Randomer Thoughts

[The General]

falkor2k15,

Why do you believe the VDW can work?  What do you believe the edge is?

[falkor2k15]

It seems to work because it's 50/50 like betting R/B normal, but it has a certain stability about it, so I don't think the 50/50 fluctuates in the same way; however, the most important thing is that the 50/50 comprises several different outcomes instead of just 2. I don't yet understand where the edge comes from, but it seems supernatural.

[The General]

I don't see the purpose in it, and it appears that you don't either.

[Priyanka]

General - Thanks for providing something out of the nursery to write my thoughts. (Bayes and others - Let me be very clear, no hints, no puzzles, and above all no claims on HG - just an attempt to see whether there is a way to rewrite the facts and beat the house edge. Any point you think it follows any of these, do nudge me). Any naysayers, welcome as always. The more the critique, the merrier it is.

Lets split down the mathematic of cycles and as dozen seems to be hot and clicking, lets take the dozens.

There are three lengths of dozen cycles possible.

Cycles of length 1 - Very straight forward. The dozen that started the cycle has to finish the cycle. Odds of this happening = 1/3
Cycles of lenght 2 - A little bit more complex. For this to happen the second dozen that appears in the cycle has to be different than the first dozen (2/3 odds) and the third dozen has to be one of the first two (again 2/3 chance). Odds of this happening = 2/3*2/3 = 4/9
Cycles of length 3 - Again, following what we did in cycles of length 2, the second dozen has to be different than the first dozen (2/3). But the third dozen has to be different from first and second. Hence only one dozen is a possibility or 1/3 chance. Odds of this happening = 1/3*2/3 = 2/9

This mathematic equation is fundamental to the cycles and how it is defined. Some who are mathematically inclined might wonder, huh, whats new about it. Nothing new, it is just that some who are not as gifted like you would like to know more. And for me it is a place to note my randomer thoughts.

[Turner]

So....
Cycle 1
11
22
33
= 3
Cycle 2
121
131
122
133
X 3 = 12
Cycle 3
1231
1321
1322
1233
1232
1323
X 3 = 18

Yes?

[Priyanka]

Yes?

Yes.

[falkor2k15]

Understanding cycles alone is not enough though? Where does Non-Random and VdW come into it? The house edge cannot be overcome without those right? None of Priyanka's videos seemed to show VdW?

[Turner]

Understanding cycles alone is not enough though? Where does Non-Random and VdW come into it? The house edge cannot be overcome without those right? None of Priyanka's videos seemed to show VdW?

lol.....kids in the back of the car going to Blackpool

"are we there yet"
"are we there yet"

[falkor2k15]

I got a little demo coming up on how I found some edge... to be posted over in the Random Thoughts topic.

[Tamino]

I got a little demo coming up on how I found some edge... to be posted over in the Random Thoughts topic.
[/


My prayer: Please deliver us from another evil. One is enough.


Amen

[Priyanka]

lol.....kids in the back of the car going to Blackpool

"are we there yet"
"are we there yet"

I thought we are just going for a ride.

[TurboGenius]

Why does everyone ignore or pretend to not notice the 0 or worse, the 0 and 00 ?
This totally changes the math of anything that you calculate.

I always read something has 2/3 chance of showing up - or 1/2 chance of showing up......
The big elephant in the room is the 0 - and no one mentions it.
In posts I often see - "excluding the 0".
Why on earth would you work out a method, do the calculations - and completely ignore the one (or two) numbers
that come along while you're playing and destroy your ideas ?

Cycles of length 1 - Very straight forward. The dozen that started the cycle has to finish the cycle. Odds of this happening = 1/3
Cycles of lenght 2 - A little bit more complex. For this to happen the second dozen that appears in the cycle has to be different than the first dozen (2/3 odds) and the third dozen has to be one of the first two (again 2/3 chance). Odds of this happening = 2/3*2/3 = 4/9
Cycles of length 3 - Again, following what we did in cycles of length 2, the second dozen has to be different than the first dozen (2/3). But the third dozen has to be different from first and second. Hence only one dozen is a possibility or 1/3 chance. Odds of this happening = 1/3*2/3 = 2/9

Now you will have to redo this accounting for the zero (or basically the HOUSE EDGE which is what players are up against).
If we're going to play a fair game against the casino - we can come up with some great ways to do this - as long as the zero (or 00) is ignored..... but that's not reality, this game isn't fair - why do we leave the 0 or 00 out of the math while looking for answers (I say "we", but I don't mean it - I always count the zeros as their own numbers)

[psimoes]

Cycles of length 3 - Again, following what we did in cycles of length 2, the second dozen has to be different than the first dozen (2/3). But the third dozen has to be different from first and second. Hence only one dozen is a possibility or 1/3 chance. Odds of this happening = 1/3*2/3 = 2/9

Cycle 3
1231
1321
1322
1233
1232
1323
X 3 = 18

Yes?

Yes.

Having trouble understanding this. To me the third cycle is still of length two as in the description there is no mention of a forth dozen.
It should instead be:
123
132
X 3 = 6

Sorry, clueless here.

[RouletteGhost]

priyanka thanks for that

someone brought up a good point to me

when someone gets off on upsetting people just ignore them

your thread would not have suffered what had happened had we ignored him, and that would have pissed him off

[RouletteGhost]

General

we are TIED for smites!!!!

YES!

my smite level upsets me

im not THAT bad