Math Question

[Scarface]

After 6 spins with no repeat, what are the odds a repeat will occur in the next 6 spins?

[Herby]

45.5517 %
Greets

[Scarface]

Thanks!

[Herby]

Probability of the first repeat of any shown number (in %)

{{1,2.7027},{2,5.25931},{3,7.46254},{4,9.14329},
{5,10.1935},{6,10.5792},{7,10.341},{8,9.58236},
{9,8.44931},{10,7.10453},{11,5.70282},{12,4.3717},
{13,3.2},{14,2.23535},{15,1.48879},{16,0.944243},
{17,0.569417},{18,0.325898},{19,0.176651},{20,0.0904612},
{21,0.0436414},{22,0.0197706},{23,0.00837944},{24,0.00330845},
{25,0.00121086},{26,0.000408421},{27,0.000126093},{28,0.0000353412},{29,8.90354×10-6},{30,1.99147×10-6},{31,3.89324×10-7},
{32,6.51701×10-8},{33,9.08199×10-9},{34,1.01159×10-9},
{35,8.44331×10-11},{36,4.69435×10-12}}

[Herby]

The values above are for 37 numbers

The diagramm for these values:

[NextYear]

Thanks Herby!

Would you mind explaining this numbers for the "slower" brains?

[Herby]

We look at numbers at a 37 numbers wheel.

First number shows up (doesn't matter which one):
what's the probability for an immediate repeat ?
Lookup in the table above: {1,2.7027}
that means: ~2.7 %

next number, if different from the first:
what's the probability for a repeat of any of the 2 previous different numbers? Lookup in the table above: {2,5.25931}
that means: ~5.3%

and so forth ...

[NextYear]

Understood, thanks!

[Herby]

 the highest probability for the first repeater (of any of the previos 6 different numbers) you find {6,10.5792}

this is only statistics !, don't play this