Repeats Prog Method

[Andre Chass]

Anyway, just sharing an idea with Andre that instead of randomly play the 1st 12 unique when you are at the table, play the 12 unique immediately after the 16 unique has happened with a shorter 4steps progression.

Hey CHT, let's work on your idea?

RouletteBeater, nottophammer, proofreader and everyone who wants to collaborate.

[Proofreaders2000]

Thanks for the invite Andre :d

How about working with six uniques?

It could expand to 12, but if we
could get hits with fewer numbers...

[Roulettebeater]

What's the hell going on here ?
I told you that at max a 24 uniques can appear, so either you get ready for 12 progressions or you wait for 16 or whatever uniques and bet up to the limit (24).

Cht's suggesting to wait for 16 uniques then bet 4 that makes 20.
Isn't going to change anything, is the same as andre's way !!!

[denzie]

24 is NOT the limit. But anyway playing to any limit will get your a$$ kicked in roulette. Its a old known fact.

Seriously guys....if it was that easy...

[cht]

Hey CHT, let's work on your idea?

RouletteBeater, nottophammer, proofreader and everyone who wants to collaborate.

From my small sample test I found there's frequency spike for repeat in the spin after 17 unique and the spin after 19 unique. If this observation can be validated through large sample test then this can be exploited with flat bets at those 2 specific spots.

This explains for my request  for test at each level. This test is tricky in that it gives the result on a rolling basis. This means that there has to be a delimiter set to remove this phenomena for it to be meaningful else it's just a next best guesstimate.

This is as far that I'll go with this approach to play repeaters.

Good luck with your efforts here.

[Andre Chass]

Thanks for the invite Andre :d

How about working with six uniques?

It could expand to 12, but if we
could get hits with fewer numbers...

Ok, we play with six uniques. But what about the progression and stop loss?

Have you tried this way?

[Andre Chass]

What's the hell going on here ?
I told you that at max a 24 uniques can appear, so either you get ready for 12 progressions or you wait for 16 or whatever uniques and bet up to the limit (24).

Cht's suggesting to wait for 16 uniques then bet 4 that makes 20.

PS: If I add a number in each step, I will have to correct the progression.
Isn't going to change anything, is the same as andre's way !!!

I understand you. I'll try to play as the CHT suggested. I'll wait for 16 unique and start betting. But I'll keep the same progression. 1,1,2,3,4,6,9,14. (8 steps). So it go to 24 numbers.
I know a table with a minimum bet of 30 cents. So if it burst, the damage will not be as significant.

Well, I never saw 24 uniques in a row. So I will try it.

PS: If I add a number in each step, I will have to correct the progression.

[Andre Chass]

From my small sample test I found there's frequency spike for repeat in the spin after 17 unique and the spin after 19 unique. If this observation can be validated through large sample test then this can be exploited with flat bets at those 2 specific spots.

CHT, can you explain more about play flatbet in these steps?

[ozon]

One does not reach you.
Such strategies will have to play on the RNG, because it will take a lot of waiting on the live wheel.
Such a strategy for virtual limits  with progression will be immediately killed by the casino software.
Even if it seems unlikely to be probable, software dont giva f ...

[Andre Chass]

One does not reach you.
Such strategies will have to play on the RNG, because it will take a lot of waiting on the live wheel.
Such a strategy for virtual limits  with progression will be immediately killed by the casino software.
Even if it seems unlikely to be probable, software dont giva f ...

This strategy can not be applied to RNG tables.
I'll watch 8 live wheels simultaneously.

[Proofreaders2000]

Ok, we play with six uniques. But what about the progression and stop loss?

Have you tried this way?

Yes, looks good so far

Track until you have six Black or Red uniques (whichever collected first)
bet those six for up to six spins.  Stop on a win or after six consecutive misses.

If all six miss at 1x progression restart steps,
gathering Black and Red uniques at 2x progression...

If win at 2x prog restart at 1x progression.  End when in profit.
Stop if 1x and 2x miss (12 consecutive misses.)

Bankroll: 18 units per session

[Andre Chass]

So good so far!

I played like Cht suggest. I waited for 16 unique with 1 repeat max.
Then I betted the 12 unique.

Max progression went to 5 steps 1,1,2,3,4 (only one cycle). Table with minimum bet of $1

8 cycles, $168 of profit.

[Roulettebeater]

So good so far!

I played like Cht suggest. I waited for 16 unique with 1 repeat max.
Then I betted the 12 unique.

Max progression went to 5 steps 1,1,2,3,4 (only one cycle). Table with minimum bet of $1

8 cycles, $168 of profit.

If I remember well, this is not what cht suggested, he asked us to wait for 16 uniques and bet only 4 steps progression, your test scenario proved that you went over 4 steps !!!!

[Andre Chass]

If I remember well, this is not what cht suggested, he asked us to wait for 16 uniques and bet only 4 steps progression, your test scenario proved that you went over 4 steps !!!!

Yes you right! He suggested wait for 16 unique and a ONLY 4 step progression.

I was ready to use a 10 step progression but it wasn't necessary. It went to 5.

I liked this method and will continue betting using it.

[Andre Chass]

Theres something in this strategy that I have to solve. A few minutes ago I was playing using the strategy when I realized that even using an autoclicker it's very difficult to use the progression on live wheels. The tables allow only 20 seconds to place the bets. The progression 1,1,2,3,4,6,9,14 is very difficult to use. I can use the progression up to 6 chips per number using the autoclicker. From that point the autoclicker can't be quick enough to place the bets.
Place 14 chips on 20 numbers is impossible even using the autoclicker.
So the max progression has to be 6 steps.
1,1,2,3,4,6... x9,14x