KTF

[nottophammer]

Does anyone think flat betting 11th spin only and switching terminals has any merit?

RG i seldom look at links,but in the avg doc betting for the 11th non-hit has hit 1st spin 79 out of 101 games. Would it be better going for the 11th non-hit instead of just spin 11

[RouletteGhost]

RG i seldom look at links,but in the avg doc betting for the 11th non-hit has hit 1st spin 79 out of 101 games. Would it be better going for the 11th non-hit instead of just spin 11

Thanks notto

I will download excel viewer to view

[psimoes]

Notto, your reasoning makes sense. There are always more unique numbers that won´t repeat any sooner. The problem is you´re therefore betting on too many numbers. A loss and it gets difficult to recover.

I explaned how I see this method on post #244 IIRC.

I got the Loothog definition now: when they say the longest gap between two winning numbers is say 14, there were in fact 13 losing numbers between them. They count the second winning number as a gap (confusing). So when they say 22 it´s 21, when they say 10 it´s 9 and so on. Which means the numbers to bet for plus their longest gap must total 37+1.

So 27 + 10 = 37 : still one wheel pocket short.

[psimoes]

Ooops. Got caught by the law of large numbers again. Ran more tests. No longest gap big enough to totalize the 37+1. Sorry friend, this won´t work. It´ll succumb to the house edge. 

[RouletteGhost]

RG i seldom look at links,but in the avg doc betting for the 11th non-hit has hit 1st spin 79 out of 101 games. Would it be better going for the 11th non-hit instead of just spin 11

The one ktf bust you did have, what was different from the others? Besides the repeats. Any red flags to check for?

[psimoes]

@ Nottophammer

Maybe my conclusions were premature. Wait 6 uniques and bet 31 against. Try that. Flat bet.

[tuddilue]

@ Nottophammer

Maybe my conclusions were premature. Wait 6 uniques and bet 31 against. Try that. Flat bet.

@psimoes

One bet and stop or start betting with KTF rules? Just curious..

[psimoes]

This doesn´t foresee what happens if you bet on a rolling basis. There are of course the back to back repeaters. If you´re supposed to win right on the first spin then all the numbers hitting would have to be unique. Need coffee. As I see it, if the simulations for what they´re worth were done right, there should be "one terrible loss"every 100000 spins. But if you stumble on an early repeater, you should recover six spins later.

[psimoes]

@psimoes

One bet and stop or start betting with KTF rules? Just curious..

Bet and stop I´d say. The other KTF rules seem arbitrary IMHO.

[tuddilue]

This doesn´t foresee what happens if you bet on a rolling basis. There are of course the back to back repeaters. If you´re supposed to win right on the first spin then all the numbers hitting would have to be unique. Need coffee. As I see it, if the simulations for what they´re worth were done right, there should be "one terrible loss"every 100000 spins. But if you stumble on an early repeater, you should recover six spins later.

Isn't it recover 5 spins later?
6+7+8+9+10=40
Maybe I also need coffee 

[RouletteGhost]

So your saying wait until theres 6 numbers unique that have NOT repeated. Then bet the remaining numbers. One time. ?

[nottophammer]

 psimoes
Did you look at the attachment in reply 856, know idea where this 6 uniques come from.
Repeats is the other topic

[psimoes]

Isn't it recover 5 spins later?
6+7+8+9+10=40
Maybe I also need coffee 

Yeah something like that LOL.

So your saying wait until theres 6 numbers unique that have NOT repeated. Then bet the remaining numbers. One time. ?

Yep

This is  fascinating. According to the simulations, the longest gap for 35 numbers is 5 exceeding the total of 38 by 2. So, does this mean if you wait for 4 uniques then bet 38 against the last two you´ll actually have an edge over the house in the course of 100000 spins? WOW...

Test ppl, test

Edit - corrected the numbers.

[RouletteGhost]

Yeah something like that LOL.Yep

This is  fascinating. According to the simulations, the longest gap for 35 numbers is 5 exceeding the total of 38 by 2. So, does this mean if you wait for 5 uniques then bet 38 against the last three you´ll actually have an edge over the house in the course of 100000 spins? WOW...

Test ppl, test

If thats the case start another thread

1) that'd be fascinating
2) lets respect ktf

I will test

[psimoes]

Attention, I edited my post: bet wait 4 uniques, bet agains the last 2.


Yeah its at the verge of hijacking the thread. Better start a new one.

@Notto yes I read the attachment. See my reply in post #822. That´s my reasonings.