If you really want to know what the longest run could be on the ECs...

[The General]

People often ask me what the longest streak can be on the red and black or ECs in general.  So I've created a formula that will help all of the system players determine the maximums.  The math involved is very simple and it just requires a pencil and some paper.


1. Simply take the number 2 (as in two chances) and divide by 2 until you reach zero.   
2. Next, once you reach zero, simply count the number of times that you had to divide and this will tell you what the max run can be on either the red or the black. 

Note: In order to find the true max runs you must use a pen and paper because a calculator will round off creating an error in the calculation.  Again, you must keep dividing until you actually reach zero.




Best of luck,

The General   

[The General]

 It will tell you the max losing run length that you should consider, it will give the you highest level of confidence when playing your triggers, and it will help maximize your wins! 

[Turner]

You can use occam's razor to sharpen the pencil

[RouletteGhost]

You can use occam's razor to sharpen the pencil

Just googled and read about it

Lol

Fan. Tast. Ic.

[Turner]

Just googled and read about it

Yep....."Entities should not be multiplied unnecessarily" 

[RouletteGhost]

Yep....."Entities should not be multiplied unnecessarily" 

Indeed

No coorelation to roulette.

Anyone seen 30 reds in a row? Once in a lifetime scenario

His proposal doesn't apply to real world roulette

Trying to make a point i guess

Dividing by 2 will never hit 0. Whats this have to do with roulette

Trolling

Trolls are easy to spot these days

[The General]

If you're someone that believes in triggers, then you need to know that number.  So don't give up so easily!

Just trying to be helpful.

[RouletteGhost]

You give up tooo easily.  I guess you don't want your triggers to work.

Geez, just trying to be helpful.

Hey man

If u enjoy being here then more power to ya

Troll away sir

The way u say trying to be helpful is obviously sarcasm and with the added smiley face? Grown man? A grown man?! Noooooo.

[Turner]

Whats this have to do with roulette

Probability shows there could be 100 reds, but its so high its negligible

I dont look up to see if an asteroid is heading directly for me every time I go out,  but it has a probability.

Most likely same as 100 reds.

Its silly to consider it.

[RouletteGhost]

Probability shows there could be 100 reds, but its so high its negligible

I dont look up to see if am asteroid is heading directly for me every time I go out,  but it has a probability.

Most likely same as 100 reds.

Its silly to consider it.

Exactly.

A solar flare can wipe out the power grid tomorrow.

[Steve]

What actually matters is odds vs payout.

[RouletteGhost]

What actually matters is odds vs payout.

Add a "member repeats this" button

Hehehehehehe

[Steve]

Well I could, but it might overload the server. The same things need to be repeated because very basic things are not being understood, so the same approaches get repeated a billion times.

[The General]

Dividing by 2 will never hit 0.-RouletteGhost

Where's your proof?

[psimoes]

It will never reach zero; you can always cut anything in half, even a half from a half, ad infinitum. But of course given an inifinite number of spins even 1000 reds in a row will occur. If they don´t occur in a 10 million spins test, I´d say that´s because 10 million spins are not "infinite enough"

How about counting the decimal places to determine the longest streak in a given finite number of spins?

Ex: 2÷2÷2÷2÷2÷2÷2÷2÷2=0.0078125.

0.00 would mean 999 or less spins where you could expect a streak of 9 reds.