Repeats Prog Method

[Andre Chass]

So let's get back to the topic and try to improve the strategy.

PS: if you don't like it, get out of here.
If you want to help with new ideas to improve the strategy, YOU ARE WELCOME!

[Andre Chass]

I'm getting many private messages. I thank everyone for the support and I will answer them as soon as I can.

Thank you all

[iggiv]

And hopefully you will cool down as well. Thank you.

[iggiv]

Let's keep the discussion friendly. Please.

I warned some privately.

[Roulettebeater]

Hi Andre, Hi Guys.

I am testing this Method again, the result is awesome... this method seems very successful if the progression can jump to 12 steps.

8 Steps = 113/100k
9 Steps=47/100k
10 Steps=10/100K


I have programmed the testsing logic:

Code Select Expand

AND r13.num <> (r1.num,r2.num,r3.num,r4.num,r5.num,r6.num,r7.num,r8.num,r9.num,r10.num,r11.num,r12.num)
AND r14.num <> (r1.num,r2.num,r3.num,r4.num,r5.num,r6.num,r7.num,r8.num,r9.num,r10.num,r11.num,r12.num,r13.num )
AND r15.num <> (r1.num,r2.num,r3.num,r4.num,r5.num,r6.num,r7.num,r8.num,r9.num,r10.num,r11.num,r12.num,r13.num,r14.num)
AND r16.num <> (r1.num,r2.num,r3.num,r4.num,r5.num,r6.num,r7.num,r8.num,r9.num,r10.num,r11.num,r12.num,r13.num,r14.num,r15.num )
AND r17.num <> (r1.num,r2.num,r3.num,r4.num,r5.num,r6.num,r7.num,r8.num,r9.num,r10.num,r11.num,r12.num,r13.num,r14.num,r15.num,r16.num)
AND r18.num <> (r1.num,r2.num,r3.num,r4.num,r5.num,r6.num,r7.num,r8.num,r9.num,r10.num,r11.num,r12.num,r13.num,r14.num,r15.num,r16.num,r17.num)
AND r19.num <> (r1.num,r2.num,r3.num,r4.num,r5.num,r6.num,r7.num,r8.num,r9.num,r10.num,r11.num,r12.num,r13.num,r14.num,r15.num,r16.num,r17.num,r18.num)
AND r20.num <> (r1.num,r2.num,r3.num,r4.num,r5.num,r6.num,r7.num,r8.num,r9.num,r10.num,r11.num,r12.num,r13.num,r14.num,r15.num,r16.num,r17.num,r18.num,r19.num)
AND r21.num <> (r1.num,r2.num,r3.num,r4.num,r5.num,r6.num,r7.num,r8.num,r9.num,r10.num,r11.num,r12.num,r13.num,r14.num,r15.num,r16.num,r17.num,r18.num,r19.num,r20.num)
AND r22.num <> (r1.num,r2.num,r3.num,r4.num,r5.num,r6.num,r7.num,r8.num,r9.num,r10.num,r11.num,r12.num,r13.num,r14.num,r15.num,r16.num,r17.num,r18.num,r19.num,r20.num,r21.num);



[Andre Chass]

Hi Andre, Hi Guys.

I am testing this Method again, the result is awesome... this method seems very successful if the progression can jump to 12 steps.

8 Steps = 113/100k
9 Steps=47/100k
10 Steps=10/100K

Thank you, RouletteBeater!

I'm trying to figure it out how to play it flatbet or with a mild progression.
I've tested the method playing with 8 numbers too.

PS: If someone here don't like the way I'm trying to play it, please be kind. If you want just give me suggestions without attacking me.

I wish all forum members a nice week!

Peace

[Andre Chass]

Ok, the premise is that we dont need to and we will not win every cycle unless we use an absurdly long progression with the risk of blowing up the bankroll. We all know that in average 24 single number appears in 37 spins. My dilemma is: What is the best way to bet waiting for a repeat? Betting on four? six? or twelve uniques? I also think it's essential to use a smooth progression. But from which moment to use the progression? Im doing a lot of tests based on this method using the RX but I have not come to a conclusion yet.

Some help?

[denzie]

Some help ? Why change your current systemS ? 

[denzie]

Ok, the premise is that we dont need to and we will not win every cycle

This in the only smart thing you ever posted here!

[Andre Chass]

Denzie leave me alone, please.

[winkel]

Ok, the premise is that we dont need to and we will not win every cycle unless we use an absurdly long progression with the risk of blowing up the bankroll. We all know that in average 24 single number appears in 37 spins. My dilemma is: What is the best way to bet waiting for a repeat? Betting on four? six? or twelve uniques? I also think it's essential to use a smooth progression. But from which moment to use the progression? Im doing a lot of tests based on this method using the RX but I have not come to a conclusion yet.

Some help?

There is no conclusion to this.

First mistake: "on average" The average is a lie. it is only right at about 22%.
Second mistake: If you bet any sort of numbers you will always have the same mathematical probability:
4 numbers: 4/37
6 numbers: 6/37
12 numbers: 12/37
and so on.

The best way to have a hit on repeaters is the following:
Watch all tables and croupiers. If the croupier or the table shows repeaters back to back: bet all numbers back to back.

On all other betselections referring to LoTT, the math will catch you.

[ozon]

A few days ago at betselection.cc were free systems.
I played one and to my surprise, after several hundred spins on RNG the result was positive, the whole strategy is intended for a live wheel and it should work on them way  better than  rng.
If I have some time, I will try play   on  live  spins.

The assumptions of this strategy are quite good, we play hot sectors and only 4 numbers.

If the flat results oscillate around zero, it is always possible to think of some good progression.

[Andre Chass]

There is no conclusion to this.

First mistake: "on average" The average is a lie. it is only right at about 22%.
Second mistake: If you bet any sort of numbers you will always have the same mathematical probability:
4 numbers: 4/37
6 numbers: 6/37
12 numbers: 12/37
and so on.

The best way to have a hit on repeaters is the following:
Watch all tables and croupiers. If the croupier or the table shows repeaters back to back: bet all numbers back to back.

On all other betselections referring to LoTT, the math will catch you.

Winkel, and what about TurboGenius statement?
He is wrong?
Thanks in advance!

"Here's a rough example using something everyone knows already - that law of thirds or whatever fancy name it has now (I think everything is packaged in 3 letter catch-phrases now ?).
Spin of cycles of 37 spins over and over and over until your balls hurt.
Tell me how many numbers appear once, twice, three times, not at all - etc.
I don't have to do this, I can tell you it's going to be damn near 24 numbers appearing
and 13 not appearing (on average... and yes it's a little off but I rounded stuff for the sake of the post). You can do this over and over. The total amount of numbers that appear will end up being 24...20...28...20...24...25...25...24...20....19....24 go on until you're tired - you'll end up with an incredible amount of cycles where it's 24.
Now think of the math of the game as it's commonly stated.
Any number has a 1 in 37 chance of appearing during a cycle of spins.
That means that any number on average will show up once per 37 spins.... we can all agree with this right ?
But no.. as you can test and prove to yourself - 24 numbers appear on average every 37 spins, not 37. There never will be 37 possible outcomes... just because there are 37 numbers and 37 spins in a cycle and each spin is independent - there will never be 37 numbers that show once and no repeats.
Now grab the eraser and make it every number has a 1 in 24 chance of appearing ?
You could do this or you could take this info and look into repeaters....
I said it until I'm blue in other posts. A number can't show twice unless it's shown once, it can't show 3 times unless it's shown twice, etc..
And most importantly - you can never lose a single unit on any number that doesn't appear because you never bet on it."

[winkel]

Last time my numbers:

from 1,040,000 37spin cycles
there are only 211,766 cycles with 24 numbers appeared
the LOTT says the correct average is 13 unhit (or14?) 14 once appeared (or 13???) and 10 repeaters.
The LOTT combination appeared only 41,013 times.( about 5-6%)

You have to decide whom you will believe.

[JimmieB]

I still think this is a decent repeater method....

link:s://:.rouletteforum.cc/index.php?topic=15715.0