How to play and win with VdW (from "Random Thoughts")

[winkel]

to wiggy

So you had some good laughs on here? OK! You can leave us alone now till you found something by yourself that fits your requirements. We will then come over and will have our laughs.

[winkel]

Does this rolling method you proposed inside this row of 6 give an edge ?

Is there any particular reason for it to be winning bets itlr ?

I´m not here to find edges (there not such things in a game with negativ odds) I just show ways to bet and win if you also use your brain.

[cht]

What’s the big difference between a Non Random and a Random system?

A Random system is subject to the wild swings of variance.

A Non Random system is more stable and subject to less variance.

I tested3 sessions of 3,000 spin each for both a Random system, FTL (Follow The Last) and a Non Random VDW.  Flat betting graphs attached.

Notice the results for FTL had a high of +34 and a low of -122 (a 156 swing).  It had an overall loss of -121.

The 2nd picture (VDW Stability had a high of 49 and a low of -44 (a swing of 93, notice the symmetry) and ended up +28 units.

Which system would require a lower bankroll?

Which system would be safer to add a progression to?

Which system do you think has a better chance of ending up in profit?

Remember this is only for No Zero or baccarat.  I have not yet finished testing with a SZ table.

Cheers
Nick

Do the total bets 2900 for FTL and 1700 VdW in any way contribute to the difference in swing ?

[winkel]

But to me it seems that even in perfect circumstances the next spin can be anything.

You don´t know this: It is the nature of a random game!

[RouletteGhost]

Ok then there is a piece to this I don't get

[praline]

Did any of you tried to find a relation between Tic-tac-toe game and vdw???

In this game we win if we have three X or O in arithmetic progression. And here comes the most interesting part....
We have "9" cells in this game!

[atlantis]

Did any of you tried to find a relation between Tic-tac-toe game and vdw???

In this game we win if we have three X or O in arithmetic progression. And here comes the most interesting part....
We have "9" cells in this game!

You mean sort of like:

r  r  b
r  r  b
b b r

the diagonal r-r-r wins!

There can be stalemates though!

A.

[stringbeanpc]

I also have alot of respect for winkel. He keeps posting ideas to help us, even though he is frequently attacked by other members. Thank You

MoneyT101, I keep struggling to find the answer.
Perhaps you are using something not yet mentioned in this topic, like the Friend & Strangers Theorem

link:s://en.wikipedia.org/wiki/Theorem_on_friends_and_strangers

[praline]

Yes. the difference is that for example you can't win with 234 or 678 etc..

1. 2. 3
4. 5. 6.
7. 8. 9.


Also it's an extremely easy way to track APs.

[Andre Chass]

I wanna give it a try but I'm trying to figure it out...

[RouletteGhost]

I'm not knocking it

I just don't fully understand it

But it seems it's still a guessing game.

My question is how does this help?

Can someone answer this question without getting all crazy.

[DoctorSudoku]

I'm not knocking it

I just don't fully understand it

But it seems it's still a guessing game.

My question is how does this help?

Can someone answer this question without getting all crazy.

Rich,
From all that I have read and seen so far, it remains essentially a guessing game -- B vs R, etc, etc.

Yes, according to the VDW theorem (as applied to roulette), there should be at least one complete AP in a set of 9 spins. But, frequently, in order to fulfill the above requirement, you will need to bet on both Band R -- because either can complete the AP.

Then what do you do  -- other than taking a guess?

And, yes, you will find people (the usual familiar culprits) throwing out clues and hints (and the accompanying condescending statements), but you won't find any definitive answer as to how to take the guessing element out of the equation.

Why?

Because these individuals don't have the answers themselves. You will just be given the run around (along with gratuitous insults thrown in your direction).

[RouletteGhost]

Ok. Then it's as good as anything.

[RouletteGhost]

so if i understand you correctly then only one of the 2 can have a remaining AP to be sure.....

[DoctorSudoku]

so if i understand you correctly then only one of the 2 can have a remaining AP to be sure.....

Yes, that's when you have a stalemate (a mutual bet) -- either B or R can complete the arithmetic progression.

On other occasions, there is a clear-cut choice -- take for example the following two scenarios:

1. Let's say the first four spins of a set are R R B B  -- then to complete the possible 3 4 5 arithmetic progression at spin no. 5, you have to bet on B.

Here the answer is clear (bet on B), but that does NOT mean the the ball and the wheel are going to cooperate with you. They don't have any obligation to do so ! They can produce an R. You lose!

2. Another example: If you have 4 spins such as  B R B B, then you have two possible APs that can be completed with the next spin. The 1 3 5 and the 3 4 5 -- and both can be completed with B. The choice, again, is clear-cut.

But, again, the ball and the wheel have NO obligation to cooperate with you -- they can produce an R. You lose!

The VDW theorem as applied to roulette is still a 50-50 game. Actually, it is worse -- if you include the 0/00 !