La Bouchere based on probability and odds of repeated numbers in 37 spins

[huskerdu]

We know that in 37 spins some numbers will be repeated.
We also know that the propability of unique numbers to appera is as follow:

unique
numbers    probability
17         0.051300%
18        0.282190%
19        1.174500%
20        3.605390%
21        8.384150%
22        14.835930%
23        19.936310%
24        20.475660%
25        15.925890%
26        9.406580%
27        4.159970%
28        1.364840%
29        0.328120%
30        0.054960

We also know that with La Bouchere system we can win a session in which we have half the winning spins  from the losing spins.
Having that in mind we could bet in every spin, the last 18 numbers that have come up,  using La Bouchere.
it is impossible to have double of loses than wins having in mind that is imposible to have double times for new numbers to appear compared with repeating numbers to appear.

[Bigbroben]

Interesting.

Can you expand on this?
Applied MM?

[huskerdu]

When we bet the last 18 numbers (half of the roulette) it is an EC betting. So theoritically we have 50% chances to win.
But from the other 18 numbers that they haven't come yet, we know that some numbers will not come out before many spins.
So it is like we bet 18 numbers against about 10 numbers to come.

[Steeefan2014]

When we bet the last 18 numbers (half of the roulette) it is an EC betting. So theoritically we have 50% chances to win.
But from the other 18 numbers that they haven't come yet, we know that some numbers will not come out before many spins.
So it is like we bet 18 numbers against about 10 numbers to come.

It's not a bad idea, but I still have 2 issues about what you said:

1. I don't think I understand this one: "So it is like we bet 18 numbers against about 10 numbers to come."
2. Considering the fact that on the wheel you have 0 or 00.... it's not really EC.

[huskerdu]

1. When we bet on 18 numbers, theoretically iwe have 50% chances to win (ok, 48,3 because of zero) . But when we bet on the last 18 numbers that they have come up, we don't bet against the other 18 that haven't come up but against less numbers. Because we know that some of them will never come out before 60-50-100 or even more spins.  So we bet 18 numbers against 10-12 numbers. Even with flat betting we can win. But we use Labouchere to come up with quick positive results
2. Betting on half of the numbers (or on red/black, on even/odds or small/large) we use to call it  EC even if it is not exactly the half because of 0 / 00.

2.

[SWEET]

Labouchere needs at least 33.34%hit, to close or win...
Thus, say, in next 20spins,
you need no less than 7hit, in 20spins.
Consider that you need 18units for 18numbers, and if you hit 10losing streak!!!???
Do a test , 20 spins increment, for million real bm spins, and see how the worst hit in 20spins, or 50spins,&100spins.
If you see, there never less than 7/20, then Labouchere is manageable/winner, else the staking will quickly snowball to bust!

[huskerdu]

You will never have more than 10 loses on the next 20 spins because it is Impossible to come up with more than  10 unique numbers

[SWEET]

You will never have more than 10 loses on the next 20 spins because it is Impossible to come up with more than  10 unique numbers

Huskerdu,
with due respect,
The main problem is not it may not lose up to 10spins, for how are we going to bet up to 10lpsses streak...

The real problem, is,
How many hit,
in next 20spins???
Please show example, of 100spins, 500,1000spins, so we can be sure.
if it hit not less than 40%,
then we found hg.
thanks.

[Madi]

I can remember him for his wonderful work on “ modified hp jhonson”. Welcome

[huskerdu]

Thanks MADI

Ok, lets continue.
I have bellow, 450 spins from random.org Timestamp: 2020-04-04 08:55:24 UTC
(read the numbers first at the first column,  then at second column etc)

20   30   27   33   30   20   14   12   18   36   21   11   11   20   9
19   23   23   20   33   23   3   7   16   0   23   31   22   9   34
1   13   31   36   17   35   7   11   29   20   5   23   25   7   6
4   15   26   8   33   25   27   11   19   0   19   7   6   20   4
15   28   26   26   10   19   27   15   26   12   10   22   27   9   36
36   1   0   26   7   11   11   18   9   12   30   11   34   36   5
5   10   7   35   9   9   20   20   33   18   11   15   11   17   18
27   7   27   3   36   2   2   22   14   34   0   26   16   28   31
1   14   28   10   13   1   27   1   15   24   24   4   22   29   30
14   10   31   30   30   20   29   36   8   8   33   34   5   36   36
4   0   23   33   6   6   22   14   28   34   20   34   34   18   10
32   9   27   20   21   12   1   29   4   30   4   26   32   22   26
30   30   30   26   4   19   16   33   7   33   8   34   28   16   8
6   1   9   14   16   18   31   3   28   12   2   26   29   16   14
10   17   13   9   12   21   0   9   13   30   4   17   17   1   35
14   12   5   34   28   18   34   0   32   10   5   3   10   31   12
13   26   10   6   15   20   20   25   18   26   22   25   25   35   35
9   30   34   12   3   1   8   3   1   7   4   28   29   21   4
3   4   23   0   13   22   35   34   0   4   24   36   33   26   9
32   29   28   1   4   10   31   21   20   11   29   13   15   3   25
24   6   3   29   23   9   3   35   4   1   29   28   12   3   19
36   25   29   7   27   10   26   6   7   30   35   36   23   34   36
5   7   29   32   23   14   16   16   25   5   4   32   24   17   4
34   33   16   22   16   18   25   36   2   19   17   9   15   21   26
24   20   34   16   17   12   17   13   8   30   25   21   9   30   31
3   8   9   4   19   28   2   32   35   7   17   34   13   14   22
36   12   2   20   30   0   1   19   34   29   31   22   35   14   32
18   20   18   32   9   6   24   18   15   28   11   31   30   1   15
29   5   6   23   14   28   26   3   17   8   4   13   18   30   26
35   23   25   23   23   24   29   31   16   34   23   1   24   11   25

What I did was to bet the last 18 unique numbers.
When we start we have 21 spins until 18 unique nymber sppear.
Starting from the 22nd spin and betting always the last 18 unique numbers, we have the following results during the next 428 spins:
(W=win, L-lose)

WWLWWWLLLWLWLLLWLLWLLWWLLLWLWLLWLLLWW
LLLWLWWLWWLWWWWLLWLLWWLLWLWWLLLLLLLLLW
LWLLWWWLWWWLLLLLLLLLWWLWWWLWLWWLLWLLW
WLLLLWWWLLWWLWWLWLWLLWLWLLWLLWLLLWWLL
WWWWWLLLWLWLLLWLWLWLWWLLWLWLLWWLWLLWW
LWWLLLWLLWLWLLWLLLLLWLLLLLWLLLWWLWWWWLWW
LLLLLLWWWWLLLWWLLWLLWLLLWWWLWWWLWWLLWW
LLLLLLWLLWWLLWWLLWWWWWLLLLWWLWWLWWWWLW
LLWLWWLWWWLWWLLWLWWWWWLWLLLWWLLLWWWW
LWWWLLWWLWLWWWLLLWWLLLLLWLLLLLWLWLWWL
WWWWWLLWLLWLLLWLWWLLWWWLWWLLWLLWWWL
WLWLLWWWLLWWWWLLLWW

Lets take a look :

Wins: 204
Loses: 224

With La Bouchere it is unbeatable strategy.
Even though if we play flat betting the last 18 numbers, it  will come a moment that we will be with a small win.

PS: A drawback is that there are some series of many loses in a row, (but also there are many series of wins in a row that follow)

[SWEET]

Hi,
this is interesting...
you mean
1)wait for 18 different
numbers appear ( no matter it has few repeating numbers) and then bet?

or
2)wait for 18 different numbers in a row, then bet?
thanks.

[SWEET]

if the WL, alway behave like what you show us, then, Labouchere, start with (0,1) must win everytime the win hit larger  than >33.34%.

Even mild progression 123456.... will win if the result are stable.
please test more real casino data, and longer spins, and see if it really never 10 losses in row, (as I cant do computet program.)

thank you so much!

[huskerdu]

SWEET:
Wait for 18 different numbers appear ( no matter it has few repeating numbers) and then bet. because it is very rare for 18 unique numbers to appear !
Then you start betting.
When the next number is a new number you bet on the last 18 numbers (you don't bet the first number) when at the next spin a new number appears again you bet the last 18 unique numbers (don't bet the forst two numbers)
When a same number appears you win and continue bettibg.
I would be thankful if somebody try to programm it.

[ignatus]

we bet the last 18 numbers

Nice. From my testings now, betting last 18, (with an ordinary Neg. progression) it had about a 90% winrate. WG+2000, SL-2000 

Code Select Expand

System "Last 18"
// © ignatus 2020 ©

method "main"
begin
while starting a new session
begin
   put 0 to Record "Highest Bankroll" Data

   Set List [1,1,1,1,1,1,1,1,2,3,4,6,9,14,21,32,60,120,240,480,960]  to Record "progression" Data
   Set List [1,2,3,4,5,6,7,8,9,10,11,12,13] to Record "Number Bet" Data
end

while on each spin
begin

copy last Number to Record "last1" layout

if flag "betmax" false each
begin

Track last number for 18 spins to
Record "last12" layout

end

if any inside bet won each
begin
       reset all flags false
       clear Record "last12" layout
       set flag "betmax" false
        put 1 on Record "progression" Data Index
        put 1 to Record "Number Bets" Data Index
end


{
If Record "Last12" layout list lost each time
begin
   Put 100% of Record "progression" data to Record "last12" Layout list
end
}










IF Record "last12" layout count >= 17 each
Begin
//add 1 on Record "progression" Data Index
//set flag "bet" true
end

IF total inside bets count >= 17 each
Begin
set flag "betmax" true
end

//add 1 on Record "Number Bet" Data Index

if flag "bet" true each
begin
Put 100% of Record "progression" Data to Record "last12" layout list
end

add 1 on Record "progression" Data Index
Put 100% of Record "progression" Data to Record "last12" layout list



If Record "progression" Data Index >
  Record "progression" Data Count
    Begin
     clear Record "last12" layout
     Put 1 on Record "progression" Data Index
     Put 1 on Record "Numbers Bet" Data
    End



{if total spin count >= 150 each time
begin
stop session
end
}
if total bankroll <= -2000 each time
begin
stop session
end

if total bankroll >= 2000 each time
begin
stop session
end

  end
END

[huskerdu]

Thanks IGNATUS I appreciate this!!!!