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Started by Anastasius, Jun 10, 10:54 AM 2019

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0 Members and 2 Guests are viewing this topic.

Steve

Quote from: Anastasius on Jun 13, 07:32 AM 2019
Can someone test most amount of spins before 2 numbers hit side by side on wheel?

Most in what amount of spins? To know the average you need lots of sets. But you can calculate that already with basic math. And it wouldn't help anyway.
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
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Roulettephysics.com/roulette-strategy ← Why most systems lose

Steve

Quote from: 6th-sense on Jun 13, 03:26 PM 2019.a certain guaranteed point that a pair would form table side or wheel side to hit within a certain amount of spins..

Rubbish. Nothing is guaranteed. They would be looking only at their sample, forgetting the basic math, and assumimg only what they see is absolute reality.
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

Firefox

Quote from: Anastasius on Jun 13, 07:32 AM 2019
Can someone test most amount of spins before 2 numbers hit side by side on wheel?

Most amount of spins? ... infinity.

The red numbers could keep on hitting forever and no numbers side by side would ever hit.

If you want to stick to the observed universe, I believe there was a run of 27 reds once... or was it 30?

However, non of this is any use at all in improving your prediction of the next number!

Anastasius

Notto what is the graph u posted

Also i mean not side by side but if u bet just the neighbours of each hit

So if 2 red hit next to eachother this would constitute  one neighbour..
I tested got up to 15 numbers  bet so far before hit.
Boom boom sir

ozzi43

Quote from: Anastasius on Jun 14, 12:39 AM 2019
Notto what is the graph u posted

Also i mean not side by side but if u bet just the neighbours of each hit

So if 2 red hit next to eachother this would constitute  one neighbour..
I tested got up to 15 numbers  bet so far before hit.

Firefox

Quote from: Anastasius on Jun 14, 12:39 AM 2019
Notto what is the graph u posted

Also i mean not side by side but if u bet just the neighbours of each hit

So if 2 red hit next to eachother this would constitute  one neighbour..
I tested got up to 15 numbers  bet so far before hit.

Answer is still infinity.

But you are probably in the right ball park, practically speaking that there remains a very small chance a sector remains unhit 15-20 spins.

However, there is zero advantage on bet selection from this.

This method will lose money long term.

Anastasius

In 36 spins the average is 12 singles  and 12  repeats.... so...what if we just play up to 6 repeats....  to account for variance
Boom boom sir

Steve

In 37 spins, number 12 averages 1 hit. Why not just bet on the average... and bet on 0 to account for variance?

You havent been listening.

Are you actually serious about winning, or is it just a hobby?
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

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