Half of the Wheel

[denzie]

Ego... im curious....what did you answer ? Thx

[stringbeanpc]

ego, that is good information, 19 numbers covered with 10 units

The remaining numbers (other half of the wheel) could be covered like this, with 12 units

split 13-14
split 17-18
split 20-21
split 22-25
split 28-29
split 31-34

straight up 2,6,7,9,27,36

or cover the splits, and first dozen and 3rd column

[denzie]

Many ways to bet a half Wheel...the main question is which half. And later which # from that half   

[ego]

Ego... im curious....what did you answer ? Thx

I did not answer anything - i just wanted to show how i play bi-modal selection as even money bets using the number ring layout.
A placement that involve some physics.

ego, that is good information, 19 numbers covered with 10 units

The remaining numbers (other half of the wheel) could be covered like this, with 12 units

split 13-14
split 17-18
split 20-21
split 22-25
split 28-29
split 31-34

straight up 2,6,7,9,27,36

or cover the splits, and first dozen and 3rd column

I like this placement when you play to win two in a row and betting against that the other bi-modal sectors will not reach 3.0 SD.
Is rare for rotor/ball combination hitting one particular half constant and same with bi-modal effect using my selection method.

Cheers

[denzie]

Is rare for rotor/ball combination hitting one particular half constant

Cheers

Not extremely rare....But rare enough to use it imo (i dont mean all the time)

[stringbeanpc]

I like this placement when you play to win two in a row and betting against that the other bi-modal sectors will not reach 3.0 SD.
Is rare for rotor/ball combination hitting one particular half constant and same with bi-modal effect using my selection method.

Please explain in more detail

[Roulettebeater]

The poll's result is still a tie
I am gonna vote with *****

[ego]

I will give you some clear hints so you can go back to the drawing board and come up with something - don't have time to explain how i do things every time i reply.

Singles has the value of 1
Series of two has the value of 0
Series of three has the value of 1

So there is a 50/50 situation between singles and series of three - because each serie of two result in a tie - no win no loss - so you can repeat that bet when you aim to catch series of three or higher - i assume you did no know this.

So now you can for example count how many singles you get before a serie of three or higher hit.
You ignore series of two as you know they break even.

Then you might get results like 3 1 0 4 2 1 0 1 2 8 3
Now is up to you to make up your mind.

For example after you see two results above 3 you might aim to catch result from 0 to 2 that is three attempts.
You might build a progression that has five levels with three attempts to cover a larger spread.

Another way can be waiting for two singles 2 and then bet for three times to avoid result above five several times in a row using five levels with three attempts.
There is no limit to how to make up a trigger against singles versus series of three.

One more complex way to make even money into card conuntint system you would do the following.
Any series higher then three is regression toward the mean.

So each time you get for example 7 singles and one serie of three you write minus seven 7-
This indicate that if you get seven more singles after this sequense you have 3.0 SD with no regression present.
Now after does seven bets you can place seven more bets and then you start the first bet after next serie of three.
If you get a seven minus again 7- then you would be betting against 4.0 SD this almost never happens - same as see 20 red in a row.

Now if you get a 7= that means you get seven equal and that is seven and a serie of four, so you did not gain two in a row and got a tie - break even and can repeat the bet.
Now if you get seven plus 7+ you get seven and a serie of five or higer and won two in a row.
And do you get a minus sign between all does bets you have a serie of three and won two in a row and got some regression.

Here is the match for straight singles versus series of three and a chart for overrpresented and underrepresented events or singles versus series of three.

1. Z-Score 0,02 -  1 singles contra 1 serie of three
2. Z-Score 0,73 -  2 singles contra 1 serie of three
3. Z-Score 1,18 -  3 singles contra 1 serie of three
4. Z-Score 1,53 -  4 singles contra 1 serie of three
5. Z-Score 1,82 -  5 singles contra 1 serie of three
6. Z-Score 2,07 -  6 singles contra 1 serie of three
7. Z-Score 2,30 -  7 singles contra 1 serie of three
8. Z-Score 2,51 -  8 singles contra 1 serie of three
9. Z-Score 2.58    9 singles contra 1 serie of three
10. Z-Score 2,70 - 10 singles contra 1 serie of three
11. Z-Score 2,89 - 11 singles contra 1 serie of three
12. Z-Score 3,06 - 12 singles contra 1 serie of three
13. Z-Score 3,22 - 13 singles contra 1 serie of three
14. Z-Score 3,37 - 14 singles contra 1 serie of three
15. Z-Score 3,52 - 15 singles contra 1 serie of three
16. Z-Score 3,66 - 16 singles contra 1 serie of three
17. Z-Score 3,80 - 17 singles contra 1 serie of three
18. Z-Score 3,93 - 18 singles contra 1 serie of three
19. Z-Score 4,06 - 19 singles contra 1 serie of three
20. Z-Score 4,18 - 20 singles contra 1 serie of three
21. Z-Score 4,30 - 21 singles contra 1 serie of three
22. Z-Score 4,42 - 22 singles contra 1 serie of three
23. Z-Score 4,53 - 23 singles contra 1 serie of three
24. Z-Score 4,64 - 24 singles contra 1 serie of three
25. Z-Score 4,75 - 25 singles contra 1 serie of three
26. Z-Score 4,86 - 26 singles contra 1 serie of three
27. Z-Score 4,96 - 27 singles contra 1 serie of three
28. Z-Score 5,07 - 28 singles contra 1 serie of three
29. Z-Score 5,17 - 29 singles contra 1 serie of three
30. Z-Score 5,26 - 30 singles contra 1 serie of three
31. Z-Score 5,36 - 31 singles contra 1 serie of three
32. Z-Score 5,45 - 32 singles contra 1 serie of three
33. Z-Score 5,55 - 33 singles contra 1 serie of three
34. Z-Score 5,64 - 34 singles contra 1 serie of three
35. Z-Score 5,73 - 35 singles contra 1 serie of three
36. Z-Score 5,82 - 36 singles contra 1 serie of three
37. Z-Score 5,90 - 37 singles contra 1 serie of three
38. Z-Score 5,99 - 38 singles contra 1 serie of three
39. Z-Score 6,07 - 39 singles contra 1 serie of three

[ego]

I will show you a experiment i like - you almost can feel you know when a serie of three or four will hit in the future.
You can use anyting as singles event - sereis by them self and aim for three series in a row or you can use larger series using playing model above.

For example - the experiment - twelve bets

Singles has the value of 1
Series of two has the value of 0
Series of three has the value of 1

AND ...

Series of two has the value of 1
Series of three has the value of 0
Series of four has the value of 1

Now you use a six step progression and play to win two in a row or with other words catch a serie of three.
Series of two break even.
So each time you have a single you bet.

If you lose six bets in a row without winning two in a row catching a serie of three - then you start betting from series of two to catch a serie of four.
Then series of three break even.
So each time you have a serie of two you bet.

Now if you lose six bets again - then you got at least six singles with no higher serie and no series of two with higer series.
The sequence is a clean sequence with no existing regression present and the variance increase in perfect order in a perfect world.

Have fun

[stringbeanpc]

Thank you for the explanation. I will have to study your posts and test/experiment.

[denzie]

Soooo... 4 can. Can the 4 say who they are pls ?

[Taotie]

yeah! and who's the 5 cant's too?

[denzie]

placing bets would be easy. now predicting over 50% guaranteed... unfortunatly I dont have skills yet.

Honest answer pls..

Did you tried for few sessions weekly?

[denzie]

I guess this isnt gonna be going somewhere. Although its probably much closer to that HG we all look for.

[maestro]

I guess this isnt gonna be going somewhere

reason is that no one can do it even people said yes