9 boxes method (pdf attached)

[edved77]

A system I've been toying with - I've attached a pdf for easier reading - it doesnt display quite right below...

9 boxes

This system splits the cloth into 9 boxes as follows:

Box #1 â€" 1, 4, 7, 10
Box #2 â€" 2, 5, 8, 11
Box #3 â€" 3, 6, 9, 12
Box #4 â€" 13, 16, 19, 22
Box #5 â€" 14, 17, 20, 23
Box #6 â€" 15, 18, 21, 24
Box #7 â€" 25, 28, 31, 34
Box #8 â€" 26, 29, 32, 35
Box #9 â€" 27, 30, 33, 36

I use the following scorecard in Excel and it auto counts the spins:
   3   6   9   12   15   18   21   24   27   30   33   36
   2   5   8   11   14   17   20   23   26   29   32   35
   1   4   7   10   13   16   19   22   25   28   31   34
                                               
SPINS                                               
0                                               

So the top part is obviously the cloth and the bottom part is where I mark a ‘1’ every time a particular box is hit â€" within a 37 spin cycle.  But we never get that far into a round as we win before spin 37.

Trigger â€" when a box has 4 hits it becomes active and you should bet on it â€" two splits, flat bet  the four numbers or bet the dozen they are in. You could start with a parachute of some sort then focus in on the box.

Obviously as more boxes are hit 4 times you bet them too. So the scenario we don’t want is loads of boxes being triggered.

A win occurs when you get a fifth hit on one of the nine boxes.

The rationale behind this is you are highly unlikely to get the following spread of hits in 36 spins:

   3   6   9   12   15   18   21   24   27   30   33   36
   2   5   8   11   14   17   20   23   26   29   32   35
   1   4   7   10   13   16   19   22   25   28   31   34
   1   1   1   1   1   1   1   1   1   1   1   1
SPINS   1   1   1   1   1   1   1   1   1   1   1   1
36   1   1   1   1   1   1   1   1   1   1   1   1

Testing

Using actuals from a file called Dublinbet 4k â€" I got it from VLS roulette forum if I remember correctly - I have tested 361 rounds of 37 spins (13k spins).

For what it’s worth I did the averages in Excel on the 361 tests and:

Average triggers (4 hits) = 26 spins
Average hit/win = 29 spins

Of the tests, the perfect hit pattern above didn’t occur - so ‘theoretically’ all 361 were winners.

I haven’t used real money yet, I don’t have a big enough bank roll, just been using Excel and fun money to practice.

If someone wants to post me some actual numbers, I am happy to run through an example game.

Edved77

[ozon]

When  You  hit/win  split  ,  reset the   numbers ,  starting  new searching  the  triggers   with  new  numbers?

[edved77]

The 361 tests I refer to were done in Excel with rounds of 37 spins.

In reality, as soon as you get your win (a fifth hit on one box), you don't have to see it through to spin 37, just restart tracking from scratch - you can go back a few numbers on the history board to speed things up. Either way doesnt seem to change the pattern of outcome.

I hope that's clear? Send me some live numbers and I can run through a test and we can see what happens.

[ozon]

I know it works in short time, but as we find that some triggers can collapse into sleep, we lose previously earned profits.
I played 5 sessions Yours way in Dublinbet I finished  +50 units.

[JimmieB]

Hi edved77,

Thanks for sharing, like your avatar

This seems really straight forward to play, for myself anyway, and therefore, I like it, it's funny how certain ways suit players, and not others...I did a quick test this morning, just a couple of games, lot more testing required. The second game was straight forward, got my first box to bet after spin 18, and it won on spin 20, didn't have to bet more than the 1 box, my first game was quite different, first box to bet after spin 21, won on spin 29, however, I was betting 4 boxes on the final spin, using a progression (divisor 1/35, max bet was 2 units on 16 numbers) this finished in the plus (+4), if I hadn't used the progression it would have finished -20. Another way to play this could be to just bet the first box to hit 4 times until it gets a fifth hit, or, possibly no more than 2, not sure, I'm just putting it out there??

Regarding tracking, just a thought, once a game is won/finished, you could simply go through your first 10-15 numbers, and score of the relevant marks on your table, should be pretty straightforward to do if using old fashioned pen & paper , meaning you should be betting again fairly quickly, or, as you say you can use the board.

Jim

[ozon]

I  wait  only  for  one  hit ,then reset numbers and  starting new  session  with  new  numbers.

[edved77]

Thanks Jim and Ozon, some useful help and info there.

How does the 1/35 divisor work?

What methods do you two prefer to use?

[JimmieB]

Hi edved,

Here is link to the divisor method link:://:.rouletteforum.cc/index.php?topic=13574.0

I'll try and summarise how I use it, I think it's the correct way ...take the odds of 1/35 for your bets if betting individual numbers, now, 1 into 35 is less than 1, therefore, your first bet is 1 unit per number, using your box method, this is a total of 4 units if betting the 1 box, ok, we lose, we now add 4 units to the 1/35, making it 5/35, 5 into 35 is still less than 1, again 1 unit on each number, say another box it to be bet, meaning we are betting a total of 8 units, this looses, and the 8 to the 5, now making it 13/35, again 13/35 is still one, another box comes into play, we are now betting 12 units, this looses, we are now 25/35, again still 1, bet the 3 boxes again as none have come into play, this looses, it's now 37/35, now 37 goes into 35 more than 1, therefore, we increase our bet to 2 units per number, betting 3 boxes again, this is now 24 units, making 61/35, this greater than 1, although, less than 2, still betting 2 units on the numbers, let’s say another box is to be bet making it 4, this is now 32 units to bet, this looses, we now have 93/35, greater than2 less that 3, bet is now 3 units per number, 4 boxes this is 48 units per number, ok, we now get a win of 60 units subtract the 60 from the 93, this gives us 33/35 for our new game, as this is less than 1 we start of betting 1 units per number again, however, you will move to 2 units in the next bet as this would be 37/35, which  is greater than 1. Any time we get in the plus we reset the divisor to 1/35. I understand there are other elements to it regarding a safety break if bets are getting 2 high, however, I’ve not quite got my head round this yet....


1/35 loose 4, next bet 5/35 (1 unit per number)
5/35 loose 4, next bet 9/35 (1 unit per number)
9/35 loose 4, next bet 13/35 (1 unit per number), now betting 2 boxes
13/35 loose 8, next bet 21/35 (1 unit per number), now betting 3 boxes
21/35 loose 12....and so

Like any progression it can get scary, however, if you have a good system and BR, I'm led to believe this can pull through.

Regarding what I play, I have to be honest, I jump from system to system instead of sticking to several tried and tested methods, my bad. There are some excellent posters on the forum with great ideas, and I’m sure you’ll find one to suit your play. Check out the members who have regularly posted a lot over the years, and you’ll come across some nuggets. I’m currently playing a version of Mr J’s 2’s company and a couple of methods from member Dane. I’ve also been looking at a topic called 8 is great, search the forum and you’ll find it.

I hope this helps, any more questions, feel free to ask either on the thread, or, via PM.

Jim

[thelaw]

The biggest asset of the Divisor Method is that if it gets too high, then you can just add equal units to the divisor and keep going.

Check the link in the last post for details.

I'm surprised more people don't use it regularly.

[JimmieB]

Hi the law,

This is where I get slightly lost with divisor....

Ok, let's say I'm sitting at 215/35, meaning my next bet would be 7, and, I want to bring this down, would all I have to do, for example, is add, say, 60 to both numbers, now giving me 275/95, meaning my bet would now be 3?

Jim

[shuttle]

Hi edved77

I would appreciate if you could play this method with the attached spins.

Thanks

[thelaw]

Hi the law,

This is where I get slightly lost with divisor....

Ok, let's say I'm sitting at 215/35, meaning my next bet would be 7, and, I want to bring this down, would all I have to do, for example, is add, say, 60 to both numbers, now giving me 275/95, meaning my bet would now be 3?

Jim

ok, so here is my understanding :

10/10 (goal in units/divisor)

so our bet would be 1 unit...

Now, let's say that that we have a ton of losses and we are at 30/8 and we don't want to exceed 5 unit bet (which would happen if we lost again and resulted in 34/8), so we add 3 units to each side and get (33/11).

We now need to win 11 units instead of 8. The only problem with this method is eventually it becomes Martingale if we don't add more wins needed to continue.

In theory, you could go on forever. This is particularly effective if you are expecting a handful of wins.

***Please note that I always round up to the next largest number instead of using decimals***

Does that make sense?

[edved77]

Hi edved77

I would appreciate if you could play this method with the attached spins.

Thanks

Hello - I've attached your excel sheet with the results -

- I've marked the triggers (T) and the wins (W)
- you bet every box that gets 4 hits until one of them gets a fifth hit
- in the attached, after I win I just start from scratch, rather than track back
- Ignore zeros

So these spins worked out nicely, no problems. 

The only thing I haven't included is what to bet.  I'm still not 100% the best way to do this.  Some good ideas in this thread about the 1/35 divisor method.  Or you could bet the two splits in each box.

Does the attached help?

[edved77]

Hi edved,

Here is link to the divisor method link:://:.rouletteforum.cc/index.php?topic=13574.0

I'll try and summarise how I use it, I think it's the correct way ...take the odds of 1/35 for your bets if betting individual numbers, now, 1 into 35 is less than 1, therefore, your first bet is 1 unit per number, using your box method, this is a total of 4 units if betting the 1 box, ok, we lose, we now add 4 units to the 1/35, making it 5/35, 5 into 35 is still less than 1, again 1 unit on each number, say another box it to be bet, meaning we are betting a total of 8 units, this looses, and the 8 to the 5, now making it 13/35, again 13/35 is still one, another box comes into play, we are now betting 12 units, this looses, we are now 25/35, again still 1, bet the 3 boxes again as none have come into play, this looses, it's now 37/35, now 37 goes into 35 more than 1, therefore, we increase our bet to 2 units per number, betting 3 boxes again, this is now 24 units, making 61/35, this greater than 1, although, less than 2, still betting 2 units on the numbers, let’s say another box is to be bet making it 4, this is now 32 units to bet, this looses, we now have 93/35, greater than2 less that 3, bet is now 3 units per number, 4 boxes this is 48 units per number, ok, we now get a win of 60 units subtract the 60 from the 93, this gives us 33/35 for our new game, as this is less than 1 we start of betting 1 units per number again, however, you will move to 2 units in the next bet as this would be 37/35, which  is greater than 1. Any time we get in the plus we reset the divisor to 1/35. I understand there are other elements to it regarding a safety break if bets are getting 2 high, however, I’ve not quite got my head round this yet....


1/35 loose 4, next bet 5/35 (1 unit per number)
5/35 loose 4, next bet 9/35 (1 unit per number)
9/35 loose 4, next bet 13/35 (1 unit per number), now betting 2 boxes
13/35 loose 8, next bet 21/35 (1 unit per number), now betting 3 boxes
21/35 loose 12....and so

Like any progression it can get scary, however, if you have a good system and BR, I'm led to believe this can pull through.

Regarding what I play, I have to be honest, I jump from system to system instead of sticking to several tried and tested methods, my bad. There are some excellent posters on the forum with great ideas, and I’m sure you’ll find one to suit your play. Check out the members who have regularly posted a lot over the years, and you’ll come across some nuggets. I’m currently playing a version of Mr J’s 2’s company and a couple of methods from member Dane. I’ve also been looking at a topic called 8 is great, search the forum and you’ll find it.

I hope this helps, any more questions, feel free to ask either on the thread, or, via PM.

Jim

Hi Jim,

Thanks for taking the time to provide that detailed explanation! This is very interesting and I will certainly be looking into this now especially with the 9 boxes method.

Will also check out the systems you mention by other members.

Edved

[JimmieB]

ok, so here is my understanding :

10/10 (goal in units/divisor)

so our bet would be 1 unit...

Now, let's say that that we have a ton of losses and we are at 30/8 and we don't want to exceed 5 unit bet (which would happen if we lost again and resulted in 34/8), so we add 3 units to each side and get (33/11).

We now need to win 11 units instead of 8. The only problem with this method is eventually it becomes Martingale if we don't add more wins needed to continue.

In theory, you could go on forever. This is particularly effective if you are expecting a handful of wins.

***Please note that I always round up to the next largest number instead of using decimals***

Does that make sense?

Ah, ok, the way you’ve described it, is how I would use the divisor for EC bets, again, I wasn’t sure how the safety break worked in this scenario either, let me make sure I’ve got this right, I’ll start off with 10/10 betting EC’s, I see you round up as soon you get a decimal i.e. 1.1 becomes 2, I’m aware you can play it where you don’t round up until th decimal is .5 i.e. 1.1 remains at 1, 1.6 would be 2....

10/10, bet 1, lose -1, BR -1
11/10, bet 2, lose -2, BR -3 (now we add 2 to the 11)
13/10, bet 2, win +2, BR -1 (now we take the 2 of the 13, and reduce the 10 to 9 as its a x1 payout?)
11/9, again still 2, lose -2, BR -3
13/9, bet 2, lose -2, BR -5
15/9, bet 2, lose -2, BR -7
17/9, bet 2, lose -2, BR -9
19/9, now bet 3, lose -3, BR -12
22/9, bet 3, win +3, BR -9
19/8, bet 3, lose -3, BR -12
22/8, bet 3, lose -3, BR -15
25/8, now bet 4, lose -4, BR -19
29/8, ok, if we lose this bet would now become 5, and say this is to high, increase both sides by, say 4, I’ve now got 33/12, bet would be 3...
33/12, bet 3, win +3, BR -16
29/11, bet 3, win +3, BR-13
26/10, bet 3, win +3, BR -10
..and so on...

The above example is quite extreme, I would have probably have quit and started over when I got to -15, however, I’m hoping this means I now have an understanding of the safety break!!! Here is a link to playing the divisor for EC’s in an almost similar way link:://:.rouletteforum.cc/index.php?topic=3731.0

Regarding the way I’ve used the divisor for the box method would you use it any differently, or, could you maybe start with something like, say 35/105, and if I get a win at some point 105 would reduce to 70, anytime I’m in a plus balance, simply start over?

@edved, sorry for kind of high jacking your thread.....you mentioned betting the 4 numbers with splits, this could also be used with the divisor, in this case starting of at 1/17, after loss it would be 3/17, etc. not as much BR required, however, returns are less.

As thelaw quite rightly mentioned, I don't know why more people don't look at this as a progression....

Jim