Looking for new perspectives on how to play - 4 repeats

[Colbster]

This concept has already been discussed from various angles but I think that I have one of the more sound approaches to applying it but remain unsure how to actually PLAY it.  I'm looking for ideas on staking, progressions, betting, etc to make it more manageable.

In 36 spins, there will be a minimum of 4 repeats, meaning that there will be at least 1 dozen (column) that has 2 repeats over the course of the cycle. 

My answer is very simple to that - track all numbers that hit until there is a repeat.  Whatever dozen that repeat happens to fall in becomes "active" because you can only get a second repeat after gaining a first repeat.  At this point, all numbers that have fallen in this dozen will be played until there is a winner.  Each dozen is activated and gets covered as they have repeats, so there could frequently be 2 or 3 dozens in play covering numbers that have already shown.

The worst-case scenario would be a 1,1,13,13,26,26 scenario where all 3 dozens are activated by early repeats followed by a load of non-repeats, forcing you to cover around 30 numbers as the 4th repeat takes a long time to fall.  You can do the progressions easily enough with a spreadsheet or some modestly simple math but the table limits and B/R that are required become undesirable quickly.

This is the most mathematically confident of a winner I have been but I still cannot figure out what tweaks I need to make it more universally playable.  Ideas?

[6th-sense]

i had this sheet made up years ago based on mr j catch the 8 train based on repeaters ..you can adjust options in the top blue sections hope this can be of use to you...was botted for the excell bot

[ignatus]

Hi Colbster,

Well, the only thing i can think of, is trying to limit your bet, this can be done by only betting numbers within last 2  "active" dozens, for an example. OR limit the bet to only betting Red or Black numbers. And not bet more than 8-10 numbers and using a simple +1u progression until hit, (or with a stoploss)....?

[cht]

Hi colbster,
Great to see you posting again.

Took me awhile to wrap my head around what you posted but I got it now.

Just want to confirm, the worst case scenario is 1,1,13,13,25,25 right ?

I'll try to figure this one out, see if I can come up with something.

[cht]

I made this sheet to give me a visual of the doz/col count.

[cht]

In 36 spins, there will be a minimum of 4 repeats, meaning that there will be at least 1 dozen (column) that has 2 repeats over the course of the cycle.

The premise of the idea is the bolded part. I made a sheet to count specifically that - green for start of doz/col and red for stop for all doz/col. Take the difference from one after the start(green) to the stop(red) for the actual units betted or cost, win(red) is a +36. Looking at the data set not so confident it's a winner bet, takes time to figure out how to optimise the bet because have to look at the nature of the distribution. 

[Colbster]

It will provide a guaranteed hit. The math ensures that, often early in the cycle. As soon as you hit, you can delete the spins up to the first showing of either of the repeats in the winning dozen so none of the dozens have more than 1 repeat. You can immediately continue betting with the new numbers in your new cycle.

The issue is when the winning repeat comes late. I'm looking to minimize the betting problems that this scenario presents.

1 point of clarification: I consider 0 as a normal part of 1st dozen and 00 as a normal part of 3rd dozen.

If you are finding any flaw, it's due to my explanation of the method. The math is flawless, the betting method is not (so far).

[cht]

It will provide a guaranteed hit. The math ensures that, often early in the cycle. As soon as you hit, you can delete the spins up to the first showing of either of the repeats in the winning dozen so none of the dozens have more than 1 repeat. You can immediately continue betting with the new numbers in your new cycle.

The issue is when the winning repeat comes late. I'm looking to minimize the betting problems that this scenario presents.

If you are finding any flaw, it's due to my explanation of the method. The math is flawless, the betting method is not (so far).

There's no contention with the math. It's with the issue right there(bolded). And if the RFH comes in you get 1,1,13,13,25,25.....then back to 1 finally although unthinkable to happen yet possible highlights the extreme end of the issue.

The betting method has to focus on capitalising on the high distribution R2 zone. And that requires specific tests.

[Colbster]

Right. It looks like the tracker is playing the dozen. This plays the individual numbers within the dozen that have already shown once it becomes active. The payout of frequently 1 or 2 spaces covered makes it profitable quickly.

[denzie]

Let me see if i get this right. You wait for a repeat. If it comes you play all the numbers from that dozen that have a hit ?  Lets say # from dozen 1. Now # 13 hits....You now bet all the # from doz 1 and doz 2 with a hit ? Or you bet all the hit # from doz 1 and #13 ?

[cht]

Let me see if i get this right. You wait for a repeat. If it comes you play all the numbers from that dozen that have a hit ?  Lets say # from dozen 1. Now # 13 hits....You now bet all the # from doz 1 and doz 2 with a hit ? Or you bet all the hit # from doz 1 and #13 ?

Nope, not that.

Eg. You wait for the 1st repeat say in doz1, bet all the hit# in doz1, then if say a repeat in doz2, bet all the hit # in doz1 and doz2 .......keep betting until say a second repeat happens in doz1 or doz2, then stop bet cycle ends. There may be cases where all 3doz become active and are betted.

Colbster can confirm if what I describe is correct or not

[Madi]

Will be to many number in that case if i m not wrong?

[Colbster]

CHT has it right. You track all hits but only bet the numbers in a dozen made active by a repeat in that dozen. Madi makes the point that led me to post here again about this. The win comes every time, it's a matter of how to play it.

[Madi]

Bit hard actually to reduce the number. Its very normal to have 13 single with 2 double hit from two dozon giving us a 9-12 number to bet on and big chance to deliver unhit from13- 20. I know detect 1s to 2s is the key. Keep on eye on that double hit number within the dozon. If that double hit number got another single hit from same street bet on that . If the double street got 1 or 2 single only bet that 2. Not more that 2 number.

[Proofreaders2000]

How about a qualifier per dozen before playing it's numbers i.e

All three dozens have a minimum of
four playable numbers before making bets

(this can be optimized by tracking dozens and columns)

As each dozen/column shows bet the respective
numbers until win or a drawdown of -36 units.