American 00 wheel spins.

[wiggy]

RG, Here is my tweak to your idea.

These are the first few spins in the American Zumma.

You can see on spin 5 that Column C is the furthest back if you combine both the dozens and columns. So I am taking it that you would bet Column C as the furthest back and Column B as the last one to appear.

Number 6 comes next and so it's a win on the furthest back Column. Like I said, I see this happen a lot. Could be a nice little tweak. I will run a few tests and see how it goes.

cheers

[RouletteGhost]

Thanks. On your screen shot if the top is newest my next bet would be column A and column B

Column a hit most recent and column b hit last

[wiggy]

Thanks RG, I got it! 

The bottom number is the latest in these screenshots.

So on spin 16, Column A is the furthest back out of both the dozens and columns. So it's a bet on Column A and Column C which is the most recent. Another win because number 34 comes out belonging to Column A.

Obviously there is no bet if you get both a Dozen and Column as the equal furthest back.

[RouletteGhost]

Tha ks for the tweak wiggy

Always good to tweak

I just want to make sure the way i had bet isnt misunderstood

If u do understand then i apologize

At the bottom of your chart, A is the last hit
And the sleeper B

So i would bet next A and B

See what i mean by sleeper? B was the least recent column hit

[wiggy]

Finally, you can see how when number 32 appeared on spin 19, that now the bet switched over to the dozens because Dozen 2 is the furthest back between the Dozens and Columns. So it was a bet on Dozen 2 and Dozen 3. Dozen 1 appeared (number 5) still leaving Dozen 2 as the furthest back. So now the new bet is the Dozen 2 and Dozen 1 because Dozen 2 is still the furthest back and Dozen 1 is now the most recent.

cheers

[wiggy]

At the bottom of your chart, A is the last hit
And the sleeper B

So i would bet next A and B

Yes, that's right. All I am really doing with the tweak is waiting for the sleeper to be the longest sleeper between either the dozens and columns. So it's exactly the same except for that.

[RouletteGhost]

Yes, that's right. All I am really doing with the tweak is waiting for the sleeper to be the longest sleeper between either the dozens and columns. So it's exactly the same except for that.

$$$$$

[RouletteGhost]

Playing how i suggest is not for long term play

ND - get in. Get up. Get out

It doesnt change the house edge

It just exploits the rarer event of the 2nd column to show to repeat over and over again. Which it will but we temporarily take advantage of it

Betting the most recent and the sleeper takes advantage of 2 scenarios as they can often streak and the sleeper will eventuallly awake

The 20 unit win last night was simply flawless.

I added it to my arsenal

[wiggy]

Well said RG 

Long term, there are 37/38 numbers on a 0/00 wheel. They will mostly be a sleeping dozen at the end of a 37 spin cycle. This leaves around 25 originals and they will be around 12 repeats consisting of doubles and trebles+. The trick/skill is how you can isolate those 12 repeats without going gung ho because you really need to find a way to win flat betting or as close to it. Anything else related to boom/bust progressions will eventually wipe your BR out. Let's face it, there is no simple way or roulette wouldn't exist. Really just my 2 cents for when you really get down to the nitty gritty of it all.

What this will do is guarantee that you won't bet on any sleepers in the 37 spin cycle and you can then start a fresh cycle from scratch and go again.

cheers

[nottophammer]

Good evening Wiggy, RG
Like the 37 spin cycle bit, LOTT, i think.
Now we see the 24 non hit + the 12 repeat and those who are not turning up to the party.
Me i have 40 spins,why, when the old cave man wanted to count i suppose he'd look at the end of his arms and low and behold he could count to 10.
So 40 spins is good for me, over time i've found mr non hits avg in those 40 spins.

After 24 spins you've 13 left,has the sleeper shown by here? where is the most likely repeat going to be.

[wiggy]

Just to say guys.....my payment got sorted out with CelticCasino. I wouldn't want to put anyone off from playing there. The support were actually pretty good today and helpful. Based on my experiences there over the last several weeks, I would rate it on a par with Dublin.

cheers

[RouletteGhost]

100 spins
betting last column to hit and the sleeper

2 loss in a row happened twice
4 loss in a row happened once

other then that several single losses in between a bunch of win streaks
-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
here is an example (ZUMMA)

oldest spin up top, as we go down those are the newest spins and what I'd bet. by this example it should be easy to understand

column hit / what I'd bet / Win or Lose

C
B
A (bet B and A) WIN
C (bet A and C) WIN
A (bet C and B) LOSE
B (bet A and B) WIN
B (bet B and C) WIN
A (bet B and C) LOSE
C (bet A and C) WIN
A (bet C and B) LOSE
A (bet A and B) WIN
A (bet A and B) WIN
C (bet A and B) LOSE
A (bet C and B) LOSE
A (bet A and B) WIN
A (bet A and B) WIN
C (bet A and B) LOSE
C (bet C and B) WIN
C (bet C and B) WIN
A (bet C and B) LOSE
B (bet A and B) WIN
A (bet B and C) LOSE
A (bet A and C) WIN
A (bet A and C) WIN

[denzie]

Good evening Wiggy, RG
Like the 37 spin cycle bit, LOTT, i think.
Now we see the 24 non hit + the 12 repeat and those who are not turning up to the party.
Me i have 40 spins,why, when the old cave man wanted to count i suppose he'd look at the end of his arms and low and behold he could count to 10.
So 40 spins is good for me, over time i've found mr non hits avg in those 40 spins.

After 24 spins you've 13 left,has the sleeper shown by here? where is the most likely repeat going to be.

Where I can find LOTT?

[wiggy]

Where I can find LOTT?

Denzie, this is it!

In 37 spins...
... approximately 13 (13.4) numbers will have no hit
... approximately 14 (13.8 ) numbers will have one hit
... approximately 10 (9.8 ) numbers will have more than one hit out of which...
... approximately 7 (6.9) will have exactly two hits and...
... approximately 3 (2.7) will have more than two hits.

[wiggy]

Denzie, just to add.

Some people will tell you the LOTT does not work. Others will tell you it's the holy grail like an Italian guy called Ludducci or something along those lines selling expensive systems.

The answer is somewhere in the middle. On its own, I don't suppose it's of much use. As part of a framework, it can help you in making decisions which in my personal experience can help you overcome the house edge on both 0 or 00 wheels. It takes a lot of work.

cheers