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Repeaters roulette systems

Started by Steve, Oct 28, 07:54 PM 2019

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0 Members and 11 Guests are viewing this topic.

Steve

For anyone interested in the truth about roulette repeater systems, see link:s://:.roulettephysics.com/can-repeaters-systems-win-at-roulette/

Repeaters are as old as gambling itself. They dont work.
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

luckyfella

Binomial distribution guarantees that repeaters 100% hit.

The only problem is which pockets repeat and when they repeat.

Solve this 2 related problems and you have a winning mechanical repeaters systems bet.
Goodbye everyone - 20/10/2019

luckyfella

Repeaters mean these pockets hit higher than mean, positive variance.

Sleepers mean these pockets hit lower than mean, negative variance.

That's why I wrote for mechanical repeaters systems bet to work it has to predict variance accurately to generate alpha.

To do this the bet must be placed on the correct pockets and right time that the repeaters hit higher than mean, ie. positive variance.
Goodbye everyone - 20/10/2019

Steve

Quote from: luckyfella on Oct 28, 08:30 PM 2019To do this the bet must be placed on the correct pockets and right time that the repeaters hit higher than mean, ie. positive variance.

What's the "right time"? I tested this a long time ago to exhaustion. So have others.

The previous winning number has no correlation to the future winning numbers, except in specific conditions - none of which are anything discussed in typical repeaters threads.
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

luckyfella

To predict which pocket hit higher than mean at the right time is equivalent to variance prediction.

Variance is liken to luck.

How is it possible to predict luck ?
Impossible !

That's the narrative on forum.

Instead of a serious discussion of what aspects to look at about,
1. right pocket, and
2. right timing.

End of a very predictable negative conversation as usual.

Note to those who seek this solution,

The solution has to be based on MATH.

There is nothing, repeat NOTHING posted on all forums that is close to this math that's required for the solution.
Goodbye everyone - 20/10/2019

Steve

Do you claim to have the solution?
"The only way to beat roulette is by increasing the accuracy of predictions"
Roulettephysics.com ← Professional roulette tips
Roulette-computers.com ← Hidden electronics that predicts the winning number
Roulettephysics.com/roulette-strategy ← Why most systems lose

Elite

Quote from: luckyfella on Oct 28, 08:36 PM 2019
To predict which pocket hit higher than mean at the right time is equivalent to variance prediction.

Variance is liken to luck.

How is it possible to predict luck ?
Impossible !

That's the narrative on forum.

Instead of a serious discussion of what aspects to look at about,
1. right pocket, and
2. right timing.

End of a very predictable negative conversation as usual.

Note to those who seek this solution,

The solution has to be based on MATH.

There is nothing, repeat NOTHING posted on all forums that is close to this math that's required for the solution.
Any clues,,?  Repeaters are balance,, house edge prove mathematically,,  it's not possible  to beat roulette long term , group of numbers or variance can be before repeats or after,long term,,  how can it work,,, 

Elite

All theories, binomial,, maths prove,,, in long term,,, it will loose,,,, in roulette,,,  not know why reading truth, still insist,,  there a mechanical system can be,,,  but tracking that way,,,  can give some hints,,,  but tracking,,, monitoring for small profit cannot lead to success,,,  and will cost player time,,,

luckyfella

Quote from: Elite on Oct 29, 02:16 AM 2019
Any clues,,?  Repeaters are balance,, house edge prove mathematically,,  it's not possible  to beat roulette long term , group of numbers or variance can be before repeats or after,long term,,  how can it work,,,
Quote from: luckyfella on Oct 16, 06:52 PM 2019
For dependent outcome it must have two unconnected points of reference.
Goodbye everyone - 20/10/2019

Joe

Quote from: luckyfella on Oct 28, 08:36 PM 2019Instead of a serious discussion of what aspects to look at about,
1. right pocket, and
2. right timing.

Sounds like VB.  ;)
Logic. It's always in the way.

Elite

Quote from: luckyfella on Oct 29, 03:19 AM 2019

[/quote

For 5 no,  there will be 15 no. To cover suppose and it can span more also,,  risk,,  always there,,  as more numbers to cover,,  profit, loss together and at the end house edge will overcome,,,  only it can survive if luck is there at right time with high value bets,  else it will go up and down,,  how to cope that,,, 

Joe

Quote from: luckyfella on Oct 28, 08:36 PM 2019The solution has to be based on MATH.

You mentioned the binomial distribution, which models roulette wins and losses well and assumes independent outcomes. If outcomes were not independent the binomial model would be a crap model. But for maths to help with right pocket and timing (and I'm assuming you're not talking about AP) it must assume dependent outcomes. A mathematical model which works well and assumes independent outcomes cannot coexist with another which assumes dependent outcomes and also works well.

QuoteEnd of a very predictable negative conversation as usual

Perhaps, but it's also predictable that the conversation will raise contradictions, which means that one of the premises is false. Nobody who advocates systems and makes big claims ever resolves them, so the same old topics come and go endlessly.


Logic. It's always in the way.

Elite

Below extract  for binolial distribution,
how it can usefuln

Let's return to the coin-tossing experiment. The coin was tossed 12 times, so N = 12. A coin has a probability of 0.5 of coming up heads. Therefore, π = 0.5. The mean and variance can therefore be computed as follows:

μ = Nπ = (12)(0.5) = 6
σ2 = Nπ(1-π) = (12)(0.5)(1.0 - 0.5) = 3.0.

luckyfella

Quote from: Joe on Oct 29, 04:36 AM 2019
You mentioned the binomial distribution, which models roulette wins and losses well and assumes independent outcomes. If outcomes were not independent the binomial model would be a crap model. But for maths to help with right pocket and timing (and I'm assuming you're not talking about AP) it must assume dependent outcomes. A mathematical model which works well and assumes independent outcomes cannot coexist with another which assumes dependent outcomes and also works well.

Perhaps, but it's also predictable that the conversation will raise contradictions, which means that one of the premises is false. Nobody who advocates systems and makes big claims ever resolves them, so the same old topics come and go endlessly.
Binomial distribution guarantees repeaters hit 100%.

We know repeaters must hit. The question is which pockets and when the pockets hit.

Spend time figure this out instead of writing posts that cast aspersions of credibility that doesn't help anyone one bit.
Goodbye everyone - 20/10/2019

Joe

You don't need the Binomial to guarantee repeaters; the pigeonhole principle also tells you that.

Yes, we 'just' need to know which pocket and when, LOL! simples.

And the maths can show you the way without assuming dependent trials?
Logic. It's always in the way.

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