Step In To My Game

[MoneyT101]

I have a question for all of you.

If we sit a a roulette table and they add a second ball.  So instead of one ball spinning they have two.

We pick 1 number.  But since we have two chances to pick a win. 

Is it safe to say our chance of winning has increased?

If this was real do you think you can win more?

[luckyfella]

I have a question for all of you.

If we sit a a roulette table and they add a second ball.  So instead of one ball spinning they have two.

We pick 1 number.  But since we have two chances to pick a win. 

Is it safe to say our chance of winning has increased?

If this was real do you think you can win more?

In a roulette game, there is always more than 1 ball spinning.😃

To answer your question, the net positive or negative edge has doubled based on the same number of spins the dealer spin.

[luckyfella]

In a roulette game, there is always more than 1 ball spinning.😃

To answer your question, the net positive or negative edge has doubled based on the same number of spins the dealer spin.

Single spin
+1, or
-1

2 spins
+1+1=+2, or
+1-1=0, or
-1-1=-2

[MoneyT101]

Single spin
+1, or
-1

2 spins
+1+1=+2, or
+1-1=0, or
-1-1=-2

Ok I get what you mean but I said 1 number and two results per spin

So -1 if I lose + 35 if I win but two result to get the win because we have more than 1 ball in play at the same time



Single spin
+35 or
-1

2 spins
+35 +35=+70 or
+35-1=+34 or
-1-1=-2

[boyd30]

What is the advantage knowing when a cycle starts and end?

[boyd30]

So how do you take advantage of it?

[mickavelli]

***If you play cycles perfectly with no house edge you will always break even.

Step 1 - Create a template
Step 2 - Limit your session

Agree.
And I like the way you break it down from a betting point of view aswell

Here's some stats from Priyankas cycles spreadsheet. . .

Just for example playing Double Dozens against the previous defining dozen

5294 total dozens cycles

Cycle length 1 Totals = 1754
So playing 2 dozens against the last Defining dozen we would lose x 2 units 1754 times = Neg -3508

Cycle Length 2 Totals = 2356
Same as Previous = 1185...
Different = 1171
To get to cycle length 2 means we win our first bet avoiding cycle length 1 x 2356 times and lose 2 units 1185 times = -2370
2356 -2370 = -14
But we win on "different" +1171 times so
1171 - 14 = 1157

Cycle length 3 Totals = 1184
Same as Previous = 366
Different = 818
To get to cycle length 3 means we win our first TWO bets avoiding cycle length 1 and cycle length 2 = 1184 X 2 = 2368 and losing the 2 units 366 times = -732
2368 -732 =1636
And winning another 818 units on "different"
1636 + 818 = 2454

So end result is basically break even
-3508 + 1157 + 2454 = 103

[ati]

So how do you take advantage of it?

That's the hard part everyone needs to work out themselves. Telling eveyone how to win consistently would be the end of roulette.

[ati]

What is the advantage knowing when a cycle starts and end?

The advantage is that cycles provide us with reliable constant statistics. There is barely any variance of cycle lengths, so I guess cycles must be the pillars of a system.

[Blueprint]

I have a question for all of you.

If we sit a a roulette table and they add a second ball.  So instead of one ball spinning they have two.

We pick 1 number.  But since we have two chances to pick a win. 

Is it safe to say our chance of winning has increased?

If this was real do you think you can win more?

This game has been around for at least 5 years now.

link:s://wizardofodds.com/games/double-ball-roulette/

[MoneyT101]

Agree.
And I like the way you break it down from a betting point of view aswell

Here's some stats from Priyankas cycles spreadsheet. . .

Just for example playing Double Dozens against the previous defining dozen

5294 total dozens cycles

Cycle length 1 Totals = 1754
So playing 2 dozens against the last Defining dozen we would lose x 2 units 1754 times = Neg -3508

Cycle Length 2 Totals = 2356
Same as Previous = 1185...
Different = 1171
To get to cycle length 2 means we win our first bet avoiding cycle length 1 x 2356 times and lose 2 units 1185 times = -2370
2356 -2370 = -14
But we win on "different" +1171 times so
1171 - 14 = 1157

Cycle length 3 Totals = 1184
Same as Previous = 366
Different = 818
To get to cycle length 3 means we win our first TWO bets avoiding cycle length 1 and cycle length 2 = 1184 X 2 = 2368 and losing the 2 units 366 times = -732
2368 -732 =1636
And winning another 818 units on "different"
1636 + 818 = 2454

So end result is basically break even
-3508 + 1157 + 2454 = 103

Yes betting against cycles will also get you into the break even zone

That’s another reason why cycles are beautiful.  In the long run you technically just lose to the house edge

[MoneyT101]

That's the hard part everyone needs to work out themselves. Telling eveyone how to win consistently would be the end of roulette.

I just told everyone... ppl lazy and they want you to actually go and play for them. 

So I doubt even 95% of everyone reading this will even attempt to investigate

[MoneyT101]

The advantage is that cycles provide us with reliable constant statistics. There is barely any variance of cycle lengths, so I guess cycles must be the pillars of a system.

Thank you, I honestly could not have explained it that simple and short.  I have trouble finding the correct words 🤦‍â™,️

[MoneyT101]

This game has been around for at least 5 years now.

link:s://wizardofodds.com/games/double-ball-roulette/

Clearly not the same hypothetical game I explained.  In the game you posted you get paid 1/17 if ball lands on a straight.  If both land then you get the full payment or more.

In the game I explained you still get 1/35 when either ball lands on a straight

[Blueprint]

Clearly not the same hypothetical game I explained.  In the game you posted you get paid 1/17 if ball lands on a straight.  If both land then you get the full payment or more.

In the game I explained you still get 1/35 when either ball lands on a straight

I didn’t say anything about the odds.  No need to get defensive bc you’re unfamiliar with actual casinos.