Vaddis Holy Grail

[Bigbroben]

For sure,

there are 2 aspects to decide, how many nrs to play, and which ones to play.
The grinding recovery applies to how many.

About which ones, have a look at the following datas.   The numbers in the pair are coming out this way. ( Mako, RCR, you know?)
Take pair 11, in this example.  Say a 37pair, 11/26.
Sequence: 1,1,1,1,2,2,1,2,1,1,1,1,4,2,2,2,1,5,1,5,2,4,1.
So the nr out in the pair, if 11 was the first one to come.
11,26,11,26,11,11,26,26,11,26,26,11,26,11,26,11,11,11,11,26,26,11,11,26,11,11,11,11,11,...

Whereas pair 18 would have been: 1,1,9,1,1,3,1,2,...
So: 18,19,18,18,18,18,18,18,18,18,18,18,...



So sequences with smaller runs and more switching (pair 8 ), will show profit if playing switch.
Pair 11 totalizes 23W/21L.  Pair 14: 23/17
Now this doesn't tell how many spins it takes between hits, so we don't know how much every hit costs.

When adding the other nr on a loss, though, so at 2nrs, one is certain to hit it next time.  Could it be then the time to play a run?  Stay at 2nrs until next switch?  Or the nr that's running only?  Must be thought over.
Nevertheless, these reflexions are intriguing.

It is less of a big deal also when attempting to recover with nr density, because anyway at some point many pairs will be played with 2 nrs.
Comes another question: always keep one of the 2nrs or also delete the last one on a win?  Depends, I guess, if reaching new highs, or new lows, or if playing an incomfortable amount of nrs.  I like keeping the last nr in a pair when playing below 22nrs.  I'd never keep one  if playing 24 or more nrs, especially early in a recovery.  (My feeling is the sweet spot is from 18 to 24 nrs using the grind).

Bref, 51% switch is already noteworthy.

[Proofreaders2000]

Thanks for the input Bigbroben.

Remember a bettor usually has 15 to 20 seconds
to place a bet, so execution should be fairly simple.

[Proofreaders2000]

Here's an idea

***Red or Black singles***

Bet the last four Red singles outcomes and one number numerically
higher (if the last decision is Red) and vice versa if the last decision is Black.

Example: 20,2,12,31,5,14,36,12 (newest spin-value)

Bet 12,13:  36,0:  14,15:  5,6 once:    1.) 13(x)-8

Bet 13,14:  31,32:  2,3:  20,21 once....

[Bigbroben]

Here's an idea

***Red or Black singles***

Bet the last four Red singles outcomes and one number numerically
higher (if the last decision is Red) and vice versa if the last decision is Black.

Example: 20,2,12,31,5,14,36,12 (newest spin-value)

Bet 12,13:  36,0:  14,15:  5,6 once:    1.) 13(x)-8

Bet 13,14:  31,32:  2,3:  20,21 once....

Surprising start...

[Bigbroben]

Here's the file I created to calculate the Switch/Run sequences.

Reduced it to 500 spins so the files gets smaller than 1.5Mb.
If anyone sees an error that could radically change results, please share!

P.S.: find Waldo!

[Herby]

P.S.: find Waldo!

Gotcha! 

[Bigbroben]

Fun isn't it?

[Proofreaders2000]

Surprising start...

Seek and you shall find 

I'm hoping the Red-Black phenomena holds

Thanks for testing Bigbroben 

[Bigbroben]

These are the only spins I tested though.

[Bigbroben]

Here's the file I created to calculate the Switch/Run sequences.


If anyone sees an error that could radically change results, please share!

Found it!

I was running tests win 10k spins per shot and saw the switch average went from 51% to 50.15.  Then ran 37 spin tests and the switch average was 77%.
Thought: something wrong.

Indeed, if only the first switch per pair is taken into account, switches and run end up the same, in the long run.  Since some pairs showed more switching than others, more 1s appeared, creating an unbalance in the calculations, which is diminished with ever longer spin tests.

So, yeah, 50/50, as expected.

Let's move on.

[Proofreaders2000]

Alright then here's another idea

Bankroll suggestion: 216 units

Track until you have seven consecutive unique singles.

Bet that spin-value and the number numerically higher once.

Repeat betting the last decision outcome and the
higher number (always two numbers in play) until in profit.

Example: 21,0,13,9,18,3,14 (newest outcome)

Bet 14,15 once:    1.) 3(x)

Bet 3,4 once:        2.) 0(x)

Bet 0,1 once....

[Proofreaders2000]

One more idea

Two Blacks,Two Reds Plus One

Procedure: Note the newest two Red and Black outcomes.

Bet those four and one number numerically higher once.

Example:  14,31,2,31,21 (newest spin-value)

Bet 14,15, 21,22 & 2,3, 31,32 once:    1.) 17(x)

Bet 14,15, 21,22 & 31,32, 17,18 once....

Bankroll suggestion: 192 total units

[Proofreaders2000]

Some time to brainstorm, so here goes 
==============================
Bankroll suggestion: 210 total units

Procedure: Track five consecutive unique singles (qualifier)

Flat-bet those five once.  If miss

Bet the six consecutive unique singles.  If miss

Bet the seven consecutive uniques...

If nine unique singles miss, restart tracking five new unique singles.

Stop when in profit.

[Proofreaders2000]

Time for a new idea so here goes:
==============================
Bankroll suggestion: 180 units total

Procedure: Note the newest three unique singles outcomes.

Place *two* chips on each unique and one chip on
the number numerically higher (nine chips in play).

Repeat steps with the newest outcomes until in profit.

Example: 21,36,9 (newest outcome)

Bet #21 (two chips), #22:  #36 (two chips), #0:  #9 (two chips), #10 once:  1.) 13(x)-9

Bet #36 (two chips), #0:  #9 (two chips), #10: 13 (two chips), #14 once...

[Proofreaders2000]

Alright, a different approach:
==============================
Look at the marquee.  Which singles have repeated in the last 12 spins?

Bet those singles and the number numerically higher continuously.

As more repeats show within 12 spins bet those also with its compliment
(Max eight numbers in play).  Stop when in profit.