high hit rate plus positive progression

[RouletteGhost]

The problem with a high hit rate bet selection such as 5 lines is on a loss you lose all profits, every win yields 1 unit while every loss loses 5 units. Therefore the win streaks dont compensate

How can we overcome this?

I think a positive progression can overcome

Take a 5 line bet selection

On a win add a unit

The way i see it is 3 wins in a row will be common place on 5 lines

If you add a unit
Spin 1, 1 unit each position- win 1 unit
Spin 2, 2 unit each position- win 2 units
Spin 3, 3 units each position- win 3 units

We are up 6 units

Now we lose, lose 5 units still plus 1

When we lose back to 1 unit

Maybe with a high hit rate high number strategy with a positive progression we have something

No trigger needed. Every spin

Always put a chip on 0. Well because f*** 0

[NextYear]

You may lose 5u in 1st spin, 9u in 2nd spin, 12u in 3rd spin. Also if you add 1 on zero...

[RouletteGhost]

Its roulette. Possible

You mean 5 then 10 then 15 then add 1 for 0

[RouletteGhost]

Point im making is if we can make a 5 line strategy that wins 3 for ever 1 loss with a positive progression then we have a winning system

The expectation is to win over 75 percent of the time covering 5 Lines

Mathematically we will win over 75 percent of the time

On a plus 1 positive progression on a win i think this is good

[NextYear]

First you place 5 u, then you earn 1 and add 4 new units (5+4=9) to place 10 (5x2), then you earn 2 and add new 3 (9+3=12) to place 15 (5x3) units...
Just saying, maybe the idea is good, also?!

I would treat zero as one of 7 losing numbers.

[RouletteGhost]

First you place 5 u, then you earn 1 and add 4 new units (5+4=9) to place 10 (5x2), then you earn 2 and add new 3 (9+3=12) to place 15 (5x3) units...
Just saying, maybe the idea is good, also?!

I would treat zero as one of 7 losing numbers.

On paper the idea is good. Mathematically you should win at least 3 times to 1. On a positive progression it should win

[ddarko]

On paper the idea is good. Mathematically you should win at least 3 times to 1. On a positive progression it should win

If I've got this right, betting 5 lines should mathematically win 5 times out of every 6 spins
(excluding the zero)

[RouletteGhost]

If I've got this right, betting 5 lines should mathematically win 5 times out of every 6 spins
(excluding the zero)

Yes. So with a positive progression on a win only should win consistently

On a positive progression 3 consecutive wins to 1 loss leaves u in positive

Always insurance on 0

[RouletteGhost]

Actually im wrong

If lose at step 4 lose 20 units after winning only 6

Have to re think this

Perhaps a positive progression 1-2 then back to 1

On a win goto 2 units then right back to 1

1 unit each position
If win
2 units each position
Win or lose back to
1 unit each position

Hit and run may be the theme here

[onetaste]

could always do the ol' 3/2...3 units on high or low and 1 unit on 2 DS of your choice.same coverage,less risk,easier to recover.

[RouletteGhost]

could always do the ol' 3/2...3 units on high or low and 1 unit on 2 DS of your choice.same coverage,less risk,easier to recover.

3 on low 2 on 3rd dozen

On a loss

6 on high 4 on 1st dozen
Then pray for 3 conescutive wins to recover

Theres a system for this have to find it

[Proofreaders2000]

Try this: wait for a line to hit three times in six spins.  Bet all lines except that one once.

[6th-sense]

why don,t you do a john legend style matrix 6 wide....put 1st line in..next line start betting against the ds above and bet the rest but place units 1..2..3..4..5..on the rest of the ds.using the matrix results above line in the order they are in to put your units on...same for each line pf matrix...bet against 1st result put units 1..2..3..4..5..in that order on the ds streets in the order above your best flat betting until end of line..ie 5 spins...just an idea never tested it just throwing it out there    so a 15 unit bet...

[RouletteGhost]

Im very familiar with matrixes

Thanks for the idea. Ill try to make something

[RouletteGhost]

testing a 5 wide DS matrix

write results left to right, play vertically

bet that the above DS wont repeat

in laymens terms you are betting that the DS 5 back will not repeat

6 0 2 2 2
0 5 4 1 4
3 6 1 6 1

insurance on 0 so far so good

thanks for the ideas guys

will also test a 6 wide, or 6 back