Are Cycles combinations?

[falkor2k15]

We can have true combinations, such as dozens in 3 spins:
111 (1 dozen in 3 spins)
122 (2 dozens in 3 spins)
321 (3 dozens in 3 spins)

But let's say we have Dozen Cycles:
121 (CL2)
11 (CL1)
1321 (CL3)

Are they also combinations? Both example have different stats, and for both the order doesn't matter. If they are not combinations then what are they - In terms of number arrangements?

[Turner]

have you run any stats on the cycles. would you care to share it if you have?

[falkor2k15]

have you run any stats on the cycles. would you care to share it if you have?

redwarf/rrbb was able to calculate some of these stats using tree diagrams:
CL1: 1/3 = 33.333333%
CL2: 2/3 * 2/3 = 4/9 = 44.444444%
CL3: 2/3 * 1/3 = 2/9 = 22.222222%
Defined by same: 17/27 = 62.962962962%
link:s://:.rouletteforum.cc/index.php?topic=15938.msg155266#msg155266

Rounded down:
CL1 = 33%
CL2 = 44%
CL3 = 22%

Who can give me the combinatoric stats for dozens in 3 spins?
111
222
333

123
132
213
231
312
321

121
122
...
...
...

[nottophammer]

thought combination cycles were 3 wheeled

[stringbeanpc]

nottophammer, what do you mean by "3 wheeled" ?

[falkor2k15]

Here is a short example set of dozen cycles:

22
2133
3122
233
322
211
11
11
1232

Ignoring zero for the time being, how might we play in parallel with dozen combinations?

Dozen Cycles + Dozens in 3 spins

Cycle 1: 22
Game 1/Cycle 2: 2.. (last 2 dozens: 22)
Game 2/Cycle 3: 3.. (last 2 dozens: 33)
Game 3/Cycle 4: 2.. (last 2 dozens: 12)
Game 4/Cycle 5: 3.. (last 2 dozens: 33)
Game 5/Cycle 6: 2.. (last 2 dozens: 22)
Game 6/Cycle 7: 1.. (last 2 dozens: 11)
Game 7/Cycle 8: 1.. (last 2 dozens: 11)
Game 8/Cycle 9: 1.. (last 2 dozens: 11)

Would it help if we replaced Dozens in 3 spins with Lines in 3 spins?

How about we play another way with just dozen cycles? Let's play multiple games within a game:

2
2
1
3
3
1
2
2
3
3
2
2
1
1
1
1
2
3
2

Game 1
2 = 2...
2 = 2... + 2...
1 = 21... + 2...
3 = 21... + 23...
3 = 213... + 23...
1 = 213... + 231...
2 = 2132 + 231...

Left CL3 wins!


Game 2
2 = 2...
3 = 2... + 3...
3 = 23... + 3...
2 = 23... + 32...
2 = 232 + 32...

Left CL2 wins!


Game 3
1 = 1...
1 = 1... + 1...
1 = 11 + 1...

Left CL1 wins!


Game 4
1 = 1...
2 = 1... + 2...
3 = 13... + 2...
2 = 13... + 22

Right CL1 wins!