Vaddis Holy Grail

[nottophammer]

Maybe the trick is to follow the wheel in different ways rather than dropping the last outcome and playing the newest?
Anyway the 24/8 thing could it be 8 repeats in 24 spins likewise 12/4 4 repeats in 12 spins?
36/12
12 repeats in 36 spins so every 3 spins there should be a repeat on average?
Don’t know , confused


Jay
Your sentence underlined. 24 spins, 8 repeats.
Now, the roulette tracker thread. Ayk; did the notto tracker of his own back. But if you watched multiple sets of 60 spins, you would eventually see in groups of 10 spins, where repeats hit.
You would find that the average would be 1-3-5-7 and 30.
So, 30 spins would have on average 9 spins.
What if you played a set of numbers for a specific number of spins?
Again, underlined what you suggest.
Now if the 1st 10 has 1 repeat, providing it hit on spin 8 or before you would have Vaddi. But if hits after, say hits spin 10, you’d be minus.
What would you do next, knowing there’s potentially 3 repeats coming in next 10 spins? And the next 10 spins another 5 repeats.
So, try this. Use unit of 1 on the 1st 10 spins; you’ll need a repeat by spin 7, 8 to breakeven. Now if you get the 1st 10 spins, no repeat, you bet the next 10 spins, where hopefully you get 3 repeats at units of 2. If the repeat hits and is from 1st 10; bet the 2 units on the repeat number, will now have 3 units. This might be a Turbo hot number! Carry on till you have bet 20 spins. If profit is gained stop and re-set. If you have to carry on; now use 4 units. Any number that repeats add the 4 units, again this number could be a Turbo hot number!!
Alarm bells should be ringing, it’s using a Marty.
Now go to R-sim and try, not MPR as you’ll get a freeze or extra numbers sometimes.

[nottophammer]

Using unit of 5

[nottophammer]

See repeat on 10 and 4 repeats in 20 spins. Average

The 1-3-5-7and 30 shows on airball rng live, General gormless supplied 30'330 live spins and that average shows.

[nottophammer]

3 repeats, is #18 going to get hotter? who knows, perhaps ask Turbo or get 80'000 phone

[jay]

Notto thanks for all that info much appreciated and I think your methodology has much similarities with Vaddis teachings with a slight difference as he didn’t advocate using progression.

[jay]

And another important thing is not to solely rely on repeaters on their own in order to create a balanced strategy.
I mean if you do enough testing I m sure one can come up with a strategy based on what I have written.

[jay]

vaddis holy grail what a croc of shit
so easy to teach but a 1,000 adults cant crack  it ...you know why ?? because its BULLSHIT

I disagree with your analogy of shit in a croc, lol
That’s the case until you discover it
Vaddi was a genius

[nottophammer]

Are there really 37 outcomes. No one is in there reading some great info.

[jay]

copying things together...

Ok ...

General guidelines and more tips:
========================

Let's assume that 10 is the maximum of numbers that you will bet on.

Stage 1) Begin single sequence to X numbers (where X represents the maximum numbers that you will bet on)

You enter casino and the number ...

13 has just dropped. Place your unit chip on it. (1 unit in total)

30 drops instead. Now place a unit on 13 and 30 (2 units total)

17 drops instead. Now place a unit on 13, 30, and 17 (3 units total)

13 drops. You win and make a profit.

Because you are in profit and because you have not reached your X number limit of 10, you will continue the process all over again, by placing a unit chip on your last dropped number, which is 13. You will continue this process of betting on every number that drops.

Now, as I've said, "The X number is important" and it's not 10 .

As another clue, I suggest that you create a stepping sequence (like above) wherein if you hit the last number in that sequence, you will break even.

If you use 10, you will have 10 numbers on the table if you reach your 10-number limit. And, if the ball lands on that last set of 10, you'll make a small loss and the funny thing is that 10 numbers doesn't improve accuracy over the lower, perfect X number.

Stage 2)

If you do not make a hit within the first stage, that means that you have bet X times on X numbers. That is 10 spins, 10 numbers, no hits.

So, you might have something like this:

36  (The last number dropped)
---
19  (part of your 10-number X group)
14  (part of your 10-number X group)
25  (part of your 10-number X group)
17  (part of your 10-number X group)
31  (part of your 10-number X group)
13  (part of your 10-number X group)
0    (part of your 10-number X group)
3    (part of your 10-number X group)
22  (part of your 10-number X group)
2   (part of your 10-number X group)

At this point, your set of 10 didn't come up. And the last number that landed is 36.

So, the idea is to bet on every number that the wheel spits out, but you want to always place a limit on how much you place on the table. Betting on 10 numbers is a waste, so find that magic X number.

From this point onward you will bet on 10 numbers (or the X number when you discover it).

But, this is what you do:

Knock the #2 off the bottom so that your new 10-set bet selection now becomes ...

36  (part of your new 10-number X group)
19  (part of your new 10-number X group)
14  (part of your new 10-number X group)
25  (part of your new 10-number X group)
17  (part of your new 10-number X group)
31  (part of your new 10-number X group)
13  (part of your new 10-number X group)
0    (part of your new 10-number X group)
3    (part of your new 10-number X group)
22  (part of your new 10-number X group)

If the next spin hits one of your X numbers, then great! But, you must check to see if you have increased your bankroll above what you started with at Stage 1.

If you are in profit above where your bankroll was when you started with at Stage 1, then go back to Stage 1 and place a unit chip on the last number that made you win.

If you are not in profit at this point in Stage 2, then continue playing your X-number blocks (in this example: 10) by knocking off the bottom number and adding the number that landed.

So, let's say #31 landed (you win) and your bankroll is below the level when you first placed your first single unit at Stage 1. In this case, ...

... you'll only bet on 9 numbers. Why? You're following the pattern and spins of the wheel. The wheel is telling you that you're accurate so you need to lay out less on the table:

You're thinking in terms of number of numbers and number of spins.

So, we now have ...

31  (The last number dropped)
---
36  (part of your new 10-number X group)
19  (part of your new 10-number X group)
14  (part of your new 10-number X group)
25  (part of your new 10-number X group)
17  (part of your new 10-number X group)
31  (part of your new 10-number X group)
13  (part of your new 10-number X group)
0    (part of your new 10-number X group)
3    (part of your new 10-number X group)
22  (part of your new 10-number X group)

Looking at the 10 last spins, you now only need to bet on 9 by knocking off #22 and adding #31. But, of course, #31 is slap bang in the middle of your X number set (it's not at the bottom, where you would knock it off).

Of course, if you discover the X number, sometimes you end up betting on lower numbers than 9, while making hits.

Once your bankroll is in profit above what you started with at the first placing of your first-stage single chip, then start the first-stage single chip process all over again.

Another aspect you can observe and experiment with, is multiple 37-spin cycles, starting from Stage 1 + Stage 2, as described in this post.

All the best.

- Vaddi

P.S.: Should have added the following:

If you break even when one of your numbers hit, then go back and start Stage 1 all over again.

Which means, if at any stage ... let's say your bankroll was $1200 and it went down, and then you get a hit that takes you back to $1200, you would re-start Stage 1 and bet on the number that just hit.

[nottophammer]

Jay

So, why did pairings appear, when the above is all you need.

Jay, when we get say 16 non-hits and are dropping the last all the time, How you going to get back to starting bank-roll? If 16 have hit, there'd be no win and -100.

So, now the riddle of pairings would be added. If 8 spins has lost, drop the 1st and add the pairings, 8 #'s has now become 16 #'s.

It looks like BIGMONEY is right. Unless you can decifer the riddles.

[jay]

Come on guys ...

You're sitting on a goldmine!

What's the tiny 1 percent missing element?

I want to see how good the roulette veterans are on this forum.

I want to see the deep-thinking roulette players who have been playing for years.

What's missing guys?

The system wins, but how can you guarantee it?

- Vaddi

Pairings are there to guarantee winning as we all know repeaters will let you down at some point.

[Proofreaders2000]

Hey guys

I want to take a shot at Vaddi (again)...

-----*Newest Two High outcomes vs Two Low Outcomes w/Zeros*-----

Note the newest outcome, is it High or Low?

Bet the newest two High outcomes if the last decision is High and
vice-versa if Low.  Bet also the next higher and Lower numbers respectively.

Repeat steps with each outcome.

Stop when in profit.

Example: 23, 15, 9, 31 (newest spin-value)

Bet 22, 23, 24 & 30, 31, 32, 0:    1.) 2(x)-7

Bet 8, 9, 10 & 1, 2, 3, 0....

Bankroll suggestion: 140 total units

[Proofreaders2000]

Paper Test: BetPhoenix American Wheel-
Saturday, May 1,2021 @ 7:21am CDT USA

...30, 16, 12, 17, 00, 20 (newest spin-value)

Bet 29, 30, 31 & 19, 20, 21, 0, 00:    1.) 23(x)-8

Bet 19, 20, 21 & 22, 23, 24, 0, 00:    2.) 26(x)-8

Bet 22, 23, 24 & 25, 26, 27, 0, 00:    3.) 27(win)+28
----------------------------------------------------------------------
+12
==============================
Paper Test: BetPhoenix European Wheel-
Saturday, May 1,2021 @ 7:28am CDT USA

...5, 9, 36, 24, 23, 26 (newest spin-value)

Bet 22, 23, 24 & 25, 26, 27, 0:    1.) 4(x)-7

Bet 8, 9, 10 & 3, 4, 5, 0:               2.) 17(x)-7

Bet 3, 4, 5 & 16, 17, 18, 0:           3.) 14(x)-7

Bet 16, 17, 18 & 13, 14, 15, 0:     4.) 35(x)-7

Bet 25, 26, 27 & 34, 35, 36, 0:     5.) 20(x)-7

Bet 34, 35, 36 & 19, 20, 21, 0:     6.) 1(x)-7

Bet 13, 14, 15 & 36, 1, 2, 0:         7.) 36(win)+29

Bet 19, 20, 21 & 35, 36, 1, 0:       8.) 0(win)+29
---------------------------------------------------------------------
+16
==============================
Paper Test: BetPhoenix American Wheel-
Saturday, May 1,2021 @ 7:58am CDT USA

...34, 29, 18, 8 (newest spin-value)

Bet 33, 34, 35 & 28, 29, 30, 0, 00:    1.) 8(win)+28
==============================
Paper Test: BetPhoenix European Wheel-
Saturday, May 1,2021 @ 8:03am CDT USA

...34, 6, 8, 0, 7, 35, 4, 7 (newest spin-value)

Bet 3, 4, 5 & 6, 7, 8, 0:    1.) 10(x)-7

Bet 6, 7, 8 & 9, 10, 11, 0:    2.) 11(win)+29
-------------------------------------------------------------
+22

[Proofreaders2000]

Paper Test: BetPhoenix American Wheel-
Saturday, May 1,2021 @ 12:07pm CDT USA

...20, 7, 29, 16 (newest spin-value)

Bet 6, 7, 8 & 15, 16, 17, 0, 00:    1.) 8(win)+28
==============================
Paper Test: BetPhoenix European Wheel-
Saturday, May 1,2021 @ 12:08pm CDT USA

...2, 29, 33, 25, 20, 20, 32, 4 (newest spin-value)

Bet 1, 2, 3 & 3, 4, 5, 0:    1.) 7(x)-7

Bet 3, 4, 5 & 6, 7, 8, 0:    2.) 18(x)-7

Bet 6, 7, 8 & 17, 18, 19, 0:    3.) 31(x)-7

Bet 31, 32, 33 & 30, 31, 32, 0:    4.) 4(x)-7

Bet 17, 18, 19 & 3, 4, 5, 0:           5.) 29(x)-7

Bet 30, 31, 32 & 28, 29, 30:        6.) 30(win)+65
-----------------------------------------------------------------
+30

[carvigno]

I'm not interested in this system but here you have my 2 cents.

Magic number as you say Jay is 8 coz 1 + 2 + 3 + 4 + 5 + 6 +7 + 8 = 36

If you fail the 8 bets you'll be -36 and you start over again with a new set of numbers (1+2+3,etc) if you have a hit in step 3 then you win 30 chips.

You play seeking a repeat inside this ladder of 8 steps.

Just having a boring day so that's my guess.
If this was discussed beforehand have my apologizes. I havent read the thread.