Roulette Time Loops: (Percentage 99,99%)

[amk]

If I randomly generate 37 numbers on random.org

and take note of which numbers have repeated 3 times

then go to a casino and the next spin of the wheel I observe I start betting on the numbers which have repeated 3 times on the random.org data stream

will those numbers abide by the below stats.....

in other words why would the random data stream from random.org which i have observed with my eyes thus must be my point of reference and entry point into any new random roulette data stream that i see, be any different because both are just a continuation of my continually perceived roulette data stream

whether on random.org or in any random casino

i would think it didnt matter but if you ask a player at the table, perhaps Turbo, who has been tracking all numbers that have hit 3 times in the last 37 spins before i got there they would have to be different numbers then the ones i have

but both would have to conform to the stats below which show that a number must repeat a 4th time by spin 74

well 99,99% of the time

whats going on here?

any interesting insights out there into this time loop and how to possibly catch a number repeating 4 times 99,99% of the time



STATS:
From 10 million spins, single 0 wheel simulated:

In 37 spins to expect a third hit:
Number of spins: 9999990
Number of cycles of 37 spins: 270270
Cycles with three hits: 265475 / 270270
Percentage: 98%

In 37 spins to expect a fourth hit:
Number of spins: 9999990
Number of cycles of 37 spins: 270270
Cycles with four hits: 134963 / 270270
Percentage: 49%

In 74 spins to expect a fourth hit:
Number of spins: 9999990
Number of cycles of 74 spins: 135135
Cycles with four hits: 135122 / 135135
Percentage: 99,99%

In 74 spins to expect a fifth hit:
Number of spins: 9999990
Number of cycles of 74 spins: 135135
Cycles with five hits: 122565 / 135135
Percentage: 90%

In 111 spins to expect a fifth hit:
Number of spins: 9999990
Number of cycles of 111 spins: 90090
Cycles with five hits: 90090 / 90090
Percentage: 100%

In 111 spins to expect a sixth hit:
Number of spins: 9999990
Number of cycles of 111 spins: 90090
Cycles with six hits: 90090 / 90090
Percentage: 100%

[Rinad]

   hi AMK  , you are the first that I know of  who  are bringing up this "loop time" factor about roulette.

I can tell you that the stats you are showing will always happens once you play that 4th number on a table even if prior you had the repeats from rand.org.
I have recorded a lot of live spins over last years and use a "loop time" into my game playing a single or 3 number system.  and when I analized my stats I discovered that my single number had beaten the odds of hitting once in 38 spins.
that should guide anyone in building a money management system that can sustain 120 spins.
regards

Rinad

[ice789]

[amk]

   hi AMK  , you are the first that I know of  who  are bringing up this "loop time" factor about roulette.

I can tell you that the stats you are showing will always happens once you play that 4th number on a table even if prior you had the repeats from rand.org.
I have recorded a lot of live spins over last years and use a "loop time" into my game playing a single or 3 number system.  and when I analized my stats I discovered that my single number had beaten the odds of hitting once in 38 spins.
that should guide anyone in building a money management system that can sustain 120 spins.
regards

Rinad

Hello Rinad!

Could you show an example of your betting within 120 spins on a single number and your MM

you noticed a possible glitch / betting advantage when you recorded only your live spins on a continual bases?

what kind of time loop do you think you have found?

i see its also your first post ever, welcome!

dont be put off by negativity on the forum though : )

[nichedelico]

Hello, i'm fascinated by this, and i've tried for curiosity, but i'm not a math guy. Every time i tried this, in 74 spin i had the hit, but we have really the 0,01% of probability to non-hit the number? Always? That can be amazing.

[buffalowizard]

How many triples can you get within 74 before a hit? Would you reach table limits with progression?
If not, then players could club together and defeat the casinos with 99.99 chance of wins.

[buffalowizard]

One way would be to find sets of 30-40 spins that have no triples that appear and then devise a MM plan to catch the 4th hit.

[amk]

How many triples can you get within 74 before a hit? Would you reach table limits with progression?
If not, then players could club together and defeat the casinos with 99.99 chance of wins.

B Dub!  (BW)

How can we club together?

[Bigbroben]

How many triples can you get within 74 before a hit?

Most likely 4 or less. Median of 3.


Even less if counting 4-hitters on the first 5-hitter. Around 2.

Results of 4000 runs of 74 spins:


First 3xer comes an average on spin 21.  Max was spin 52.
First 4xer comes on average on spin 37.  Max was spin 85.

[Firefox]

One of the definitions of a random number is:

It is impossible to predict future values based on past or present ones.

If you have datasets which show that the occurence of certain values can be related to previous data such that the occurrence of a value is more likely than calculated by a priori probability calculation, or influenced in some way by the previous data, then that data is not random.

[amk]

One of the definitions of a random number is:

If you have datasets which show that the occurence of certain values can be related to previous data such that the occurrence of a value is more likely than calculated by a priori probability calculation, or influenced in some way by the previous data, then that data is not random.

Is this not the definition of the "average"?

By this I mean, any dataset will have an average and this is by definition predictable

[Bigbroben]

It is also predictable that on average a hit will cost 37 units...

[amk]

It is also predictable that on average a hit will cost 37 units...

Very true Bigbro,

We all like roulette, but when it comes down to it we all know the chance of a method winning 1M spins is basically impossible. That being said on average we will only be able to play max +-100K spins during our time on the live table. All we can do is accumulate several BRs and try to play out those 100K spins with the best methods we can find and invent.

Betting for numbers repeating 3/4/5xs looks like a good choice, part of the time....

[Firefox]

Here's one definition:

link:s://whatis.techtarget.com/definition/random-numbers

There are others, but it's accepted there should be no discernable pattern

The a priori probability of a number occurring in the next 74 spins would be

1 - (36/37)^74 = 0.868

Yet your dataset indicates 0.999 over 10 million spins. That's quite a discrepancy.

Also some of the results seem strange for example the 49% result compared to the others and comoated to a priori calculation.

Is this a RNG generator? Something just seems strange about the data or maybe an error in the algorithm used to check for repeats in the data.

RNG generators have been exploited before but generally checking for cycles over billions of spins not results within a few hundred spins.

Casino wheels are also a different kind of random than RNG. They are capable of infinite repeats unlike most RNG and at the same time subject to cycles caused by human conditions eg Same dealer not varying conditions and favouring certain sector, or temporary physical bias caused by unlevel wheel in conjunction with certain rotor, or certain rotor/stator combination.

[Bigbroben]

The a priori probability of a number occurring in the next 74 spins would be

1 - (36/37)^74 = 0.868
Yet your dataset indicates 0.999 over 10 million spins. That's quite a discrepancy.

Firefox,

it's all good.  the average of numbers out on spins 74 is 32.xx.  32/37= 0.86xxxx which corresponds to the number you mentionned above.
And on 99.9% of times one of them will appear 4 times.  There is no divergence.