Unique Numbers Question

[The General]

Here's a question for the unique number guys...and law of the thirds folks.

On the single zero wheel you've just witnessed 36 unique numbers hit.  The only number that has yet to hit is the number 4, all of the other numbers have already hit.  If the number 4 hits on the next spin, then it means that all of the numbers will have hit exactly once in 37 spins.

The numbers that have already hit: 1,2,3,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,0

The number that has not hit: 4



On the next spin( the 37th spin) is the number 4 more or less likely to hit than say.. the number 5? (Number 5 has already hit once.)
Which number do you feel has a higher probability of hitting on the next spin and why?

[Anastasius]

In the one last individual  spin its 1/37

As a whole the event of the 36 uniques is 1 in however many million and the.completion  of the last number to make 37 adds however many thousand or million to the overall events probability.
Therefore this event will surely happen but it may take many spins . Its not an everyday event like 20 uniques etc

My opinion.

[Firefox]

In the one last individual  spin its 1/37

As a whole the event of the 36 uniques is 1 in however many million and the.completion  of the last number to make 37 adds however many thousand or million to the overall events probability.
Therefore this event will surely happen but it may take many spins . Its not an everyday event like 20 uniques etc

My opinion.

It's a chance of 37! (37^36) = 4.825E-14
(Correct me someone if this is wrong)

But the chance of the last number adding is just 1/37th of that chance above, not 1000"s or millions times less.

[MoneyT101]

Here's a question for the unique number guys...and law of the thirds folks.

On the single zero wheel you've just witnessed 36 unique numbers hit.  The only number that has yet to hit is the number 4, all of the other numbers have already hit.  If the number 4 hits on the next spin, then it means that all of the numbers will have hit exactly once in 37 spins.

The numbers that have already hit: 1,2,3,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,0

The number that has not hit: 4



On the next spin( the 37th spin) is the number 4 more or less likely to hit than say.. the number 5? (Number 5 has already hit once.)
Which number do you feel has a higher probability of hitting on the next spin and why?

This is where you have the confusion...

The chances of the next spin being 4 is 1/37 that is true and this never changes.

But now if I group all the numbers into a set of 37 spins.... the chances for the 4 are still 1/37

BUT the math says that more then 34 uniques doesn’t show up before a repeat.

You can run this a trillion times and you won’t find this event. 

Right now at this point which Math do you believe?  Both math is correct!

[nottophammer]

730 sets of 148 spins.
34 non-hit's have hit in all 730 sets.
367 times all 37 have hit in the 148 spin.

So when will you see all 37 in 37 spins.

[Firefox]

The maths does not show that 34 uniques don't show up before a repeat.

The maths shows that it is very unlikely. But there is still a small finite chance.

[MoneyT101]

The maths does not show that 34 uniques don't show up before a repeat.

The maths shows that it is very unlikely. But there is still a small finite chance.

Ok the chance is so small that if you find a way to win on this event.   When you lose that one time does it really matter?

Theoretically speaking...

If you win 1 unit every 37 spins...

Would it matter if you lose say 100 units if all 37 numbers come out?

If I start with 500 units....

Can I reach 200 unit profit before I lose 100?

[6th-sense]

Ok the chance is so small that if you find a way to win on this event.   When you lose that one time does it really matter?

Theoretically speaking...

If you win 1 unit every 37 spins...

Would it matter if you lose say 100 units if all 37 numbers come out?

If I start with 500 units....

Can I reach 200 unit profit before I lose 100?

Well said touché

[Firefox]

The point is, you can't profit from any of this.

Say you turn up at a table and see 33 uniques.

What do you bet on now? Another unique? A repeater.... if so which one(s).

Those 33 uniques are history, the clock resets every spin. The odds of any number now is still 1/37.

You're deluding yourself you have an advantage thrashing around  with 1000''s of spins of "testing"  and 1000's of pages of spreadsheets.

[MoneyT101]

The point is, you can't profit from any of this.

Say you turn up at a table and see 33 uniques.

What do you bet on now? Another unique? A repeater.... if so which one(s).

Those 33 uniques are history, the clock resets every spin. The odds of any number now is still 1/37.

You're deluding yourself you have an advantage thrashing around  with 1000''s of spins of "testing"  and 1000's of pages of spreadsheets.

No, YOU can’t profit from any of this.

Because you can’t see past the wheel and past the odds of the game.

All the testing and spreadsheets helped see better

[Person S]

But if we expand our boundaries, we will see that these are not blind numbers, but Straights, doubles, dozens, etc ...
We are trying to learn how to play at short distances. Why do we need 14 million spins?

[Firefox]

No, YOU can’t profit from any of this.

Because you can’t see past the wheel and past the odds of the game.

All the testing and spreadsheets helped see better

So, 33 uniques occur. How do you now bet to profit?

I know you won't answer, because you don't have an answer!

[MoneyT101]

So, 33 uniques occur. How do you now bet to profit?

I know you won't answer, because you don't have an answer!

To be honest with you depends how I’m playing.

But I would have won way before 33 uniques and multiple wins atleast a minimum of 2 wins

33 uniques equals

Atleast 10 ec cycles
Atleast 8 dozen cycles
Atleast 4 double streets cycles
Atleast 2 street cycles

When I say atleast it means that’s the minimum. Worst case scenario!  So normally it’s more.

Also my current game play is streets mixed with unique numbers.  So 33 uniques is profitable for me!

The way I would play is to remove a unit off any number that showed up within the street I am playing.

The system profits flatbet over 60 spins.  Then playing uniques compliments and gives it the edge to boost it. 

My street bet wins flatbet the more spins I bet and the unique play gives me the real profit

Two systems at play all based on info I’ve talked about 

[The General]

Here's the problem with many systems and system players.

They tend to look at the past spins to reinforce the gambler's fallacy.

For example, red has just hit 14 times in a row, so therefore black must be destined to hit, because the probability of red hitting again are astronomical.
In reality, the only probability that matters is that of the next spin.
The law of the third and unique number cult think in the same way.  If 34 or 35 unique numbers have hit, then they feel that the probability of another unique number hitting is astronomical.  Consequently they naively believe that they can exploit the past spins by betting on the other 34 or 35 numbers while ignoring the true probability of winning on the next spin.  They naively believe that the rare event probability trumps the probability of the next spin.



The fallacy goes even further.  When looking at the past spins they often say, that they would have one on "that sequence" or that their numbers were hitting big and they'd be winning if they just would have bet on them.    They remember the ways in which they would have won, but completely ignore all of the ways that they would have lost. 

[Anastasius]

Firefox

What is the chance of 37/37 in a row unique. I dont understand the "e" symbol.

Is it less or greater than 1 in a billion