Vaddis Holy Grail

[2BobBet]

Didn't quite understand the difference here between the prior method. Would appreciate more details so i might be able to test this myself.

;

I too want to test this too can you do an example please

[Richard Meisel]

I noticed someone posted that out of 42 spins, 66.6 per cent would be doubles. Someone else said that out of 37 spins there would be 12 to 14 doubles. Well, using 42 spins the total permutations would be 37 spins to the 42 power, which is 7.31 to 10 to the 65th. A tremendous high number, but proving mathematically that getting, for instance, 42 reds in a row or 42 number 3's in a row, or any 37 numbers in a row, are all mathematically even in the odds. So I believe my best chance of winning is betting a progression on an even bet. Though this loses in the long run, in the short run I can win around 80 per cent of the time.

[Kav]

I'm trying to contact ayk, but he doesn't seem to visit the forum anymore.
Can anyone help me contact him?
Please message me if you have his email, thank you.

[huskerdu]

I noticed someone posted that out of 42 spins, 66.6 per cent would be doubles. Someone else said that out of 37 spins there would be 12 to 14 doubles. Well, using 42 spins the total permutations would be 37 spins to the 42 power, which is 7.31 to 10 to the 65th. A tremendous high number, but proving mathematically that getting, for instance, 42 reds in a row or 42 number 3's in a row, or any 37 numbers in a row, are all mathematically even in the odds. So I believe my best chance of winning is betting a progression on an even bet. Though this loses in the long run, in the short run I can win around 80 per cent of the time.

I have been playing a long time repeaters and i still play.
I will give you my long experiance on repeaters.
It is right that in 37 spins there are on average 24 unique and 13 double numbers.
In details :
unique
numbers    probability
17         0.05%
18        0.28%
19        1.17%
20        3.60%
21        8.39%
22        14.84%
23        19.93%
24        20.47%
25        15.92%
26        9.41%
27        4.16%
28        1.36%
29        0.33%
30        0.05%

My method of playing is waiting for many unique numbers to appear e.g. 18 unique out of 20 spins
So, based on the average I expect during the 17 spins 6 unique and 11 repeats, which means if i play the numbers that they have already hit,at the next 17 spins Il have 11 wins and 6 loses.
In most of cases I win even if there are 25 or 26 uniques in 37 spins with a very soft progression.
But I have faced situations with 28 and 29 unique numbers.
So if i have in 20 spins 18 uniques, and if there will be a  situation of 29 uniques in 37 spins appear, on the next 17 spins , i will have 11 uniques  and 6 repeats. Which means I will have 11 loses and 6 wins. Keep in mind that after 24 number betting we don't have an E/C chances because we bet on 24 or 25 or 26 numbers to win 1/3 of our betting. And if we reach betting 27-29 numbers we need a very agressive progression which we cannot afford.
So far i have 90% winning sessions
But when I face too many unique numbers at least half of my winnings are gone

[Clf7]

I'm trying to contact ayk, but he doesn't seem to visit the forum anymore.
Can anyone help me contact him?
Please message me if you have his email, thank you.

Kav do you need a coder for rx? I sent you a pm

[Azim]

I have been playing a long time repeaters and i still play.
I will give you my long experiance on repeaters.
It is right that in 37 spins there are on average 24 unique and 13 double numbers.
In details :
unique
numbers    probability
17         0.05%
18        0.28%
19        1.17%
20        3.60%
21        8.39%
22        14.84%
23        19.93%
24        20.47%
25        15.92%
26        9.41%
27        4.16%
28        1.36%
29        0.33%
30        0.05%

My method of playing is waiting for many unique numbers to appear e.g. 18 unique out of 20 spins
So, based on the average I expect during the 17 spins 6 unique and 11 repeats, which means if i play the numbers that they have already hit,at the next 17 spins Il have 11 wins and 6 loses.
In most of cases I win even if there are 25 or 26 uniques in 37 spins with a very soft progression.
But I have faced situations with 28 and 29 unique numbers.
So if i have in 20 spins 18 uniques, and if there will be a  situation of 29 uniques in 37 spins appear, on the next 17 spins , i will have 11 uniques  and 6 repeats. Which means I will have 11 loses and 6 wins. Keep in mind that after 24 number betting we don't have an E/C chances because we bet on 24 or 25 or 26 numbers to win 1/3 of our betting. And if we reach betting 27-29 numbers we need a very agressive progression which we cannot afford.
So far i have 90% winning sessions
But when I face too many unique numbers at least half of my winnings are gone

This one is a waste of time..  We have tried this 5-6 years Ago.   This was the theory behind Andruchi system. I am sure somewhere in the Holy Grail by Winkel started bymyself  is his excel file and password provided thanks to Thomas.

Have a look at it.

[d80]

ok

[d80]

This one is a waste of time..  We have tried this 5-6 years Ago.   This was the theory behind Andruchi system. I am sure somewhere in the Holy Grail by Winkel started bymyself  is his excel file and password provided thanks to Thomas.

Have a look at it.

Where is the excel file? i haven't found

[Elite]

I read  vaadi clues  ,,and  what  I understand I did  coded and  tested,,,  but not  worth,,  it's  for  sure  Vaadi  system not  works,,,  vaadi  or  any  his  colleague,  or  now  also  no  one  claims,,  any  system  works,,,  If any  one  have  better  logic,,  I can  code  and test,,,,  in short  time

[Azim]

Where is the excel file? i haven't found

Hello here it is...

link:s://:.rouletteforum.cc/index.php?topic=401.0

[Proofreaders2000]

Check this out:

Procedure: Note the newest outcome.  Bet that number and one number higher.

If those two miss, bet those two again and the new outcome and one number higher.

If those four miss bet those four and the new outcome and one number higher.

If those six miss bet those four and the new outcome and one number higher.

If those eight miss bet the newest four and one number higher on all four.

Continue to bet the newest four and one number higher until in profit.

Bankroll suggestion: 96 total units

[Clf7]

Check this out:

Procedure: Note the newest outcome.  Bet that number and one number higher.

If those two miss, bet those two again and the new outcome and one number higher.

If those four miss bet those four and the new outcome and one number higher.

If those six miss bet those four and the new outcome and one number higher.

If those eight miss bet the newest four and one number higher on all four.

Continue to bet the newest four and one number higher until in profit.

Bankroll suggestion: 96 total units

Did you test this on rx if it is working or only claiming that it is working?

[Proofreaders2000]

Test: BetPhoenix European Wheel-
Saturday, May 16,2020 @ 5:00pm CDT USA

#10 (newest spin-value)

Bet 10, 11:    1.)  24(x)-2

Bet 10, 11, 24, 25:    2.) 27(x)-4

Bet 10, 11, 24, 25, 27, 28:    3.) 15(x)-6

Bet 10, 11, 24, 25, 27, 28, 15, 16:    4.) 3(x)-8

Bet 24, 25, 27, 28, 15, 16, 3, 4:        5.)  32(x)-8

Bet 27, 28, 15, 16, 3, 4, 32, 33:        6.) 8(x)-8

Bet 15, 16, 3, 4, 32, 33, 8, 9:            7.) 28(x)-8

Bet 3, 4, 32, 33, 8, 9, 28, 29:            8.) 11(x)-8

Bet 32, 33, 8, 9, 28, 29, 11, 12:       9.) 9(win)+28

Bet 32, 33, 28, 29, 11, 12, 9, 10:    10.) 12(win)+28
---------------------------------------------------------------------
+4

[Proofreaders2000]

Did you test this on rx if it is working or only claiming that it is working?

This is an educated guess.

[Proofreaders2000]

Test: BetPhoenix American Wheel-
Sunday, May 17,2020 @ 5:38am CDT USA

*Uses the Vaddi paring list and
00, 0 pair when double-zero shows.

#10 (newest outcome)

Bet 10, 11:                                       1.) 8(x)-2

Bet 10, 11, 8, 9:                               2.) 3(x)-4

Bet 10, 11, 8, 9, 3, 4:                       3.) 00(x)-6

Bet 10, 11, 8, 9, 3, 4, 00, 0:             4.) 30(x)-8

Bet 8, 9, 3, 4, 00, 0, 30, 31:             5.) 26(x)-8

Bet 3, 4, 00, 0, 30, 31, 26, 27:         6.) 00(win)+28

Bet 3, 4, 30, 31, 26, 27, 00, 0:         7.) 16(x)-8

Bet 30, 31, 26, 27, 00, 0, 16, 17:     8.) 9(x)-8

Bet 26, 27, 00, 0, 16, 17, 9, 10:       9.) 10(win)+28
-----------------------------------------------------------------------
+12