Repeats Prog Method

[cht]

so you asking about the probability of 32 uniques in one row?

What is the probability of the 2nd set of >= 16 uniques that happens immediately after the 1st set of >= 16 uniques ?

There are repeats between the 2sets.

[Roulettebeater]

What is the probability of the 2nd >= 16 uniques that happens immediately after the 1st >= 16 uniques ?

sorry but your question doesn't make sense at all, you asking for something that's hard to be measured!
i still believe you want to know the probabilty of 32 uniques in one row.

[cht]

sorry but your question doesn't make sense at all, you asking for something that's hard to be measured!
i still believe you want to know the probabilty of 32 uniques in one row.

Hard to measure may mean the probability that it happens is too low to measure ? 

Anyway, just sharing an idea with Andre that instead of randomly play the 1st 12 unique when you are at the table, play the 12 unique immediately after the 16 unique has happened with a shorter 4steps progression.

[Roulettebeater]

the conclusion:

Max 24 uniques in a row showed with very low (near zero probability).

in fact, this consultion is proved by the so-called "Law of Third", and it says that in average: in 37 or 38 spins, 1/3 of the numbers (roughly 12 numbers) do not appear.

Andre's method (chasing 20 uniques in row) is efficient and can be considered one of the top methods i ever seen.

[Madi]

/quote]

Oh god. I dont think u r new guy in roulette? Or r u??

[Roulettebeater]

[quote author=Roulettebeater link=topic=19861.msg187718#msg1877

Andre's method (chasing 20 uniques in row) is efficient and can be considered one of the top methods i ever seen.


Oh god. I dont think u r new guy in roulette? Or r u??

from the end, say what do you want ?

[Andre Chass]

Hard to measure may mean the probability that it happens is too low to measure ? 

Anyway, just sharing an idea with Andre that instead of randomly play the 1st 12 unique when you are at the table, play the 12 unique immediately after the 16 unique has happened with a shorter 4steps progression.

Hey CHT, what do you mean?

Hey CHT, what do you mean?

Wait 16 unique and start betting on a 4-step progression?

That's too much waiting.

[Andre Chass]

the conclusion:

Max 24 uniques in a row showed with very low (near zero probability).

in fact, this consultion is proved by the so-called "Law of Third", and it says that in average: in 37 or 38 spins, 1/3 of the numbers (roughly 12 numbers) do not appear.

Andre's method (chasing 20 uniques in row) is efficient and can be considered one of the top methods i ever seen.

Great!

Thanks for testing the strategy. How did you do the tests? How many cycles? How many spins?

I'm also doing various tests and playing real money.

[Andre Chass]

I just played for about forty minutes having a profit of $42. Not bad. It went to step 3 in the progression. So far without any loss.

[Ratwood85]

It seems that some people didn't understand how to use the strategy.

As we enter the table we have to wait 12 unique numbers IN A ROW. The method allows only one repeat.

Hi Andre, correct me if i'm wrong, you said that we have to wait 12unique numbers in a row and allows only one repeat, below is the example of spins results :

Example 1 :
31,14,27,0,10,29,31,8,11,24,26,7,4
12unique in 13spins with 31repeated (only one number repeat)

Example 2 :
31,14,27,0,10,29,10,31,8,11,24,24,26,7,0,4.
12unique in 16spins with 31,10,24,0repeat (four numbers repeat)

Which one from the examples that you're gonna play ? Please guide me..

Thanks

[cht]

Hey CHT, what do you mean?

Hey CHT, what do you mean?

Wait 16 unique and start betting on a 4-step progression?

That's too much waiting.

Let me explain.

You have 2 choices -

1. Wait for the formation of a >=16 unique and start betting on a 4-step progression, or

2. Wait for the formation of a >=16 unique, wait again for the formation of a >= 12 unique that follows immediately and   
start betting on a 4-step progression

The purpose is to reduce the progression from 8 to 4 steps.

8 steps progression

12 x 1chip   = Lose 12 chips, total chips loss 12 chips - win 24 chips, odds 1: 1.9166 or 3.468% of 692
13 x 1chip   = Lose 13 chips, total chips loss 25 chips - win 23 chips, odds 1: 1.7692 or 3.323% of 692
14 x 2chip   = Lose 28 chips, total chips loss 53 chips - win 44 chips, odds 1: 1.5714 or 6.358% of 692
15 x 3chip   = Lose 45 chips, total chips loss 98 chips - win 63 chips, odds 1: 1.4000 or 9.104% of 692
16 x 4chip   = Lose 64 chips, total chips loss 162 chips - win 80 chips, odds 1: 1.2500 or 11.560% of 692
17 x 6chip   = Lose 102 chips, total chips loss 264 chips - win 114 chips, odds 1: 1.1176 or 16.473% of 692
18 x 9chip   = Lose 162 chips, total chips loss 426 chips - win 162 chips, odds 1: 1.0000 or 23.410% of 692
19 x 14chip = Lose 266 chips, total chips loss 692 chips - win 238 chips, odds 1: 0.8947 or 34.393% of 692

4 steps progression

12 x 1chip   = Lose 12 chips, total chips loss 12 chips - win 24 chips, odds 1: 1.9166 or 24.489% of 98
13 x 1chip   = Lose 13 chips, total chips loss 25 chips - win 23 chips, odds 1: 1.7692 or 23.469% of 98
14 x 2chip   = Lose 28 chips, total chips loss 53 chips - win 44 chips, odds 1: 1.5714 or 44.897% of 98
15 x 3chip   = Lose 45 chips, total chips loss 98 chips - win 63 chips, odds 1: 1.4000 or 64.285% of 98

Assume your daily br is the total potential loss, for 4 steps progression is 98 chips and for 8 steps progression is 692 chips.

For 8 steps progression, on average you will need to win >= 15 games to achieve 100% of br.
For 4 steps progression, on average you will need to win >= 3-4 games to achieve 100% of br.

The 1st 4 steps of the 8 steps progression is on a higher probability of occurrence and on higher odds.

I have given you the math facts. You make your decision.

To speed up your play, scan multiple tables for the setup.

Good luck.

[Andre Chass]

Hi Andre, correct me if i'm wrong, you said that we have to wait 12unique numbers in a row and allows only one repeat, below is the example of spins results :

Example 1 :
31,14,27,0,10,29,31,8,11,24,26,7,4
12unique in 13spins with 31repeated (only one number repeat)

Example 2 :
31,14,27,0,10,29,10,31,8,11,24,24,26,7,0,4.
12unique in 16spins with 31,10,24,0repeat (four numbers repeat)

Which one from the examples that you're gonna play ? Please guide me..

Thanks

Hi RATWOOD85,

It's a pleasure help you!

You're gonna play example 1.

Never, never play example 2.

[cht]

For online casino, play with autobot.

If you play 8 steps progression, be aware you are open to disconnection.

For b&m casino, there are 20-24 history spins for electronic table games(etg). Rotate your scan over a few nearby etg in your location. Work with partners to increase your scope.

[Ratwood85]

Hi RATWOOD85,

It's a pleasure help you!

You're gonna play example 1.

Never, never play example 2.

Thanks Andre for the fast reply..
When u enter a table, you prefer to start from the beginning to wait for 12unique, why don't you use the history spins of the table before you enter that table to shorten your waiting time ?

[Andre Chass]

why don't you use the history spins of the table before you enter that table to shorten your waiting time ?

I use the history spins.