Legendary Repeater

[ignatus]

This is a progressive bet, 2-14 streets bet.

Trigger: Bet every columnstreet within each dozen that hits (2 splits), until hit. Then begin anew with the last columnstreet hit (2 splits)

If zero hits, there are 2 options

1. Ignore it, take a small loss
2. Double bets

progression

2  streets 1u
4  streets 1u
6  streets 1u
8  streets 2u
10 streets 4u
12 streets 12u (x*3)
14 streets 48u (x*4)

I have not reached 14 splits bet so far, (12 streets bet was the highest bet).

Fist test was played with 5u bets

[ignatus]

OK, so i had two losses. 2/4 games won.....nothing is certain when it comes to roulette, but i think with a proper moneymanagement this could be a playable strategy.

I have always said greed will kill you ---Therefore keep a set wingoal and QUIT when you reached that wingoal; my moneymanagement plan:

1u bets---wingoal 100u
5u bets---wingoal 500u.....and so on.

divide the bankroll into several minigames....i think it would be reasonalble to have money to cover up til 12 streets;

2  splits 1u
4  splits 1u
6  splits 1u
8  splits 2u
10 splits 4u
12 splits 12u (x*3)

What bankroll would be required? = 2+4+6+16+40+144=212u

so 212u is needed to play this one (if i calculated it right?)....

anyway, Game 4, (played with 1u bets)

[Chrisbis]

Very confusing system method description.
You mentioned :-
Column
Dozen
Streets
Splits.
Without an articulated example I have no idea what the bet is.

[ignatus]

Very confusing system method description.
You mentioned :-
Column
Dozen
Streets
Splits.
Without an articulated example I have no idea what the bet is.

it should be SPLITS, not STREETS. :s SORRY!

progression

2  splits 1u
4  splits 1u
6  splits 1u
8  splits 2u
10 splits 4u
12 splits 12u (x*3)
14 splits 48u (x*4)

OK, for an example number 1 hits;--
then columnstreet 1-10 would be bet; (split 1-4 & split 7-10)

next number 14 hits; (keep the first bet) and then
columnstreet 14-23 would be bet: (split 14-17 & split 20-23)

...and so on...

[Chrisbis]

Got it now.

Edit.
And just to qualify something. ..
your progression is thus:-

progression

2  splits 1u (on each)
4  splits 1u (on each)
6  splits 1u (on each)
8  splits 2u (on each)
10 splits 4u (on each)
12 splits 12u (x*3) (on each)
14 splits 48u (x*4) (on each)

This correct?

[ignatus]

Got it now.

Edit.
And just to qualify something. ..
your progression is thus:-

progression

2  splits 1u (on each)
4  splits 1u (on each)
6  splits 1u (on each)
8  splits 2u (on each)
10 splits 4u (on each)
12 splits 12u (x*3) (on each)
14 splits 48u (x*4) (on each)

This correct?

Yes, that's right.