51-step progression for two (2) numbers @ 350 units

[VLS]

 
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   
   

steps #	Nb $ by bet	running lost	profit
1	1	-2	34
2	1	-4	32
3	1	-6	30
4	1	-8	28
5	1	-10	26
6	1	-12	24
7	1	-14	22
8	1	-16	20
9	1	-18	18
10	1	-20	16
11	1	-22	14
12	1	-24	12
13	1	-26	10
14	1	-28	8
15	1	-30	6
16	1	-32	4
17	1	-34	2
18	2	-38	34
19	2	-42	30
20	2	-46	26
21	2	-50	22
22	2	-54	18
23	2	-58	14
24	2	-62	10
25	2	-66	6
26	2	-70	2
27	3	-76	32
28	3	-82	26
29	3	-88	20
30	3	-94	14
31	3	-100	8
32	3	-106	2
33	4	-114	30
34	4	-122	22
35	4	-130	14
36	4	-138	6
37	5	-148	32
38	5	-158	22
39	5	-168	12
40	5	-178	2
41	6	-190	26
42	6	-202	14
43	6	-214	2
44	7	-228	24
45	7	-242	10
46	8	-258	30
47	8	-274	14
48	9	-292	32
49	9	-310	14
50	10	-330	30
51	10	-350	10

Use as you please!

[EvilGenius]

Been playing with a progression like this but letting it stretch up to 170 steps or so playing single numbers.  It failed on me once (Loss of approx.  4000 units).

Even though 51 steps or spins with only 350 units sounds amazing I want to warn those who aren't in to maths and those who try every progression they spot.  On a double-zero wheel your chance to hit is 1 to 19.  Divide 51 with 19 and you get ~2. 68.  This means that the chance of success is about the same as in a 5-step martingale (which is ~2. 38) which in this case would use a progression that looked something like this:

10, 20, 40, 80, 160

When I speak of CoS (chance of success) and say something like 2. 38 (as above) it means that if all numbers always showed up in order you would hit 2. 38 times.

Best Regards
Marcus