Random Thoughts

[3Nine]

First spin a 3, then

If 2nd spin is 3 then you would play 1 and 2 to complete a Repeating Dozen Set.(332,331)

If 2nd spin is a 2 then you would play 2 and 3 to complete a Repeating Dozen set.(323, 322)

If 2nd spin is a 1 then you would play 1 and 3 to complete a Repeating Dozen set.(313, 311)

Nick

I just went back and caught that. Thanks for clarifying, Nick!

[atlantis]

113*
333
231
322*
212*
122*
331*
213
323*
133*
131*
221*
132
312
122*
211*
322*
332*
322*
331*
121*
312
333
122*
233*
221*

27 combos
* = combo with one repeat dozen once (18 out of the 27)

Someone show me how you would have played those - thx.

A.

[Nickmsi]

Hi Atlantis . . .

The attached Tracker shows one way to play your numbers.

Each person can use the information in this thread to create their own method of playing.

Cheers

Nick

[3Nine]

Hi Atlantis . . .

The attached Tracker shows one way to play your numbers.

Each person can use the information in this thread to create their own method of playing.

Cheers

Nick

Do you have a sheet for quads?  Thanks!

[Nickmsi]

3Nine

Only have sheets for Van de Waerden and Dozens so far.

Will eventually get lines and quads but won't be for a while.

Cheers

Nick

[3Nine]

3Nine

Only have sheets for Van de Waerden and Dozens so far.

Will eventually get lines and quads but won't be for a while.

Cheers

Nick

Ok, cool. Thanks.  No rush, there are many ways to win.

[Scarface]

Not sure what advantage it is to bet for the previous cycle to repeat.  I understand at least 1 in 4 cycles has to repeat, but if it gives no advantage, then why bet it?

Sample cycles:
132 222 322 121
132 - 3 different dozens
222- 1 dozen
322 - 2 dozen
121 - in this cycle, something has to repeat.  Bet double dozen 12 after the 2 here.  A cycle containing 2 dozens will hit 18 out of 27 times.  So this is a winning bet

Basically, if you see the last 2 cycles are different, and one of them contain 2 dozens, then bet for the 2 dozen to repeat after the second spin of the 3rd cycle

[Scarface]

We know that there are 27 different combinations for dozen cycles.  3 will be 1 dozen.  6 will be 3 dozen.  And 18 will contain 2 dozen. 

I'm wondering what would be the statistics on winning cycles.  Obviously, 2 dozen cycles will win most of the time.  But how can we use this to gain an advantage?  Maybe wait till the first 2 dozen cycle appears, then bet on it repeating? 

[Drazen]

drazen,

i proposed this many times this particular concept and i was only attacked

is that only because RG posted it?

Of course not 

What Priyanka showed with this is not playing concept. It is just starting point for better understanding of it. There are still  few things which must be involved here before we can figure it out.

Priyanka is also not applying heavy progressions like you were, and I think that would be the main objection from what you advocated. Your betselection in particular is not worse then any other with such odds but applying martingale on it is what shouldnt be done.

[atlantis]

We know that there are 27 different combinations for dozen cycles.  3 will be 1 dozen.  6 will be 3 dozen.  And 18 will contain 2 dozen. 

I'm wondering what would be the statistics on winning cycles.  Obviously, 2 dozen cycles will win most of the time.  But how can we use this to gain an advantage?  Maybe wait till the first 2 dozen cycle appears, then bet on it repeating? 

Hi Scarface,
If it such a STABLE bet then maybe can use something like PA's variance principles...  wait until conditions are in our favour over the 27 triplet cycle to capitalise on the 2 doz combos?

A.

[atlantis]

The state of a triplet can be:

same eg. 222 or 111 or 333
repeat eg. 122 or 331 or 121 etc...
different eg. 213 or 312 or 123 etc..

Idea: wait for 2 consecutive lines consisting of of "same" and/or "different" then play for next line to be a "repeat" line but only after the first 2 results.
For example if first 2 results are 1-2 then play d1+d2
For example if first 2 results are 2-2 then play d1+d3
If lose play as above for "repeat" on next line...

113 (repeat)
333 (same)
231 (different)     trigger
322 (repeat)        after the 32 bet d3+d2. result=2.   won+1
212 (repeat)
122 (repeat)
331 (repeat)
213 (different)
323 (repeat)
133 (repeat)
131 (repeat)
221 (repeat)
132 (different)
312 (different)       trigger
122 (repeat)         after the 12 bet d1+d2. result=2.   won+1
211 (repeat)
322 (repeat)
332 (repeat)
322 (repeat)
331 (repeat)
121 (repeat)
312 (different)
333 (same)            trigger
122 (repeat)          after the 12 bet d1+d2. result=2.  won+1
233 (repeat)
221 (repeat)

A.

[3Nine]

The state of a triplet can be:

same eg. 222 or 111 or 333
repeat eg. 122 or 331 or 121 etc...
different eg. 213 or 312 or 123 etc..

Idea: wait for 2 consecutive lines consisting of of "same" and/or "different" then play for next line to be a "repeat" line but only after the first 2 results.
For example if first 2 results are 1-2 then play d1+d2
For example if first 2 results are 2-2 then play d1+d3
If lose play as above for "repeat" on next line...

113 (repeat)
333 (same)
231 (different)     trigger
322 (repeat)        after the 32 bet d3+d2. result=2.   won+1
212 (repeat)
122 (repeat)
331 (repeat)
213 (different)
323 (repeat)
133 (repeat)
131 (repeat)
221 (repeat)
132 (different)
312 (different)       trigger
122 (repeat)         after the 12 bet d1+d2. result=2.   won+1
211 (repeat)
322 (repeat)
332 (repeat)
322 (repeat)
331 (repeat)
121 (repeat)
312 (different)
333 (same)            trigger
122 (repeat)          after the 12 bet d1+d2. result=2.  won+1
233 (repeat)
221 (repeat)

A.

The issue with this, for me, is playing too many numbers. 

[Scarface]

The state of a triplet can be:

same eg. 222 or 111 or 333
repeat eg. 122 or 331 or 121 etc...
different eg. 213 or 312 or 123 etc..

Idea: wait for 2 consecutive lines consisting of of "same" and/or "different" then play for next line to be a "repeat" line but only after the first 2 results.
For example if first 2 results are 1-2 then play d1+d2
For example if first 2 results are 2-2 then play d1+d3
If lose play as above for "repeat" on next line...

113 (repeat)
333 (same)
231 (different)     trigger
322 (repeat)        after the 32 bet d3+d2. result=2.   won+1
212 (repeat)
122 (repeat)
331 (repeat)
213 (different)
323 (repeat)
133 (repeat)
131 (repeat)
221 (repeat)
132 (different)
312 (different)       trigger
122 (repeat)         after the 12 bet d1+d2. result=2.   won+1
211 (repeat)
322 (repeat)
332 (repeat)
322 (repeat)
331 (repeat)
121 (repeat)
312 (different)
333 (same)            trigger
122 (repeat)          after the 12 bet d1+d2. result=2.  won+1
233 (repeat)
221 (repeat)

A.

Sounds good!  Have you tried this bet before?  Just wondering if it would be better to flat bet, or progression.  What if there is a loss on the bet, would you recommend betting again for the repeat?

[atlantis]

Hi Scarface,

Yes - I would play on after a loser.
I would probably use a mild progression +1/-1 eg:
1-1
2-2
3-3
etc...

Also  - just did a quick test and there loads of "repeats" happening - so maybe decide to play also after 2 out of 3 groups as well as 2 consecutive groups of the other types: "same" or "different" eg:

123*
112
333* trigger: 2 out of 3 groups without "repeat" dozen.

Also - did anyone look at columns too?

Other progressions could be used: GLAT for 2doz; some of GLC's progs etc..

However Scarface, you could still play once only and if LOSS then use progression on next time qualifier. I did not try that.

A.

[3Nine]

IMHO, if you need a negative progression you're barking up the wrong tree.