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Cross - reference system

Started by Roulettebeater, May 21, 04:50 AM 2019

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0 Members and 3 Guests are viewing this topic.

Firefox

No its only that your alg was working with no or minimal data in the vid.

So results are more likely random luck than anything. We can't tell.

You don't need millions of spins, but some data on that ball and wheel. Steve could tell you, but it's more like in the hundreds of spins.

You can buy a second hand wheel from ebay for £500 to £1000 from winnings. That's what I did. Cost about £900 as I remember. I won £1000s from biased wheel play  20 years back. More than covered the cost of the wheel.

I've got more than £900s worth of fun from it too.  I'm always spinning it and predicting. Far better than a set of golf clubs or something like that which never gets used! It's still in top condition and I could sell it for £900 tomorrow. They don't depreciate if looked after.

Roulettebeater

Firefox

I understand what you want to say, i am not against your idea ... all I need is data, if you want we can verify the system against your wheel... then you will also know the Algorithm I use in the program...

A dollar won is twice as sweet as as a dollar earned

Steve

If you spin a wheel enough times, you notice all its little predictable quirks. Every wheel is unique.

If you see only a few spins from another wheel, you wont so easily notice its quirks. It doesnt mean they arent there.
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

Firefox

I can take a few hundred spins of data.

You can have release point, spin direction,  fall off number,  result, and wheel speed. 21 mm Teflon ball or 18mm Teflon ball. You can have tilted wheel or as level as I can make it.

Steve can have the same results if he wants. Then you can compare your predictions for say a given release point and wheel speed.

Roulettebeater

Steve
I agree, actually if you know the start and exit point,  half the way is done !

Next is find the scatter, that not difficult.. once you know all these inputs, you can create a small program that simulates the speed of rotor and ball.. the match point is just in the middle !

The estimation for the next spin won’t differ much than previous, I use 25% difference factor, that’s valid Since we playing in feedback mode
A dollar won is twice as sweet as as a dollar earned

Roulettebeater

Quote from: Firefox on May 23, 11:07 AM 2019
I can take a few hundred spins of data.

You can have release point, spin direction,  fall off number,  result, and wheel speed. 21 mm Teflon ball or 18mm Teflon ball. You can have tilted wheel or as level as I can make it.

Steve can have the same results if he wants. Then you can compare your predictions for say a given release point and wheel speed.

That would be great, If you want we can join and make live session .. you , Steve and myself
A dollar won is twice as sweet as as a dollar earned

Steve

There are ways of predicting spins before ball release. It has limitations and doesn't beat most wheels. Still enough to be viable. But If you can code, why not develop a roulette computer? Overall they are far better. Quicker and more accurate.
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

Firefox

Advantage of prediction before ball release as I see it, is you can play online.

Roulettebeater

Firefox

Yes it’s for online, but can also use it in real casino.
A dollar won is twice as sweet as as a dollar earned

Roulettebeater

Firefox

How can I receive the spins sets from
your wheel?
A dollar won is twice as sweet as as a dollar earned

Roulettebeater

Today I tested again, in one session where rotor was traveling quite fast, as well as the dealer was spinning the ball somehow differently, that caused the ball drop to be chaotic, the ball hit very frequently  the horizontal diamond... all these conditions made the wheel a true chaotic system...

I have no idea how one can defeat the wheel under these conditions... it seems impossible !

A dollar won is twice as sweet as as a dollar earned

Steve

The dealer has sweet FA control over which diamond is dominant in the long term. DDs are determined by wheel tilt and ball track imperfections.

A dealer may control release speeds, but take 100 random from one dealer, and 100 random spins from another dealer, and they'll have the same dominant diamonds.

If the dd seemed to change, it could be wheel property changes, or short term variance.
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

Steve

Quote from: Roulettebeater on May 30, 05:55 AM 2019I have no idea how one can defeat the wheel under these conditions... it seems impossible

Remember it doesn't matter what happens lots. What matters is there is an anomaly producing results that are predictable enough.
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

Roulettebeater

Quote from: Steve on May 30, 06:54 AM 2019
The dealer has sweet FA control over which diamond is dominant in the long term. DDs are determined by wheel tilt and ball track imperfections.

A dealer may control release speeds, but take 100 random from one dealer, and 100 random spins from another dealer, and they'll have the same dominant diamonds.

If the dd seemed to change, it could be wheel property changes, or short term variance.

that can be true, but the wheel under these conditions is a proper chaotic system... there is nothing can be done to fine tune the predictions.
the best thing is to not play while these conditions are met.

the conditions are : Very Fast rotor, ball hitting horizontal diamonds.
A dollar won is twice as sweet as as a dollar earned

Roulettebeater

Quote from: Steve on May 30, 06:57 AM 2019
Remember it doesn't matter what happens lots. What matters is there is an anomaly producing results that are predictable enough.

my cross reference system showing solid results under ideal conditions:

1- steady dealer
2- slow to medium fast rotor
3- drop point is smooth (ball hit vertical diamonds, drop point is 90 degree, when ball hits horizontal diamond, it deflects its trajectory and becomes unpredictable)


for the rest of the time, the system isnt efficient, neither any other system!

A dollar won is twice as sweet as as a dollar earned

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