close that street regardless of whether its a repeat number or not, so 2nd hit and it is closed.

I wait for the first double street to hit and then look at the intervals between each of the remaining 5 unclosed double streets to close ( get a second hit )

In all my tests so far there is always at least 1 double street that closes within 3 spins of the last double street to close, in most cases there is always 1 double street that closes within 2 spins of a double street closing but those few that go to a third spin can be the killers ( or not ) to the system.

It is too difficult in my opinion to calculate when we will get the 2/3 spin interval between double streets closing , certainly a long interval lets say between double streets 3 and 4 closing does lead to a small advantage that DS 5 may have our target 2/3 spin interval but this is not always the case , so the alternative may be to just attack the open double streets ( and any that subsequently open ) for our 2/3 spin target only,after each double street closes. This will involve a progression as remember the 2/3 spin target interval could be between double street 5 and 6 closing by which time the sums involved could be big.

These are an example of intervals for the six double streets to close :-

DS1     5
DS2     5
DS3     4
DS4     1
DS5     19
DS6     x          ( did not close in my 37 spin session )

So in the above we would have to wait until DS4 closes to hit our target. Each attack after a double street closes will have a differing amount of open double streets to bet on,so as falkor stated in his last post we need a progression calculator or a very quick maths mind to calculate bets as we go along.

I'm not sure after all this work that this system is for me in this format. I have also looked at trying to capture repeat numbers as part of the second hit of a double street and was having some success until the variance caught up and also trying to cross reference attacks with sweet spots for a certain double street to hit as I mentioned in the early part of the thread. An example being the 4th double street to close, I would be looking at spins 13 - 17 as a sweet spot. Needs more work as usual.

Would love to hear other people's opinions on this, I hope it generates more ideas.

Apologies if this steps on your toes falkor , just throwing out some work I've done on the subject even if it's already what you've covered.

Merry Christmas to all.

[RouletteGhost]

Falkors perception of warriors system performs very well going by falkors attachments

Looking forward to  reading falkors system.

[falkor]

All ideas/variations are in need of extended discussions from as wide an audience as possible, hence this topic, which I never intended to hijack. The main thing is the progressions calculator, otherwise I think there is too much to remember.

[klw]

Falkors perception of warriors system performs very well going by falkors attachments

Looking forward to  reading falkors system.

How do we know what Warrior's system is ? I have never seen it fully explained anywhere.

[vladir]

I'm sure it wins more than it loses, but I'm finding it too difficult to code the progressions. Does anyone know a formula that can dictate how many units to wager based on 1,2 or 3 simultaneous DSs and the BR?

So if:
BR = -65
Open = 3
Then how many units to bet on each DS? It would be an equation of inequality, but we should be able to round up the result to give an integer for betting.

The other method I have for coding it is too tedious to complete by New Years Day.

I hope I understood your request correctly. If I did, it's quite simple.

First of let's define some things:

DD - Draw down from the previous highest bankroll ( I assume this is the -65 you speak of)
NB - Number of streets to bet - in this case it's 3
X - The amount to bet in each street.

The formula is this:

6*X - DD - NB*X >=1

Solving to X, we will get:

6*X - DD - NB*X >=1 <==>
X(6-NB)>=1+DD <==>
X >= (1+DD)/(6-NB)


In this particular case, we have: X>= (1+65)/(6-3) <==> X >=22

So we would bet 22 in each street, to come up with a profit of 1 if we have a hit in one of our 3 streets. Hope I understood your problem correctly and to have been clear. If not, just ask.