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Solve this, solve the HG.

Started by daveylibra, May 17, 02:42 PM 2018

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0 Members and 2 Guests are viewing this topic.

Roulettebeater

Quote from: daveylibra on May 23, 10:24 AM 2018
Vladi, if you are still following this...

The equation (DrawDown+1)/(Expected Wins Left) is fine but it does not put Bets Left into the equation.
I'm trying to work out how we can factor this in?


Can you please explain his equation with an example

Base stake is 0,5


Thx
A dollar won is twice as sweet as as a dollar earned

daveylibra

1st bet is 0.5 unit.

Suppose we are confident of winning 18 from 60 EC bets.
drawdown is 0.5, expected wins left = 18.
You can round up the result to nearest integer, .25 or whatever.
Just keep going....

vladir

Quote from: daveylibra on May 23, 10:24 AM 2018
Vladi, if you are still following this...

The equation (DrawDown+1)/(Expected Wins Left) is fine but it does not put Bets Left into the equation.
I'm trying to work out how we can factor this in?

I'm still here.
I have no idea. The equation works fine regardless of the bets left. The problem in playing with it is actually having the wins ... and the table limits.

If you look closely, this is just a form of martingale, but spread over several bets, instead of aiming for 1 win only.
Actually, when the Expected wins left is 1, it becomes pure martingale and so bets can go very high.
"In God we trust; all others must bring data", W. Edwards Deming

Roulettebeater

Quote from: daveylibra on May 23, 10:40 AM 2018
1st bet is 0.5 unit.

Suppose we are confident of winning 18 from 60 EC bets.
drawdown is 0.5, expected wins left = 18.
You can round up the result to nearest integer, .25 or whatever.
Just keep going....

1st   : 0.5. Lost
2nd :  (0.5+1)/18 = 0.08!

I can’t stake 0.08!

The lowest stackable unit is 0.5 ... will it work ?
A dollar won is twice as sweet as as a dollar earned

vladir

Quote from: Roulettebeater on May 23, 10:53 AM 2018
1st   : 0.5. Lost
2nd :  (0.5+1)/18 = 0.08!

I can’t stake 0.08!

The lowest stackable unit is 0.5 ... will it work ?

You must round up to the lowest stackable unit you can play.

In theory it will work, if there are no table limits (because bets can go very high on losing streaks!) and if you are guaranteed the wins.
"In God we trust; all others must bring data", W. Edwards Deming

daveylibra

Yes it will work, but when Expected Wins Left=1 and you don't get the win, bets go high.
Also, as I said, in our example of 18 from 60, well the 60 isn't factored in. We are simply hoping for 60 wins whenever.
I'm trying to find a way of making the maximum bets significant.

Roulettebeater

I didn’t dive in the math of this but

Are you saying that if I am interested in getting 10 wins out of 30 spins then I should divide then by 10?

A dollar won is twice as sweet as as a dollar earned

daveylibra

No, if you want to win back 1 unit, divide by 10, thats your expected wins.
10 wins will give you your 1 unit, and hopefully keep your bets low.

jekhb76

Quote from: daveylibra on May 23, 10:40 AM 2018
1st bet is 0.5 unit.

Suppose we are confident of winning 18 from 60 EC bets.
drawdown is 0.5, expected wins left = 18.
You can round up the result to nearest integer, .25 or whatever.
Just keep going....
You Will Have 18 hits min. Out of  60 spins. I ran over 100.000 spins last week and the lowest hirate i got was 19/60.
The question is, how do we Always End up in profit on spin 60?

jekhb76

Just got back from a few hours at my local casino.
Win goal was +â,¬200,00

Mmmm those damn hotnumbers, maybe Steve was right all along  :lol:
I replayed my session for you all that are still non believers regarding Repeaters sq Hotnumbers.

And that without any progression  O0
mmmm, yeah a real bad betselection indeed.
The guy next to me asked if i could teach him how to play this!  :lol: I said, well I know a few who think i don't have enough experience, so it's better that i won't. Good evening sir, enjoy your stay  :twisted:
And I left with +â,¬204 euro, bet my wife will be angry that i blew all the household money!  :lol: >:D

jekhb76

Bet my teacher would be proud  :smile: Dinner is on me Turbo!
Because i'm one of the few on this board Who actualy knows how to play, and that With No Experience  :lol:

The General

Quote from: jekhb76 on May 24, 12:58 PM 2018
Bet my teacher would be proud  :smile: Dinner is on me Turbo!
Because i'm one of the few on this board Who actualy knows how to play, and that With No Experience  :lol:

Don't forget his timeless words of wisdom!  ::)

"Math beats a math game."

"I can win because I'm guaranteed to lose"

"I can increase accuracy of prediction when spins are completely unpredictable."

"In order for a number to hit twice it first has to hit once."

"Random has limits."

"I win because the wheel is random."
Basic probability and The General are your friend.
(Now hiring minions, apply within.)

Roulettebeater

Quote from: The General on May 24, 01:38 PM 2018
Don't forget his timeless words of wisdom!  ::)

"Math beats a math game."

"I can win because I'm guaranteed to lose"

"I can increase accuracy of prediction when spins are completely unpredictable."

"In order for a number to hit twice it first has to hit once."

"Random has limits."

"I win because the wheel is random."


and the list continues with:

]I win because i am lucky
In order to win you should first find a stupid dealer
always follow your heart but remember to cover the zero
[/b][/size]
:twisted: :twisted: :twisted: :twisted: [/size]
A dollar won is twice as sweet as as a dollar earned

daveylibra

... yes it becomes a martingale when expected wins =1 but what I'm thinking is, break it into "chunks" of 10 or whatever, and reset if we don't get the expected wins.
Put it this way, Jek says its EXTREMELY rare not to get 18 in 60. Let's go for 3 in 10. Yes that can easily fail. But the next round, fail to get 3 in 10 again? Unlikely. 3rd round, if we don't get 3 in 10 that means we have had 2 or less in 10,  3 times.
I reckon we can work with this. Also, I would go for one side of the wheel rather than an EC.

jekhb76

Quote from: daveylibra on May 24, 02:41 PM 2018
... yes it becomes a martingale when expected wins =1 but what I'm thinking is, break it into "chunks" of 10 or whatever, and reset if we don't get the expected wins.
Put it this way, Jek says its EXTREMELY rare not to get 18 in 60. Let's go for 3 in 10. Yes that can easily fail. But the next round, fail to get 3 in 10 again? Unlikely. 3rd round, if we don't get 3 in 10 that means we have had 2 or less in 10,  3 times.
I reckon we can work with this. Also, I would go for one side of the wheel rather than an EC.
That looks like a good plan, to get our wins. We could even use a mild progression with this.
will test.
expected wins in 10 spins is 3.

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