Question on roulette progressive probability

[Roulettebeater]

What’s the probability of 8 misses in a row for a bet on 17 numbers in roulette ?

[Bigbroben]

0,7288%,  or 1/137,2.

[Roulettebeater]

0,7288%,  or 1/137,2.

Can you please write down the equation for it ?

Thx

[Nimo]

Probability odds that it will hit 99.2711701%

=-(((20/37)^8)-1)

[Bigbroben]

Alright Nimo,

your result + my result= 1.
So we're good!

Odds of losing: 19/37.
(19/37)^8=1/137 or 0,7288%

[Bigbroben]

[Roulettebeater]

Alright !
So you would lose one cycle out of 137 rounds.

Now can anybody makes a quick simulation on the profitability of this bet ?

136* 19 - 1*( 1+2+4+8+16+32+64+128)

Like that it will lose but be aware that player can win more than 19 if he progressed the progression

Any idea ?

[Bigbroben]

136* 19 - 1*( 1+2+4+8+16+32+64+128)

Do you really mean this, or should it be:
136*19- 17*(1+2+4+8+16+32+64+128)
?

[Roulettebeater]

Do you really mean this, or should it be:
136*19- 17*(1+2+4+8+16+32+64+128)
?

Yes you have right .

Good obeservation bigroben!

[Bigbroben]

Yes you have right .

Yess......

I did a little table,  it actually shows that in a balanced 137 spins, you'll win 3661u in 136 spins and lose 4335 in 1 spin...



Do you want to proceed?

[Roulettebeater]

Yess......

I did a little table,  it actually shows that in a balanced 137 spins, you'll win 3661u in 136 spins and lose 4335 in 1 spin...



Do you want to proceed?

So it’s headed to the hell ?

[vladir]

So it’s headed to the hell ?

Exactly... the place where all methods go 

[Bigbroben]

So it’s headed to the hell ?

I dunno?
Supposedly if you're using some kind of visual ballistic the accuracy is enhanced...  So if you're good and can bet 17nrs and never lose 8 in row...